I’m on my phone so I’ll just explain what im thinking in pseudo code, but why don’t you just do something like: Create a new array of size n-1 where n is the size of the original array. Iterate over the old array in a for loop, adding each element to the new array. If the element at the ith position equals the element to remove, continue to the next iteration. Would that work? EDIT: I'm at my PC now so here's the code. I ended up doing it a little differently than I mentioned above. Note that it doesn't account for if the element appears multiple times in the array or when the element does not exist. public static void main(String []args) { int[] myArray = { 5,6,9,4 }; int[] newArray = removeElem(myArray, 9); for (int i = 0; i < newArray.length; i++) System.out.print(newArray[i] + " "); } public static int[] removeElem(int[] array, int value) { int index = -1; // First confirm the element to remove exists in the array for (int i = 0; i < array.length; i++) { // If it does, store its index if (array[i] == value) index = i; } // If element exists if (index != -1) { int[] newArray = new int[array.length - 1]; for (int i = 0; i < array.length; i ++) { if (i < index) newArray[i] = array[i]; else if (i > index) newArray[i - 1] = array[i]; } return newArray; } // Do some error handling for if the element does not exist else return array; } Output is: 5 6 4 More on reddit.com

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