You could do it like that:

File folder = new File("your/path");
File[] listOfFiles = folder.listFiles();
if(listOfFiles != null) {
 for (int i = 0; i < listOfFiles.length; i++) {
  if (listOfFiles[i].isFile()) {
    System.out.println("File " + listOfFiles[i].getName());
  } else if (listOfFiles[i].isDirectory()) {
    System.out.println("Directory " + listOfFiles[i].getName());
  }
 }
}

Do you want to only get JPEG files or all files?

Use:

public void listFilesForFolder(final File folder) {
    for (final File fileEntry : folder.listFiles()) {
        if (fileEntry.isDirectory()) {
            listFilesForFolder(fileEntry);
        } else {
            System.out.println(fileEntry.getName());
        }
    }
}

final File folder = new File("/home/you/Desktop");
listFilesForFolder(folder);

The Files.walk API is available from Java 8.

try (Stream<Path> paths = Files.walk(Paths.get("/home/you/Desktop"))) {
    paths
        .filter(Files::isRegularFile)
        .forEach(System.out::println);
} 

The example uses the try-with-resources pattern recommended in the API guide. It ensures that no matter circumstances, the stream will be closed.

    Path configFilePath = FileSystems.getDefault()
            .getPath("C:\\Users\\sharmaat\\Desktop\\issue\\stores");

    List<Path> fileWithName = Files.walk(configFilePath)
            .filter(s -> s.toString().endsWith(".java"))
            .map(Path::getFileName).sorted().collect(Collectors.toList());

    for (Path name : fileWithName) {
        // printing the name of file in every sub folder
        System.out.println(name);
    }

Please have a look at Files.find method.

try (Stream<Path> stream = Files.find(Paths.get("Folder 1"), 5,
            (path, attr) -> path.getFileName().toString().equals("Myfile.txt") )) {
        System.out.println(stream.findAny().isPresent());
} catch (IOException e) {
        e.printStackTrace();
}