yourString.substring(yourString.indexOf("no") + 3 , yourString.length());

String example = "/abc/def/ghfj.doc";
System.out.println(example.substring(example.lastIndexOf("/") + 1));

You can use RegExp: "\s*totalWinAmount\s*"\s*:\s*(?<totalWinAmount>\d*)

This is Demo at regex101.com

This is the most simpliest way to get couple of values (I think that using json converter is overhead for this reason). But if you want to find more values, then definitely, you have to use json converter (e.g. Jackson).

You can use indexOf and substring. First get the start of the link by getting the index of "https://twitter.com/". Then you look for a space after the beginning of the link, if one exists link ends there, otherwise it ends at the end of the message. Then we can use the substring method to get the link:

int startIndex = message.indexOf("https://twitter.com/");
int endIndex = message.indexOf(" ", startIndex);
if (endIndex == -1) {
    endIndex = message.length();
}
String link = message.substring(startIndex, endIndex);

Another easy way, split everything by space and check if they match the requirements:

String[] words = message.split(" ");
for (String word : words) {
    if (word.startsWith("https://twitter.com/")) {
        // ...
    }
}

indexOf is what you need. Try:

sentence.substring(0, sentence.indexOf(“Administrator”) + ”Administrator”.length())

Assuming that "temp_username_current_timestamp" is not known and is expected to be different every time but you know the word or specific character that precedes what you want to extract, you should use indexOf(String str):

String input = "create table temp_username_current_timestamp other params"
String precedes = "table";
String extracted;

//Get the index of the start of the word to extract
int startIndex = input.indexOf(precedes) + precedes.length;
//Check if the word we are looking for is even there
if(startIndex > -1){
    //Get the index of the next space character
    int endIndex = input.indexOf(" ", startIndex);

    //If there are more parameters following ignore them
    if(endIndex > -1){
        //Extract the parameter given the indexes found
        extracted = input.substring(startIndex, endIndex);  
    } else {
        //If we are at the end of the string just extract what remains
        extracted = input.substring(startIndex);
    }
}

For example:

String s = "Chocolate:30:2";
String number = s.split(":")[2];

Assuming you are trying to find parent location of specified file simplest way would be using File class or Path instead of String methods. Your code will be more readable and probably safer.

Using java.io.File:

String location = "/abc/def/ghfj.doc";

File f = new File(location);
String parentName = f.getParentFile().getName();

System.out.println(parentName);

Using java.nio.file.Path:

String location = "/abc/def/ghfj.doc";

Path p = Paths.get(location);
String parent = p.getParent().getFileName().toString();

System.out.println(parent);

Output in both cases: def

In case of selecting def in /abc/def/ghfj/ijk/lmn.doc you could use Path#getName(N) where N is zero-based index of elements from farthermost ancestor to selected file like abc is 0, def is 1,...

So your code can look like:

String location = "/abc/def/ghfj/ijk/lmn.doc";

Path p = Paths.get(location);
String parent = p.getName(1).getFileName().toString();

System.out.println(parent);// Output: def