Just pre-size a vector before the for loop as e.g. result = zeros( 1, 7 ); then inside the for loop: result = result + newValues; where newValues are the results calculated in that iteration. Unfortunately Matlab doesn't have a += operator. That will add them together as you go. If you really want to only do so at the end then you'd have to store an ( n * m ) matrix for n iterations with length m result and then sum along the relevant dimension.

A basic for loop in MATLAB is often used to assign to or access array elements iteratively. For example, let’s say you have a vector A, and you want to simply display each value one at a time: A = [3 6 9 4 1]; for i = 1:length(A) disp(A(i)) end For more examples using for loops, see:

The problem is that you are not using the index N. A = (Array(1,1)*Z)/Array(1,2); This line doesn't change, so you will get the same output 15 times. A nested loop would look like this: [row,col] = size(B); for N = 1:col for M = 1:row A = (B(M,N)*Z)/B(1,2); disp (A) end end The first loop will start at column 1, then the second loop goes through all rows. After that it repeats with column 2 and so on if you have more columns. Depending on how you want to manipulate the entries you have to use both indexes accordingly.

Hi There is a search feature in the forum, you will find hundreds of examples for this. But your problem is that you are overwriting Clt in each iteration. The solution is to save each iteration in a new column (or row). Generally speaking, it is always good to pre-initialize data containers (in this case a matrix) before filling it in a loop. Something like: % Set initial paramters. Cl_initial=3; R=0.5; u=0.5; t=[68.92 109.97 287.22 116.95 171.89 90.3 103.54]; Nt = length(t); Clt = zeros(2,Nt); % Solve for Cl residual. for i = 1:Nt Clt(:,i) = [ t(i) ; Cl_initial*(1-R)/(1-R*exp(-u*t(i)))]; end

ukn = zeros(1,10) ; for i = 1:10 if i == 1 ukn(i) = uk+udotreal(i,i) ; else ukn(i) = ukn(i-1)+udotreal(i,i) ; end end