separator = " "
average = input()
print average.split(separator)

There is a inbuilt method called split() which will get your job done , you can pass a separator variable to that method indicating the character you want to split upon However the default value is space " " itself , averge.split() would also work fine in your case.

raw_input is your helper here. From documentation -

If the prompt argument is present, it is written to standard output without a trailing newline. The function then reads a line from input, converts it to a string (stripping a trailing newline), and returns that. When EOF is read, EOFError is raised.

So your code will basically look like this.

num_array = list()
num = raw_input("Enter how many elements you want:")
print 'Enter numbers in array: '
for i in range(int(num)):
    n = raw_input("num :")
    num_array.append(int(n))
print 'ARRAY: ',num_array

P.S: I have typed all this free hand. Syntax might be wrong but the methodology is correct. Also one thing to note is that, raw_input does not do any type checking, so you need to be careful...

This list comprehension works equally well on Python2 and Python3

[int(x) for x in "1 2 3 4 5".split()]

str.split() when given no parameters will split on any whitespace

If you know the input is safe (only you provide it), you can just use eval

l = eval(input("bring it on:"))

a better version is ast.literal_eval

l = ast.literal_eval(input("much safer:"))

still in both cases you need to be sure the input is not getting from an un-trusted source

If you can make your input to be a json you have an even safer/better solution:

#possible input: [[["Zamek", 2], ["Polonez", 7], ["Wojska Polskiego", 12], ["S\\u0142owia\\u0144ska", 17], ["Solidarno\\u015bci", 21]], [["Zamek", 10], ["Polonez", 15], ["Wojska Polskiego", 21], ["S\\u0142owia\\u0144ska", 24], ["Solidarno\\u015bci", 28]], [["Zamek", 17], ["Polonez", 22], ["Wojska Polskiego", 29], ["S\\u0142owia\\u0144ska", 32], ["Solidarno\\u015bci", 36]], [["Zamek", 22], ["Polonez", 30], ["Wojska Polskiego", 37], ["S\\u0142owia\\u0144ska", 40], ["Solidarno\\u015bci", 45]]]
l = json.loads(input("please provide it in json format..."))

Try this:

for i in range(4):
    array.append(input("Enter string >>"))

Since your array doesn't have any values yet, assigning to array[i] would not work.

You can modify your function to look like this:

string = input("Input here:")
def token(string):
    start, i = 0, 0
    token_list = []
    for x in range(0, len(string)):
        if " " == string[i:i+1]:
            token_list.append(string[start:i+1])
            start = i + 1
        i += 1
    token_list.append(string[start:i+1])
    return token_list
    
print token(string)

You need to append only up until i if you don't want to include the trailing space. The second append is necessary because your condition is checking for a space to include the word, but the last word won't have a trailing space, and instead would have an end of line character or null.

No-package solution

You can use the eval function:

list = eval('["Foo", "Bar", "Baz", "Woo"]')
print (list)

# ['Foo', 'Bar', 'Baz', 'Woo']

Alternative solution

Based on baptx's comment, an alternative way (probably a better one) is to use the ast package:

from ast import literal_eval

list = literal_eval('["Foo", "Bar", "Baz", "Woo"]')
print (list)

# ['Foo', 'Bar', 'Baz', 'Woo']