Use itertools.count:
from itertools import count
class MyClass(object):
id_counter = count().next
def __init__(self):
self.id = self.id_counter()
Answer from agf on Stack Overflow Top answer 1 of 3
6
Use itertools.count:
from itertools import count
class MyClass(object):
id_counter = count().next
def __init__(self):
self.id = self.id_counter()
2 of 3
4
Why use iterators / generators at all? They do the job, but isn't it overkill? Whats wrong with
class MyClass(object):
id_ctr = 0
def __init__(self):
self.id = MyClass.id_ctr
MyClass.id_ctr += 1
Program Creek
programcreek.com โบ python
Python generate sequence
def generate_note_sequence(instrument_phrases, note_mats, length, tick_max=160): next_phrase = random.choice(instrument_phrases) phrases = [] sofar = 0 while sofar < length: phrases.append(next_phrase) sofar += sum([next_phrase["tick"][i] for i in xrange(0,len(next_phrase["tick"])) if next_phrase["type"][i] == "on"]) last_pitch = next_phrase["pitch"][-1] last_tick = next_phrase["tick"][-1] last_velocity = next_phrase["velocity"][-1] pitch = find_match(note_mats, last_pitch, note_type="pitch") velocity = find_match(note_mats, last_velocity, note_type="velocity") tick = find_match(note_mats, last_tick, note_type="tick") next_phrase = find_next_phrase(pitch, velocity, tick, instrument_phrases) return phrases ... def generate_note_sequence_id(filename, collection_name, source_type): """Generates a unique ID for a sequence.
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Generating Unique IDs in Python - YouTube
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How to create a sequence of numbers in Python - YouTube
Stack Overflow
stackoverflow.com โบ questions โบ 34287404 โบ how-to-generate-sequence-number-in-python
json - How to generate sequence number in python? - Stack Overflow
Good news is, you can store them in mongo! db.sequences.find() > { "_id": "alerts", "last_value": 234 } Then you can use findAndModify to generate a new value and return it in the same operation (no race conditions, safe and reliable).
TutorialsPoint
tutorialspoint.com โบ How-to-generate-sequences-in-Python
How to generate sequences in Python?
February 27, 2025 - tuple_1 = (2,4,6,8) list_comp = ... new sequence in a single line and we can access the items of it. To generate an object by using a generator function we use the yield keyword instead of the return keyword....
Linux Hint
linuxhint.com โบ python-generate-sequence-of-numbers
Linux Hint โ Linux Hint
July 24, 2023 - Linux Hint LLC, [email protected] 1210 Kelly Park Circle, Morgan Hill, CA 95037 Privacy Policy and Terms of Use
GitConnected
levelup.gitconnected.com โบ the-fastest-way-to-generate-a-sequence-in-python-a61da7f87852
The fastest way to generate a sequence in Python | by Astronomy not Astrology, hunty... | Level Up Coding
May 14, 2020 - The built-in method range([start, ]stop, [step]) was my first introduction to generating sequences in Python. The optional arguments in the function are shown in square brackets. The range() method generates an immutable object that is a sequence of numbers.
Stack Overflow
stackoverflow.com โบ questions โบ 68518710 โบ printing-a-list-in-python-and-generating-an-id-column-for-each-item-sequence-of
Printing a list in Python and generating an ID column for each item (sequence of numbers) - Stack Overflow
Using Python I want to print the elements of a list using for loop and also I want to generate a number for each item in the list. Something like an ID column next to the column containing the list's
Camdenreslink
code.camdenreslink.com โบ dev โบ 7-ways-to-create-sequences-in-python
7 Ways to Create Sequences in Python โ Camden Reslink
December 5, 2018 - If each value in your sequence can be calculated using a simple expression (where every value follows some rule), list comprehensions provide a terse and expressive method for creating your sequence. List comprehensions follow the format: [{expression with variable} for {variable} in {iterator} if {condition with variable}] Letโs consider the simple example of generating the first n-even numbers:
Top answer 1 of 9
41
Every number from 1,2,5,6,9,10... is divisible by 4 with remainder 1 or 2.
>>> ','.join(str(i) for i in xrange(100) if i % 4 in (1,2))
'1,2,5,6,9,10,13,14,...'
2 of 9
20
>>> ','.join('{},{}'.format(i, i + 1) for i in range(1, 100, 4))
'1,2,5,6,9,10,13,14,17,18,21,22,25,26,29,30,33,34,37,38,41,42,45,46,49,50,53,54,57,58,61,62,65,66,69,70,73,74,77,78,81,82,85,86,89,90,93,94,97,98'
That was a quick and quite dirty solution.
Now, for a solution that is suitable for different kinds of progression problems:
def deltas():
while True:
yield 1
yield 3
def numbers(start, deltas, max):
i = start
while i <= max:
yield i
i += next(deltas)
print(','.join(str(i) for i in numbers(1, deltas(), 100)))
And here are similar ideas implemented using itertools:
from itertools import cycle, takewhile, accumulate, chain
def numbers(start, deltas, max):
deltas = cycle(deltas)
numbers = accumulate(chain([start], deltas))
return takewhile(lambda x: x <= max, numbers)
print(','.join(str(x) for x in numbers(1, [1, 3], 100)))
DataCamp
campus.datacamp.com โบ courses โบ introduction-to-python-for-finance โบ arrays-in-python
Generating a sequence of numbers | Python
The NumPy function arange() is an efficient way to create numeric arrays of a range of numbers. The arguments for arange() include the start, stop, and step interval as shown below: ... Create an array company_ids containing the numbers 1 through 7 (inclusive).
Patrickwalls
patrickwalls.github.io โบ mathematicalpython โบ python โบ sequences
Sequences - Mathematical Python
It is very inefficient to create a sequence by manually typing the numbers. For example, simply typing out the numbers from 1 to 20 takes a long time! numbers = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20] print(numbers) [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20] Python has a beautiful syntax for creating lists called list comprehensions.