To convert an integer to a float in Python you can use the following:
float_version = float(int_version)
The reason you are getting 0 is that Python 2 returns an integer if the mathematical operation (here a division) is between two integers. So while the division of 144 by 314 is 0.45~~~, Python converts this to integer and returns just the 0 by eliminating all numbers after the decimal point.
Alternatively you can convert one of the numbers in any operation to a float since an operation between a float and an integer would return a float. In your case you could write float(144)/314 or 144/float(314). Another, less generic code, is to say 144.0/314. Here 144.0 is a float so it’s the same thing.
To convert an integer to a float in Python you can use the following:
float_version = float(int_version)
The reason you are getting 0 is that Python 2 returns an integer if the mathematical operation (here a division) is between two integers. So while the division of 144 by 314 is 0.45~~~, Python converts this to integer and returns just the 0 by eliminating all numbers after the decimal point.
Alternatively you can convert one of the numbers in any operation to a float since an operation between a float and an integer would return a float. In your case you could write float(144)/314 or 144/float(314). Another, less generic code, is to say 144.0/314. Here 144.0 is a float so it’s the same thing.
Other than John's answer, you could also make one of the variable float, and the result will yield float.
>>> 144 / 314.0
0.4585987261146497
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All integers that can be represented by floating point numbers have an exact representation. So you can safely use int on the result. Inexact representations occur only if you are trying to represent a rational number with a denominator that is not a power of two.
That this works is not trivial at all! It's a property of the IEEE floating point representation that int∘floor = ⌊⋅⌋ if the magnitude of the numbers in question is small enough, but different representations are possible where int(floor(2.3)) might be 1.
To quote from Wikipedia,
Any integer with absolute value less than or equal to 224 can be exactly represented in the single precision format, and any integer with absolute value less than or equal to 253 can be exactly represented in the double precision format.
Use int(your non integer number) will nail it.
print int(2.3) # "2"
print int(math.sqrt(5)) # "2"
Say I have a large int value
>>> 7 ** 69 20500514515695490612229010908095867391439626248463723805607
Now let's say I convert it to a float value.
>>> float(7 ** 69) 2.050051451569549e+58
Seems about right. Now if I convert it back to back into an int...
>>> int(float(7 ** 69)) 20500514515695489879650927979797501063745685669370929348608
Now it's a very different number. Why did that happen?
I am sorry if it's a stupid question but this has me very intrigued.
'20.0' is a string, not a float; you can tell by the single-quotes in the error message. You can get an int out of it by first parsing it with float, then truncating it with int:
>>> int(float('20.0'))
20
(Though maybe you'd want to store floats instead of strings in your dictionary, since that is what you seem to be expecting.)
It looks like the value is a string, not a float. So you need int(float(gex_dict[i]))