I can use pointers, but I am a bit afraid of using them.
If you need a dynamic array, you can't escape pointers. Why are you afraid though? They won't bite (as long as you're careful, that is). There's no built-in dynamic array in C, you'll just have to write one yourself. In C++, you can use the built-in std::vector class. C# and just about every other high-level language also have some similar class that manages dynamic arrays for you.
If you do plan to write your own, here's something to get you started: most dynamic array implementations work by starting off with an array of some (small) default size, then whenever you run out of space when adding a new element, double the size of the array. As you can see in the example below, it's not very difficult at all: (I've omitted safety checks for brevity)
typedef struct {
int *array;
size_t used;
size_t size;
} Array;
void initArray(Array *a, size_t initialSize) {
a->array = malloc(initialSize * sizeof(int));
a->used = 0;
a->size = initialSize;
}
void insertArray(Array *a, int element) {
// a->used is the number of used entries, because a->array[a->used++] updates a->used only *after* the array has been accessed.
// Therefore a->used can go up to a->size
if (a->used == a->size) {
a->size *= 2;
a->array = realloc(a->array, a->size * sizeof(int));
}
a->array[a->used++] = element;
}
void freeArray(Array *a) {
free(a->array);
a->array = NULL;
a->used = a->size = 0;
}
Using it is just as simple:
Array a;
int i;
initArray(&a, 5); // initially 5 elements
for (i = 0; i < 100; i++)
insertArray(&a, i); // automatically resizes as necessary
printf("%d\n", a.array[9]); // print 10th element
printf("%d\n", a.used); // print number of elements
freeArray(&a);
Answer from casablanca on Stack OverflowI can use pointers, but I am a bit afraid of using them.
If you need a dynamic array, you can't escape pointers. Why are you afraid though? They won't bite (as long as you're careful, that is). There's no built-in dynamic array in C, you'll just have to write one yourself. In C++, you can use the built-in std::vector class. C# and just about every other high-level language also have some similar class that manages dynamic arrays for you.
If you do plan to write your own, here's something to get you started: most dynamic array implementations work by starting off with an array of some (small) default size, then whenever you run out of space when adding a new element, double the size of the array. As you can see in the example below, it's not very difficult at all: (I've omitted safety checks for brevity)
typedef struct {
int *array;
size_t used;
size_t size;
} Array;
void initArray(Array *a, size_t initialSize) {
a->array = malloc(initialSize * sizeof(int));
a->used = 0;
a->size = initialSize;
}
void insertArray(Array *a, int element) {
// a->used is the number of used entries, because a->array[a->used++] updates a->used only *after* the array has been accessed.
// Therefore a->used can go up to a->size
if (a->used == a->size) {
a->size *= 2;
a->array = realloc(a->array, a->size * sizeof(int));
}
a->array[a->used++] = element;
}
void freeArray(Array *a) {
free(a->array);
a->array = NULL;
a->used = a->size = 0;
}
Using it is just as simple:
Array a;
int i;
initArray(&a, 5); // initially 5 elements
for (i = 0; i < 100; i++)
insertArray(&a, i); // automatically resizes as necessary
printf("%d\n", a.array[9]); // print 10th element
printf("%d\n", a.used); // print number of elements
freeArray(&a);
One simple solution involves mmap. This is great if you can tolerate a POSIX solution. Just map a whole page and guard against overflows, since realloc would fail for such values anyway. Modern OSes won't commit to the whole lot until you use it, and you can truncate files if you want.
Alternatively, there's realloc. As with everything that seems scarier at first than it was later, the best way to get over the initial fear is to immerse yourself into the discomfort of the unknown! It is at times like that which we learn the most, after all.
Unfortunately, there are limitations. While you're still learning to use a function, you shouldn't assume the role of a teacher, for example. I often read answers from those who seemingly don't know how to use realloc (i.e. the currently accepted answer!) telling others how to use it incorrectly, occasionally under the guise that they've omitted error handling, even though this is a common pitfall which needs mention. Here's an answer explaining how to use realloc correctly. Take note that the answer is storing the return value into a different variable in order to perform error checking.
Every time you call a function, and every time you use an array, you are using a pointer. The conversions are occurring implicitly, which if anything should be even scarier, as it's the things we don't see which often cause the most problems. For example, memory leaks...
Array operators are pointer operators. array[x] is really a shortcut for *(array + x), which can be broken down into: * and (array + x). It's most likely that the * is what confuses you. We can further eliminate the addition from the problem by assuming x to be 0, thus, array[0] becomes *array because adding 0 won't change the value...
... and thus we can see that *array is equivalent to array[0]. You can use one where you want to use the other, and vice versa. Array operators are pointer operators.
malloc, realloc and friends don't invent the concept of a pointer which you've been using all along; they merely use this to implement some other feature, which is a different form of storage duration, most suitable when you desire drastic, dynamic changes in size.
It is a shame that the currently accepted answer also goes against the grain of some other very well-founded advice on StackOverflow, and at the same time, misses an opportunity to introduce a little-known feature which shines for exactly this usecase: flexible array members! That's actually a pretty broken answer... :(
When you define your struct, declare your array at the end of the structure, without any upper bound. For example:
struct int_list {
size_t size;
int value[];
};
This will allow you to unite your array of int into the same allocation as your count, and having them bound like this can be very handy!
sizeof (struct int_list) will act as though value has a size of 0, so it'll tell you the size of the structure with an empty list. You still need to add to the size passed to realloc to specify the size of your list.
Another handy tip is to remember that realloc(NULL, x) is equivalent to malloc(x), and we can use this to simplify our code. For example:
int push_back(struct int_list **fubar, int value) {
size_t x = *fubar ? fubar[0]->size : 0
, y = x + 1;
if ((x & y) == 0) {
void *temp = realloc(*fubar, sizeof **fubar
+ (x + y) * sizeof fubar[0]->value[0]);
if (!temp) { return 1; }
*fubar = temp; // or, if you like, `fubar[0] = temp;`
}
fubar[0]->value[x] = value;
fubar[0]->size = y;
return 0;
}
struct int_list *array = NULL;
The reason I chose to use struct int_list ** as the first argument may not seem immediately obvious, but if you think about the second argument, any changes made to value from within push_back would not be visible to the function we're calling from, right? The same goes for the first argument, and we need to be able to modify our array, not just here but possibly also in any other function/s we pass it to...
array starts off pointing at nothing; it is an empty list. Initialising it is the same as adding to it. For example:
struct int_list *array = NULL;
if (!push_back(&array, 42)) {
// success!
}
P.S. Remember to free(array); when you're done with it!
"Correct" way of doing dynamically allocated multidimensional arrays in C
c - Using Dynamic Memory allocation for arrays - Stack Overflow
Is my understanding of dynamically allocating arrays in C correct?
difference between Dynamic Array VS. Dynamically Allocated Array ?
Videos
There are 3 ways that I know of to dynamically allocate a multidimensional array in C:
1- The malloc -> malloc -> malloc... way
int x = 4, y = 5;
int** arr = malloc(sizeof(*arr) * x);
for (int i = 0; i < x; ++i) {
arr[i] = malloc(sizeof(arr[0]) * y);
}This seems to be the worst method of them all. It's verbose to create and free and generates fragmented memory blocks. Also gets progressively bigger the more dimensions there are.
2- The 1D array with indexing way
int index(int x, int y, int maxX)
{
return y * maxX + x;
}
int main(void)
{
int x = 4, y = 5;
int* arr = malloc(sizeof(*arr) * x * y);
// get element at position (0, 2)
int elem = arr[index(0, 2, x)];
}
This is better but not much. Having to call index every time you access the array is a pain. You would also need to create a index function for each number of dimensions.
2.1- The indexing way with a macro
#define ARR(X, Y) arr[Y * x + X]
int main(void)
{
int x = 4, y = 5;
int* arr = malloc(sizeof(*arr) * x * y);
// get element at position (0, 2)
int elem = ARR(0, 2);
}I guess you could consider this better, but I personally don't really like it. Also has the same problems that number 2 has.
3- The VLA way
int x = 4, y = 5, z = 10, w = 2; int (*arr2D)[y] = malloc(sizeof(int[x][y])); int (*arr3D)[y][z] = malloc(sizeof(int[x][y][z])); int (*arr4D)[y][z][w] = malloc(sizeof(int[x][y][z][w]));
This really looks like the perfect solution. Easy to adapt to any number of dimensions and easy to index. The only downside I could find is that VLA support is not required since C11, but I'm not sure if any big compiler doesn't support them.
So, is number 3 really the best way of doing it by a far margin? Or are there any downsides to it that I don't know of? What is the method you would use on some real world project?
You use pointers.
Specifically, you use a pointer to an address, and using a standard c library function calls, you ask the operating system to expand the heap to allow you to store what you need to.
Now, it might refuse, which you will need to handle.
The next question becomes - how do you ask for a 2D array? Well, you ask for an array of pointers, and then expand each pointer.
As an example, consider this:
int i = 0;
char** words;
words = malloc((num_words)*sizeof(char*));
if ( words == NULL )
{
/* we have a problem */
printf("Error: out of memory.\n");
return;
}
for ( i=0; i<num_words; i++ )
{
words[i] = malloc((word_size+1)*sizeof(char));
if ( words[i] == NULL )
{
/* problem */
break;
}
}
if ( i != num_words )
{
/* it didn't allocate */
}
This gets you a two-dimensional array, where each element words[i] can have a different size, determinable at run time, just as the number of words is.
You will need to free() all of the resultant memory by looping over the array when you're done with it:
for ( i = 0; i < num_words; i++ )
{
free(words[i]);
}
free(words);
If you don't, you'll create a memory leak.
You could also use calloc. The difference is in calling convention and effect - calloc initialises all the memory to 0 whereas malloc does not.
If you need to resize at runtime, use realloc.
- Malloc
- Calloc
- Realloc
- Free
Also, important, watch out for the word_size+1 that I have used. Strings in C are zero-terminated and this takes an extra character which you need to account for. To ensure I remember this, I usually set the size of the variable word_size to whatever the size of the word should be (the length of the string as I expect) and explicitly leave the +1 in the malloc for the zero. Then I know that the allocated buffer can take a string of word_size characters. Not doing this is also fine - I just do it because I like to explicitly account for the zero in an obvious way.
There is also a downside to this approach - I've explicitly seen this as a shipped bug recently. Notice I wrote (word_size+1)*sizeof(type) - imagine however that I had written word_size*sizeof(type)+1. For sizeof(type)=1 these are the same thing but Windows uses wchar_t very frequently - and in this case you'll reserve one byte for your last zero rather than two - and they are zero-terminated elements of type type, not single zero bytes. This means you'll overrun on read and write.
Addendum: do it whichever way you like, just watch out for those zero terminators if you're going to pass the buffer to something that relies on them.
While Ninefingers provided an answer using an array of pointers , you can also use an array of arrays as long as the inner array's size is a constant expression. The code for this is simpler.
char (*words)[15]; // 'words' is pointer to char[15]
words = malloc (num_words * sizeof(char[15]);
// to access character i of word w
words[w][i];
free(words);
I was going through an example of C code, and I was trying to figure out WHY we have to dynamically allocate an array rather than statically allocate in a specific example. I will write the example in pseudo code as it is simple and the code is not the point of this question:
obtain user input using scanf method and store in variable of type int n
Create an array int A[n]
Is my logic sound for why this is wrong:
This is wrong because the compiler has to decide the size of the function stack. In order to asses the size of the function stack, it will observe each of the variables in the function. However, since the value of n will only be determined at runtime, we cannot determine how much stack memory is needed for array A because the size will only be determined at run time. As a result, we must dynamically allocate memory.