There is strtol which is better IMO. Also I have taken a liking in strtonum, so use it if you have it (but remember it's not portable):
long long
strtonum(const char *nptr, long long minval, long long maxval,
const char **errstr);
You might also be interested in strtoumax and strtoimax which are standard functions in C99. For example you could say:
uintmax_t num = strtoumax(s, NULL, 10);
if (num == UINTMAX_MAX && errno == ERANGE)
/* Could not convert. */
Anyway, stay away from atoi:
Answer from cnicutar on Stack OverflowThe call atoi(str) shall be equivalent to:
(int) strtol(str, (char **)NULL, 10)except that the handling of errors may differ. If the value cannot be represented, the behavior is undefined.
There is strtol which is better IMO. Also I have taken a liking in strtonum, so use it if you have it (but remember it's not portable):
long long
strtonum(const char *nptr, long long minval, long long maxval,
const char **errstr);
You might also be interested in strtoumax and strtoimax which are standard functions in C99. For example you could say:
uintmax_t num = strtoumax(s, NULL, 10);
if (num == UINTMAX_MAX && errno == ERANGE)
/* Could not convert. */
Anyway, stay away from atoi:
The call atoi(str) shall be equivalent to:
(int) strtol(str, (char **)NULL, 10)except that the handling of errors may differ. If the value cannot be represented, the behavior is undefined.
Robust C89 strtol-based solution
With:
- no undefined behavior (as could be had with the
atoifamily) - a stricter definition of integer than
strtol(e.g. no leading whitespace nor trailing trash chars) - classification of the error case (e.g. to give useful error messages to users)
- a "testsuite"
#include <assert.h>
#include <ctype.h>
#include <errno.h>
#include <limits.h>
#include <stdio.h>
#include <stdlib.h>
typedef enum {
STR2INT_SUCCESS,
STR2INT_OVERFLOW,
STR2INT_UNDERFLOW,
STR2INT_INCONVERTIBLE
} str2int_errno;
/* Convert string s to int out.
*
* @param[out] out The converted int. Cannot be NULL.
*
* @param[in] s Input string to be converted.
*
* The format is the same as strtol,
* except that the following are inconvertible:
*
* - empty string
* - leading whitespace
* - any trailing characters that are not part of the number
*
* Cannot be NULL.
*
* @param[in] base Base to interpret string in. Same range as strtol (2 to 36).
*
* @return Indicates if the operation succeeded, or why it failed.
*/
str2int_errno str2int(int *out, char *s, int base) {
char *end;
if (s[0] == '\0' || isspace((unsigned char) s[0]))
return STR2INT_INCONVERTIBLE;
errno = 0;
long l = strtol(s, &end, base);
/* Both checks are needed because INT_MAX == LONG_MAX is possible. */
if (l > INT_MAX || (errno == ERANGE && l == LONG_MAX))
return STR2INT_OVERFLOW;
if (l < INT_MIN || (errno == ERANGE && l == LONG_MIN))
return STR2INT_UNDERFLOW;
if (*end != '\0')
return STR2INT_INCONVERTIBLE;
*out = l;
return STR2INT_SUCCESS;
}
int main(void) {
int i;
/* Lazy to calculate this size properly. */
char s[256];
/* Simple case. */
assert(str2int(&i, "11", 10) == STR2INT_SUCCESS);
assert(i == 11);
/* Negative number . */
assert(str2int(&i, "-11", 10) == STR2INT_SUCCESS);
assert(i == -11);
/* Different base. */
assert(str2int(&i, "11", 16) == STR2INT_SUCCESS);
assert(i == 17);
/* 0 */
assert(str2int(&i, "0", 10) == STR2INT_SUCCESS);
assert(i == 0);
/* INT_MAX. */
sprintf(s, "%d", INT_MAX);
assert(str2int(&i, s, 10) == STR2INT_SUCCESS);
assert(i == INT_MAX);
/* INT_MIN. */
sprintf(s, "%d", INT_MIN);
assert(str2int(&i, s, 10) == STR2INT_SUCCESS);
assert(i == INT_MIN);
/* Leading and trailing space. */
assert(str2int(&i, " 1", 10) == STR2INT_INCONVERTIBLE);
assert(str2int(&i, "1 ", 10) == STR2INT_INCONVERTIBLE);
/* Trash characters. */
assert(str2int(&i, "a10", 10) == STR2INT_INCONVERTIBLE);
assert(str2int(&i, "10a", 10) == STR2INT_INCONVERTIBLE);
/* int overflow.
*
* `if` needed to avoid undefined behaviour
* on `INT_MAX + 1` if INT_MAX == LONG_MAX.
*/
if (INT_MAX < LONG_MAX) {
sprintf(s, "%ld", (long int)INT_MAX + 1L);
assert(str2int(&i, s, 10) == STR2INT_OVERFLOW);
}
/* int underflow */
if (LONG_MIN < INT_MIN) {
sprintf(s, "%ld", (long int)INT_MIN - 1L);
assert(str2int(&i, s, 10) == STR2INT_UNDERFLOW);
}
/* long overflow */
sprintf(s, "%ld0", LONG_MAX);
assert(str2int(&i, s, 10) == STR2INT_OVERFLOW);
/* long underflow */
sprintf(s, "%ld0", LONG_MIN);
assert(str2int(&i, s, 10) == STR2INT_UNDERFLOW);
return EXIT_SUCCESS;
}
GitHub upstream.
Based on: https://stackoverflow.com/a/6154614/895245
Converting char/string to int?
Beginner needing help, converting string to integer.
How to convert integer to string in C? - Stack Overflow
is there any function in c to convert an integer to a string?
Can I convert string to integer in C without using atoi function?
What is the easiest way to convert string to int in C?
Why do we need to convert string to int in C?
Hey all. I am trying to convert strings/chars to ints for a number guessing game. I have created this simple program that is supposed to start out with two character arrays and then convert them into an int, then add the two. It doesn't seem to be working. I get no output. Now I am pretty new to C. I am used to JavaScript where you can just sling data types anywhere you want, so this concept in C is giving me some trouble. Any help would be great! Thanks!
Code:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main(){
char string1[5] = "1234";
char string2[5] = "1000";
printf("String one says: %s \n", string1);
printf("String two says: %s \n \n", string2);
int toInt1 = string1;
int toInt2 = string2;
int add_ints = toInt1 + toInt2;
printf("String one should now be an int: %s \n", toInt1);
printf("String two should now be an int: %s \n", toInt2);
printf("So adding them together should produce: %s", add_ints);
}
Hello, I'm a first year CS student and am learning c++ at my university. I need to build a function that inputs a string from the user, "1234" for example, and then return the integer 1234.
I am not allowed to use the stoi function, and <iostream> and <string> are the only allowed libraries. I'm at a wall, I would appreciate any help! Thanks.
Use sprintf():
int someInt = 368;
char str[12];
sprintf(str, "%d", someInt);
All numbers that are representable by int will fit in a 12-char-array without overflow, unless your compiler is somehow using more than 32-bits for int. When using numbers with greater bitsize, e.g. long with most 64-bit compilers, you need to increase the array size—at least 21 characters for 64-bit types.
Making your own itoa is also easy, try this :
char* itoa(int i, char b[]){
char const digit[] = "0123456789";
char* p = b;
if(i<0){
*p++ = '-';
i *= -1;
}
int shifter = i;
do{ //Move to where representation ends
++p;
shifter = shifter/10;
}while(shifter);
*p = '\0';
do{ //Move back, inserting digits as u go
*--p = digit[i%10];
i = i/10;
}while(i);
return b;
}
or use the standard sprintf() function.