If I understand correctly you want to return .css file where .scss file exist. Here is the gulpfile.js code.
'use strict';
var gulp = require('gulp');
var sass = require('gulp-sass');
var autoprefixer = require('autoprefixer');
var postcss = require('gulp-postcss');
var paths = {
styles: {
src: 'modules/**/*.scss',
dest: 'modules'
}
}
function scss() {
return gulp.src(paths.styles.src)
.pipe(sass().on('error', sass.logError))
.pipe(sass({ outputStyle: 'compressed' }))
.pipe(postcss([autoprefixer()]))
.pipe(gulp.dest(paths.styles.dest));
}
exports.scss = scss
function watch() {
scss()
gulp.watch(paths.styles.src, scss);
}
exports.watch = watch
package.json file need devDependencies and browserlist. it will be like this.
"devDependencies": {
"autoprefixer": "^9.7.4",
"gulp": "^4.0.2",
"gulp-postcss": "^8.0.0",
"gulp-sass": "^4.0.2"
},
"browserslist": [
"last 71 version"
],
use $ gulp watch running your task.
Your folder structure like this
Themes
modules
hero
hero.html
hero.scss
header
header.html
header.scss
footer
footer.html
footer.scss
package.json
gulpfile.js
It will return
Themes
modules
hero
hero.html
hero.css
hero.scss
header
header.html
header.css
header.scss
footer
footer.html
footer.css
footer.scss
package.json
gulpfile.js
Hope this help!
Answer from Rahul on Stack OverflowIf I understand correctly you want to return .css file where .scss file exist. Here is the gulpfile.js code.
'use strict';
var gulp = require('gulp');
var sass = require('gulp-sass');
var autoprefixer = require('autoprefixer');
var postcss = require('gulp-postcss');
var paths = {
styles: {
src: 'modules/**/*.scss',
dest: 'modules'
}
}
function scss() {
return gulp.src(paths.styles.src)
.pipe(sass().on('error', sass.logError))
.pipe(sass({ outputStyle: 'compressed' }))
.pipe(postcss([autoprefixer()]))
.pipe(gulp.dest(paths.styles.dest));
}
exports.scss = scss
function watch() {
scss()
gulp.watch(paths.styles.src, scss);
}
exports.watch = watch
package.json file need devDependencies and browserlist. it will be like this.
"devDependencies": {
"autoprefixer": "^9.7.4",
"gulp": "^4.0.2",
"gulp-postcss": "^8.0.0",
"gulp-sass": "^4.0.2"
},
"browserslist": [
"last 71 version"
],
use $ gulp watch running your task.
Your folder structure like this
Themes
modules
hero
hero.html
hero.scss
header
header.html
header.scss
footer
footer.html
footer.scss
package.json
gulpfile.js
It will return
Themes
modules
hero
hero.html
hero.css
hero.scss
header
header.html
header.css
header.scss
footer
footer.html
footer.css
footer.scss
package.json
gulpfile.js
Hope this help!
gulp.dest() only wants a path, it will then append the current file path to it. And sass() will already have changed the extension to css so that shouldn't be a problem either. So in your case it should work like this.
gulp.task('sass', function() {
return gulp.src('modules/**/*.scss')
.pipe(sass())
.pipe(gulp.dest('modules/'));
});
» npm install gulp-sass
Converting scss to css using gulp. [Problems]
Why doesn't Gulp seem to recognise changes in my compiled .css files? (x-post r/wedev)
Attempting to compile Sass via Gulp, task runs but no CSS file is made.
I think you are missing return before gulp.src
More on reddit.comGulp scss to css is way to slow
Videos
» npm install gulp-css-scss
» npm install gulp-scss