You can use Apache Commons IO to handle this and similar tasks.
The IOUtils type has a static method to read an InputStream and return a byte[].
InputStream is;
byte[] bytes = IOUtils.toByteArray(is);
Internally this creates a ByteArrayOutputStream and copies the bytes to the output, then calls toByteArray(). It handles large files by copying the bytes in blocks of 4KiB.
You can use Apache Commons IO to handle this and similar tasks.
The IOUtils type has a static method to read an InputStream and return a byte[].
InputStream is;
byte[] bytes = IOUtils.toByteArray(is);
Internally this creates a ByteArrayOutputStream and copies the bytes to the output, then calls toByteArray(). It handles large files by copying the bytes in blocks of 4KiB.
You need to read each byte from your InputStream and write it to a ByteArrayOutputStream.
You can then retrieve the underlying byte array by calling toByteArray():
InputStream is = ...
ByteArrayOutputStream buffer = new ByteArrayOutputStream();
int nRead;
byte[] data = new byte[16384];
while ((nRead = is.read(data, 0, data.length)) != -1) {
buffer.write(data, 0, nRead);
}
return buffer.toByteArray();
Videos
Read from input stream and write to a ByteArrayOutputStream, then call its toByteArray() to obtain the byte array.
Create a ByteArrayInputStream around the byte array to read from it.
Here's a quick test:
import java.io.*;
public class Test {
public static void main(String[] arg) throws Throwable {
File f = new File(arg[0]);
InputStream in = new FileInputStream(f);
byte[] buff = new byte[8000];
int bytesRead = 0;
ByteArrayOutputStream bao = new ByteArrayOutputStream();
while((bytesRead = in.read(buff)) != -1) {
bao.write(buff, 0, bytesRead);
}
byte[] data = bao.toByteArray();
ByteArrayInputStream bin = new ByteArrayInputStream(data);
System.out.println(bin.available());
}
}
You can use org.apache.commons.io.IOUtils#toByteArray(java.io.InputStream)
InputStream is = getMyInputStream();
ByteArrayInputStream bais = new ByteArrayInputStream(IOUtils.toByteArray(is));