What does 5 have to do with absolute value?

Following your logic:

def my_abs(value):
    """Returns absolute value without using abs function"""
    if value <= 0:
        return value * -1
    return value * 1

print(my_abs(-3.5))
>> 3.5
print(my_abs(3.5))
>> 3.5

Other, shorter solutions also exist and can be seen in the other answers.

J, 2 bytes

**

Usage:

   f =: **
   f 9.3
9.3
   f -9.3
9.3

Explanation:

This uses the * verb in both its monadic and dyadic forms. The monadic form returns -1 if it's given a negative number, 0 if it's given 0 and 1 if it's given a positive number. The dyadic form is just plain old multiplication. Putting them in a function literal turns them into a hook which gets evaluated like this: y * (*y).

But it does make it positive, as can be seen here: https://replit.com/@ShiftyByte/DearSilkyResources#main.py What is the exact issue you are having with this code?

{1e999: x, -1e999: -x}[x*1e999]

I'm serious. This works.

The 1e999 is interpreted as a float, but it overflows the available precision, so it's inf. But infinity can be positive or negative. By multiplying x with infinity, we can coerce it into one of two values based on its sign, without using a condition operator. Then we can select x or its negation from a lookup table.

It's equivalent to the following, but doesn't require the import:

from math import inf

{inf: x, -inf: -x}[x*inf]

I think you can probably figure this one out just with a hint.

What happens to negative numbers when they are multiplied by -1?

Note that you can check if numbers are less than zero using if and then do something about less than zero numbers.

If you still get stuck after thinking on that for a few minutes shoot me a pm.

Edit: as long as you don't ask me to just write out all the code for you.

You can do it with the built-in abs() function:

absolute_val = abs(x)

Otherwise, without the built-in function, use math:

absolute_val = (x ** 2) ** 0.5

Final Answer: To print the absolute value of a number x in Python without the abs function, use an if statement to check if x is negative. If x is negative, multiply it by -1; otherwise, print x directly. This ensures that the output is always a non-negative number. ; Explanation: To find the absolute value of a number x in Python without using the abs() function, you can use an if statement. This statement checks whether x is less than zero. If it is, the code multiplies x by -1 to convert it to a positive value. If x is not negative (meaning it is zero or positive), it can be printed directly. This method effectively ensures that regardless of the original value of x , the output will always be a non-negative number. Here is how the code works step-by-step: Use an if statement to check if x < 0 . If the condition is true (meaning that x is negative), execute print(-x) to convert it to its positive counterpart. If the condition is false (meaning that x is either positive or zero), execute print(x) to return the number as is. Here's the code that implements this logic: if x < 0: print(-x) else: print(x) You can test this code with different values of x . For example, if x is -5, the output will be 5 . If x is 7, the output will be 7 . This approach neatly avoids using the built-in absolute value function while still achieving the correct result. ; Examples & Evidence: For instance, if you set x to -3, the code will output 3 . For x set to 4, it will output 4 as expected. The logic that negative numbers can be converted to positive by multiplying by -1 is based on fundamental arithmetic principles, ensuring accuracy in computation.

1. You can use abs and map functions like this

    myList = [2,3,-3,-2]
    print(list(map(abs, myList)))
   

Output

    [2, 3, 3, 2]

2. Or you can use list comprehension like this

    [abs(number) for number in myList]
   

3. Or you can use list comprehension and a simple if else condition like this

    [-number if number < 0 else number for number in myList]
   

The problem is with the loop you are using , Trying modifying it this way

def abs1(array):
    for i in range(len(array)):
        if array[i] < 0:
             array[i] = array[i] * (-1)
    print(array)

The reason is the loop you were previously using was just for accesing list elements but not giving you reference to change anything in list I solved it with using indexes on list.

That's because what's on the right isn't a number. It's a slice of a list or string. If lines[firsttag] is a string then you should just be able to int() or float() around it first (depending on if it's an integer or floating point value) to get it into a number and then you can call abs on it. Example: >>> data = "12-34546" >>> data[2:4] '-3' >>> int(data[2:4]) -3 >>> abs(int(data[2:4])) 3 >>>