package userinput;

import java.util.Scanner;

public class USERINPUT {

    public static void main(String[] args) {

        Scanner input = new Scanner(System.in);

        //allow user  input;
        System.out.println("How many numbers do you want to enter?");
        int num = input.nextInt();

        int array[] = new int[num];

        System.out.println("Enter the " + num + " numbers now.");

        for (int i = 0 ; i < array.length; i++ ) {
           array[i] = input.nextInt();
        }

        //you notice that now the elements have been stored in the array .. array[]

        System.out.println("These are the numbers you have entered.");
        printArray(array);

        input.close();

    }

    //this method prints the elements in an array......
    //if this case is true, then that's enough to prove to you that the user input has  //been stored in an array!!!!!!!
    public static void printArray(int arr[]){

        int n = arr.length;

        for (int i = 0; i < n; i++) {
            System.out.print(arr[i] + " ");
        }
    }

}

Another idea, not so simple as array, but more elegant is with using Collection of Integers, like this:

public static void main(String[] args) {

    Scanner in = new Scanner(System.in);
    String inputR = in.nextLine();
    String inputs[] = inputR.split(" ");

    if(inputs.length != 5) {
        System.out.println("Invalid number of input");
    }

    List<Integer> integers = new ArrayList<>();
    for (String s : inputs) {
        Integer number = Integer.parseInt(s);
        integers.add(number);
    }
    System.out.println("Got following numbers in my input: "  + integers);
}

You said you could use the following code in C++:

for(i=0;i<6;i++) 
cin>>a[i];

If this is what you used in C++, why not just use this?

for(i=0;i<6;i++)
a[i] = input.nextInt();

Assuming that the scanner declaration was:

Scanner input = new Scanner(System.in);

From what I've seen, people are trying to write the entire program for you. But seeing as you stated you could solve this problem using the C++ code, I just converted the code to Java for you.

If you want the full code, here it is:

import java.util.Scanner;

public class arrayFun {

    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);

        // Create a new array. The user enters the size
        int[] array = new int[input.nextInt()];

        // Get the value of each element in the array
        for(int i = 0; i < array.length; i++)
            array[i] = input.nextInt();

        /* Note that the user can type the following:
         * 6
         * 34 12 7 4 22 15
         * This will set the array to size 6
         * array[0] = 34;
         * array[1] = 12;
         * etc.
         */

    }

}

I realize that this response is years late, but I was searching for a different question when I ran across this. The answers here were very confusing to me until I realized this wasn't what I was looking for. Seeing as this still shows up on google, I decided to post this.