From the documentation:
range([start], stop[, step])
The start defaults to 0, the step can be whatever you want, except 0 and stop is your upper bound, it is not the number of iterations. So declare n to be whatever your upper bound is correctly and you will not have to add 1 to it.
e.g.
>>> for i in range(1, 7, 1): print(i)
...
1
2
3
4
5
6
>>> for i in range(1, 7, 2): print(i)
...
1
3
5
A nice feature, is that it works in reverse as well.
>>> for i in range(7, 0, -1): print(i)
...
7
6
5
4
3
2
1
If you aren't using it as an index but for something that can have positive or negative values, it still comes in handy:
>>> for i in range(2, -3, -1): print(i)
...
2
1
0
-1
-2
>>> for i in range(-2, 3, 1): print(i)
...
-2
-1
0
1
2
Answer from Rolf of Saxony on Stack OverflowI am pulling data from a dictionary and appending it to a list, but it appears that dictionary keys start at 1, not 0.
We have been taught to use for loops for this kind of task, but they initialize at 0. Can I start at 1? If not, what is an alternative? Thanks!
for i in range(len(dict)):
<code goes here>python - Pythonic way to iterate through a range starting at 1 - Stack Overflow
Python for loop start counter initialization - Stack Overflow
python - Why is this for loop starting at index 1 instead of index 0? - Stack Overflow
Can a for loop start somewhere other than 0?
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From the documentation:
range([start], stop[, step])
The start defaults to 0, the step can be whatever you want, except 0 and stop is your upper bound, it is not the number of iterations. So declare n to be whatever your upper bound is correctly and you will not have to add 1 to it.
e.g.
>>> for i in range(1, 7, 1): print(i)
...
1
2
3
4
5
6
>>> for i in range(1, 7, 2): print(i)
...
1
3
5
A nice feature, is that it works in reverse as well.
>>> for i in range(7, 0, -1): print(i)
...
7
6
5
4
3
2
1
If you aren't using it as an index but for something that can have positive or negative values, it still comes in handy:
>>> for i in range(2, -3, -1): print(i)
...
2
1
0
-1
-2
>>> for i in range(-2, 3, 1): print(i)
...
-2
-1
0
1
2
range(1, n+1) is not considered duplication, but I can see that this might become a hassle if you were going to change 1 to another number.
This removes the duplication using a generator:
for _ in (number+1 for number in range(5)):
print(_)
The for index in range(len(list)) loop executes the loop body with index first set to 0, then 1, then 2, etc. up to len(list) - 1. The previous value of index is ignored and overwritten. If you want index to start at iteration + 1, use the 2-argument form of range:
for index in range(iteration + 1, len(list)):
You really should be using enumerate for stuff like this, as you can loop through the index and the value at the same time (which will save you the hassle of using two for-loops).
for i, j in enumerate(list):
print i, j
Your inner loop is overriding the variable index that you defined in the first loop.
l = [a, b, c, d]
for x in l
print(x)Can this start at an index other than 0?