First of all, we can store instances of classes that implements a particular interface in an interface reference variable like this.

package com.test;

public class Test implements Testable {

    public static void main(String[] args) {

        Testable testable = new Test();

        // OR

        Test test = new Test();

        if (testeable instanceof Testable)
            System.out.println("instanceof succeeded");
        if (test instanceof Testable)
            System.out.println("instanceof succeeded");
    }
}

interface Testable {

}

ie, any runtime instance that implements a particular interface will pass the instanceof test

EDIT

and the output

instanceof succeeded
instanceof succeeded

@RohitJain

You can create instances of interfaces by using anonymous inner classes like this

Runnable runnable = new Runnable() {
    
    public void run() {
        System.out.println("inside run");
    }
};

and you test the instance is of type interface, using instanceof operator like this

System.out.println(runnable instanceof Runnable);

and the result is 'true'

You can never instantiate an interface in java. You can, however, refer to an object that implements an interface by the type of the interface. For example,

public interface A
{
}
public class B implements A
{
}

public static void main(String[] args)
{
    A test = new B();
    //A test = new A(); // wont compile
}

What you did above was create an Anonymous class that implements the interface. You are creating an Anonymous object, not an object of type interface Test.