Try the following:
int[][] multi = new int[5][10];
... which is a short hand for something like this:
int[][] multi = new int[5][];
multi[0] = new int[10];
multi[1] = new int[10];
multi[2] = new int[10];
multi[3] = new int[10];
multi[4] = new int[10];
Note that every element will be initialized to the default value for int, 0, so the above are also equivalent to:
int[][] multi = new int[][] {
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }
};
... or, more succinctly,
int[][] multi = {
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }
};
Answer from obataku on Stack OverflowSyntax for creating a two-dimensional array in Java - Stack Overflow
Initialization of 2D Array in Java? - Stack Overflow
java - Explicitly assigning values to a 2D Array? - Stack Overflow
2d array initialization in java - Stack Overflow
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Try the following:
int[][] multi = new int[5][10];
... which is a short hand for something like this:
int[][] multi = new int[5][];
multi[0] = new int[10];
multi[1] = new int[10];
multi[2] = new int[10];
multi[3] = new int[10];
multi[4] = new int[10];
Note that every element will be initialized to the default value for int, 0, so the above are also equivalent to:
int[][] multi = new int[][] {
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }
};
... or, more succinctly,
int[][] multi = {
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }
};
We can declare a two dimensional array and directly store elements at the time of its declaration as:
int marks[][]={{50,60,55,67,70},{62,65,70,70,81},{72,66,77,80,69}};
Here int represents integer type elements stored into the array and the array name is 'marks'. int is the datatype for all the elements represented inside the "{" and "}" braces because an array is a collection of elements having the same data type.
Coming back to our statement written above: each row of elements should be written inside the curly braces. The rows and the elements in each row should be separated by a commas.
Now observe the statement: you can get there are 3 rows and 5 columns, so the JVM creates 3 * 5 = 15 blocks of memory. These blocks can be individually referred ta as:
marks[0][0] marks[0][1] marks[0][2] marks[0][3] marks[0][4]
marks[1][0] marks[1][1] marks[1][2] marks[1][3] marks[1][4]
marks[2][0] marks[2][1] marks[2][2] marks[2][3] marks[2][4]
NOTE:
If you want to store n elements then the array index starts from zero and ends at n-1.
Another way of creating a two dimensional array is by declaring the array first and then allotting memory for it by using new operator.
int marks[][]; // declare marks array
marks = new int[3][5]; // allocate memory for storing 15 elements
By combining the above two we can write:
int marks[][] = new int[3][5];
The best way is probably to just declare and assign all values at once. As shown here. Java will automatically figure out what size the array is and assign the values to like this.
int contents[][] = { {1, 2} , { 4, 5} };
Alternatively if you need to declare the array first, remember that each contents[0][0] points to a single integer value not an array of two. So to get the same assignment as above you would write:
contents[0][0] = 1;
contents[0][1] = 2;
contents[1][0] = 4;
contents[1][1] = 5;
Finally I should note that 2 by 2 array is index from 0 to 1 not 0 to 2.
Hope that helps.
Are you looking to assign all values in a 2D array at declaration time? If so, it works as follows:
int[][] contents = new int[][]{ {1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
Remember that a 2D array in Java is really an array of arrays, but Java gives you some special syntax if you do this at declaration time.