To execute a python script in a bash script you need to call the same command that you would within a terminal. For instance

> python python_script.py var1 var2

To access these variables within python you will need

import sys
print(sys.argv[0]) # prints python_script.py
print(sys.argv[1]) # prints var1
print(sys.argv[2]) # prints var2

You can also use the sys module. Here is an example :

import sys

first_arg = sys.argv[1]
second_arg = sys.argv[2]

def greetings(word1=first_arg, word2=second_arg):
    print("{} {}".format(word1, word2))

if __name__ == "__main__":
    greetings()
    greetings("Bonjour", "monde")

It has the behavior your are looking for :

$ python parse_args.py Hello world
Hello world
Bonjour monde

Method one: some as Windows (not the best option)

Tell the file-manager to open files ending in .py in python /usr/bin/python3 (note the slash at the start). Then double click it.

Method two (not the best option)

Open a shell and type python3 «script name»

Method three (the preferred method)

• Add #!/usr/bin/python3 as the first line of the script.
• Make the file executable chmod +x «script name» (or right click in your file-manager).

side note:

With this method it is better to remove the .py, as it is not needed, and leaks the implementation: All callers of the script need to know the programming language.

Just make sure the python executable is in your PATH environment variable then add in your script

python path/to/the/python_script.py

Details:

• In the file job.sh, put this

#!/bin/sh
python python_script.py

• Execute this command to make the script runnable for you : chmod u+x job.sh
• Run it : ./job.sh

Actually, wouldn't we want to do this?

import sys
sys.argv = ['abc.py','arg1', 'arg2']
execfile('abc.py')