You need to read each byte from your InputStream and write it to a ByteArrayOutputStream.

You can then retrieve the underlying byte array by calling toByteArray():

InputStream is = ...
ByteArrayOutputStream buffer = new ByteArrayOutputStream();

int nRead;
byte[] data = new byte[16384];

while ((nRead = is.read(data, 0, data.length)) != -1) {
  buffer.write(data, 0, nRead);
}

return buffer.toByteArray();

You can use the good old read method like this:

   public static byte[] readAllBytes(InputStream inputStream) throws IOException {
    final int bufLen = 1024;
    byte[] buf = new byte[bufLen];
    int readLen;
    IOException exception = null;

    try {
        ByteArrayOutputStream outputStream = new ByteArrayOutputStream();

        while ((readLen = inputStream.read(buf, 0, bufLen)) != -1)
            outputStream.write(buf, 0, readLen);

        return outputStream.toByteArray();
    } catch (IOException e) {
        exception = e;
        throw e;
    } finally {
        if (exception == null) inputStream.close();
        else try {
            inputStream.close();
        } catch (IOException e) {
            exception.addSuppressed(e);
        }
    }
}

The below code worked for me.

URL url = MyClass.class.getResource("/" + configFileName);
BufferedInputStream bi = (BufferedInputStream) url.getContent();
byte[] buffer = new byte[bi.available() ];
int bytesRead = bi.read(buffer);
String out = new String(buffer);

Please note, according to Java docs, the available() method might not work with InputStream but always works with BufferedInputStream. In case you don't want to use available() method we can always use the below code

URL url = MyClass.class.getResource("/" + configFileName);
BufferedInputStream bi = (BufferedInputStream) url.getContent();
File f = new File(url.getPath());
byte[] buffer = new byte[ (int) f.length()];
int bytesRead = bi.read(buffer);
String out = new String(buffer);

I am not sure if there will be any encoding issues. Please comment, if there will be any issues with the code.