Use a wrapper
Any kind of wrapper is good.
With Java 10+, use this construct as it's very easy to setup:
var wrapper = new Object(){ int ordinal = 0; };
list.forEach(s -> {
s.setOrdinal(wrapper.ordinal++);
});
With Java 8+, use either an AtomicInteger:
AtomicInteger ordinal = new AtomicInteger(0);
list.forEach(s -> {
s.setOrdinal(ordinal.getAndIncrement());
});
... or an array:
int[] ordinal = { 0 };
list.forEach(s -> {
s.setOrdinal(ordinal[0]++);
});
Note: be very careful if you use a parallel stream. You might not end up with the expected result. Other solutions like Stuart's might be more adapted for those cases.
For types other than int
Of course, this is still valid for types other than int.
For instance, with Java 10+:
var wrapper = new Object(){ String value = ""; };
list.forEach(s->{
wrapper.value += "blah";
});
Or if you're stuck with Java 8 or 9, use the same kind of construct as we did above, but with an AtomicReference...
AtomicReference<String> value = new AtomicReference<>("");
list.forEach(s -> {
value.set(value.get() + s);
});
... or an array:
String[] value = { "" };
list.forEach(s-> {
value[0] += s;
});
Answer from Olivier Grégoire on Stack OverflowUse a wrapper
Any kind of wrapper is good.
With Java 10+, use this construct as it's very easy to setup:
var wrapper = new Object(){ int ordinal = 0; };
list.forEach(s -> {
s.setOrdinal(wrapper.ordinal++);
});
With Java 8+, use either an AtomicInteger:
AtomicInteger ordinal = new AtomicInteger(0);
list.forEach(s -> {
s.setOrdinal(ordinal.getAndIncrement());
});
... or an array:
int[] ordinal = { 0 };
list.forEach(s -> {
s.setOrdinal(ordinal[0]++);
});
Note: be very careful if you use a parallel stream. You might not end up with the expected result. Other solutions like Stuart's might be more adapted for those cases.
For types other than int
Of course, this is still valid for types other than int.
For instance, with Java 10+:
var wrapper = new Object(){ String value = ""; };
list.forEach(s->{
wrapper.value += "blah";
});
Or if you're stuck with Java 8 or 9, use the same kind of construct as we did above, but with an AtomicReference...
AtomicReference<String> value = new AtomicReference<>("");
list.forEach(s -> {
value.set(value.get() + s);
});
... or an array:
String[] value = { "" };
list.forEach(s-> {
value[0] += s;
});
This is fairly close to an XY problem. That is, the question being asked is essentially how to mutate a captured local variable from a lambda. But the actual task at hand is how to number the elements of a list.
In my experience, upward of 80% of the time there is a question of how to mutate a captured local from within a lambda, there's a better way to proceed. Usually this involves reduction, but in this case the technique of running a stream over the list indexes applies well:
IntStream.range(0, list.size())
.forEach(i -> list.get(i).setOrdinal(i));
java - Lambdas: local variables need final, instance variables don't - Stack Overflow
Why can't lambda expressions access local or non static variables?
Java 11: Local-Variable Syntax for Lambda Parameters - applications - Stack Overflow
java - Set a local variable value from inside a lambda - Stack Overflow
Videos
The fundamental difference between a field and a local variable is that the local variable is copied when JVM creates a lambda instance. On the other hand, fields can be changed freely, because the changes to them are propagated to the outside class instance as well (their scope is the whole outside class, as Boris pointed out below).
The easiest way of thinking about anonymous classes, closures and labmdas is from the variable scope perspective; imagine a copy constructor added for all local variables you pass to a closure.
In a document of project lambda, State of the Lambda v4, under Section 7. Variable capture, it is mentioned that:
It is our intent to prohibit capture of mutable local variables. The reason is that idioms like this:
int sum = 0; list.forEach(e -> { sum += e.size(); });are fundamentally serial; it is quite difficult to write lambda bodies like this that do not have race conditions. Unless we are willing to enforce—preferably at compile time—that such a function cannot escape its capturing thread, this feature may well cause more trouble than it solves.
Another thing to note here is, local variables are passed in the constructor of an inner class when you access them inside your inner class, and this won't work with non-final variable because value of non-final variables can be changed after construction.
While in case of an instance variable, the compiler passes a reference of the object and object reference will be used to access instance variables. So, it is not required in case of instance variables.
PS : It is worth mentioning that anonymous classes can access only final local variables (in Java SE 7), while in Java SE 8 you can access effectively final variables also inside lambda as well as inner classes.
Hello fellow java learners,
I am learning java through mooc of University of Helsinki and I am currently learning about streams. It says the following:
"Functions that handle stream elements cannot change values of variables outside of the function. This has to do with how static methods behave - during a method call, there is no access to any variables outside of the method. With functions, the values of variables outside the function can be read, assuming that those values of those variables do not change in the program."
I do not understand why this is the case and how does this correlate to the static functions? Static functions can use for example local variables in main function when it's passed as a parameter. Can anyone eli5? Sorry if this is a stupid question. Thanks in advance!!!!
You have two alternatives here:
- Create an class to have this attribute, so the object from it will be final, but not the instance variables
- Make the variable class scope (be careful with multithreading)
These solutions work, but maybe it's not the best option, so to have some inspiration see: Lambdas: local variables need final, instance variables don't
One solution is to make your variable a final array with one element, and modify the element inside it, like this:
final int[] stringByteArrayLength = {0};
visitIntAttribute("", (IntValue) -> stringByteArrayLength[0] = IntValue);
Although I don't consider it a best practice. I would rather return a new changed value rather than changing it.