func ParseInt(s string, base int, bitSize int) (i int64, err error)
ParseInt always returns int64.
bitSize defines the range of values.
If the value corresponding to s cannot be represented by a signed integer of the given size, err.Err = ErrRange.
http://golang.org/pkg/strconv/#ParseInt
type int int
int is a signed integer type that is at least 32 bits in size. It is a distinct type, however, and not an alias for, say, int32.
http://golang.org/pkg/builtin/#int
So int could be bigger than 32 bit in the future or on some systems like int in C.
I guess on some systems int64 might be faster than int32 because that system only works with 64-bit integers.
Here is an example of an error when bitSize is 8:
http://play.golang.org/p/_osjMqL6Nj
package main
import (
"fmt"
"strconv"
)
func main() {
i, err := strconv.ParseInt("123456", 10, 8)
fmt.Println(i, err)
}
Answer from Shuriken on Stack Overflowfunc ParseInt(s string, base int, bitSize int) (i int64, err error)
ParseInt always returns int64.
bitSize defines the range of values.
If the value corresponding to s cannot be represented by a signed integer of the given size, err.Err = ErrRange.
http://golang.org/pkg/strconv/#ParseInt
type int int
int is a signed integer type that is at least 32 bits in size. It is a distinct type, however, and not an alias for, say, int32.
http://golang.org/pkg/builtin/#int
So int could be bigger than 32 bit in the future or on some systems like int in C.
I guess on some systems int64 might be faster than int32 because that system only works with 64-bit integers.
Here is an example of an error when bitSize is 8:
http://play.golang.org/p/_osjMqL6Nj
package main
import (
"fmt"
"strconv"
)
func main() {
i, err := strconv.ParseInt("123456", 10, 8)
fmt.Println(i, err)
}
Package strconv
func ParseInt
func ParseInt(s string, base int, bitSize int) (i int64, err error)ParseInt interprets a string s in the given base (2 to 36) and returns the corresponding value i. If base == 0, the base is implied by the string's prefix: base 16 for "0x", base 8 for "0", and base 10 otherwise.
The bitSize argument specifies the integer type that the result must fit into. Bit sizes 0, 8, 16, 32, and 64 correspond to int, int8, int16, int32, and int64.
The errors that ParseInt returns have concrete type *NumError and include err.Num = s. If s is empty or contains invalid digits, err.Err = ErrSyntax; if the value corresponding to s cannot be represented by a signed integer of the given size, err.Err = ErrRange.
ParseInt always returns an int64 value. Depending on bitSize, this value will fit into int, int8, int16, int32, or int64. If the value cannot be represented by a signed integer of the size given by bitSize, then err.Err = ErrRange.
The Go Programming Language Specification
Numeric types
The value of an n-bit integer is n bits wide and represented using two's complement arithmetic.
int8 the set of all signed 8-bit integers (-128 to 127) int16 the set of all signed 16-bit integers (-32768 to 32767) int32 the set of all signed 32-bit integers (-2147483648 to 2147483647) int64 the set of all signed 64-bit integers (-9223372036854775808 to 9223372036854775807)There is also a set of predeclared numeric types with implementation-specific sizes:
uint either 32 or 64 bits int same size as uint
int is either 32 or 64 bits, depending on the implementation. Usually it's 32 bits for 32-bit compilers and 64 bits for 64-bit compilers.
To find out the size of an int or uint, use strconv.IntSize.
Package strconv
Constants
const IntSize = intSize
IntSizeis the size in bits of anintoruintvalue.
For example,
package main
import (
"fmt"
"runtime"
"strconv"
)
func main() {
fmt.Println(runtime.Compiler, runtime.GOARCH, runtime.GOOS)
fmt.Println(strconv.IntSize)
}
Output:
gc amd64 linux
64
Is a Int the same as Int64?
go - interface & integer comparison in golang - Stack Overflow
go - Golang compare numbers - Stack Overflow
Compare two variables regardless of their data type
You convert them with a type "conversion"
var a int
var b int64
int64(a) < b
When comparing values, you always want to convert the smaller type to the larger. Converting the other way will possibly truncate the value:
var x int32 = 0
var y int64 = math.MaxInt32 + 1 // y == 2147483648
if x < int32(y) {
// this evaluates to false, because int32(y) is -2147483648
Or in your case to convert the maxInt int64 value to an int, you could use
for a := 2; a < int(maxInt); a++ {
which would fail to execute correctly if maxInt overflows the max value of the int type on your system.
I came here because of the title, "How to convert an int64 to int in Go?". The answer is,
int(int64Var)
So I am sorry if this is the wrong subreddit to be posting this but I ran into an unusual error today that I wasn't able to come up with a solution for... I have a string being parsed to an int via strconv.ParseInt which returns an int64, but once I have the int64 I cannot seem to add other numbers to it. Is there something I am missing?
stringVal := "1" valInt1, errValInt1 := strconv.ParseInt(stringVal, 0 , 64) currentVal := valInt1 newVal := currentVal + 1
Thank you for any advice or help.
Edit: Thanks everyone... outside of this I was casting it back to string to place it in a cache... looks like you can't use string(int64) for int64s but rather need to use strconv.FormatInt()
As the title says. Working on a project that stores data in a DB and whoever wrote it uses int64 and C.int64_t. And in some places they cast C.int64 as int64…. Why?!