There is simpler approach to decode a ByteBuffer into a String without any problems, mentioned by Andy Thomas.
String s = StandardCharsets.UTF_8.decode(byteBuffer).toString();
Answer from xinyong Cheng on Stack OverflowThere is simpler approach to decode a ByteBuffer into a String without any problems, mentioned by Andy Thomas.
String s = StandardCharsets.UTF_8.decode(byteBuffer).toString();
EDIT (2018): The edited sibling answer by @xinyongCheng is a simpler approach, and should be the accepted answer.
Your approach would be reasonable if you knew the bytes are in the platform's default charset. In your example, this is true because k.getBytes() returns the bytes in the platform's default charset.
More frequently, you'll want to specify the encoding. However, there's a simpler way to do that than the question you linked. The String API provides methods that converts between a String and a byte[] array in a particular encoding. These methods suggest using CharsetEncoder/CharsetDecoder "when more control over the decoding [encoding] process is required."
To get the bytes from a String in a particular encoding, you can use a sibling getBytes() method:
byte[] bytes = k.getBytes( StandardCharsets.UTF_8 );
To put bytes with a particular encoding into a String, you can use a different String constructor:
String v = new String( bytes, StandardCharsets.UTF_8 );
Note that ByteBuffer.array() is an optional operation. If you've constructed your ByteBuffer with an array, you can use that array directly. Otherwise, if you want to be safe, use ByteBuffer.get(byte[] dst, int offset, int length) to get bytes from the buffer into a byte array.
ByteBuffer to String
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Hi Guys,
Could anyone please tell me how I can convert a ByteBuffer to a String? I thought it would be a simple function but I can't seem to work it out.
This is just a part of what I have written. I am essentially trying to read a message sent via TCP. There were intermediate steps which I didn't think were necessary to include here.
ServerSocketChannel tcpserver = ServerSocketChannel.open(); SocketChannel connectionSocket = tcpserver.accept(); // create buffer to hold message ByteBuffer buf = ByteBuffer.allocate(48); int bytesRead = connectionSocket.read(buf);
While googling around, there was talk of paying attention to character encoding. Could someone please explain how this factors into the problem at hand?
Any help would be greatly appreciated!!
Kind Regards,
Giri
A way to convert a ByteBuffer to a String would be to use a Charset to decode the bytes:
Charset charset = Charset.forName("ISO-8859-1");
ByteBuffer m_buffer = ...;
String text = charset.decode(m_buffer).toString();
The decoding creates a CharBuffer which you can conveniently convert to a String. You can reuse the CharSet and it is threadsafe. I wouldn't worry too much about performance (re "fastest way") unless you have really a problem in that area. A general advice, when you want to use ByteBuffer, do the to-String conversion as late as possible, and only when the String is needed.
As 14jbella mentioned, Strings are immutable. There is no way of creating a String from an array (char or byte) that does not include copying the data because arrays are mutable. So no, there is no way to do it without copying.
Further you should take into consideration, that m_buffer.array() returns the internal array of the ByteBuffer, which may be much more than the actual data stored in the buffer. Creating a String from that array might lead to a potentially huge memory allocation, because the data gets copied into a new array. For example if you're using a 256 MB ByteBuffer somewhere in your code, and you get a slice() of 32 bytes named m_buffer from that buffer to convert to a String, your invocation of new String(m_buffer.array()) would allocate a new byte array of the size of the original, backing byte array, which is 256 MB, which is probably not that fast, if it requires a GC.
Btw. new String(byte[]) internally uses a CharSet decoder on a ByteBuffer wrapped around your input byte array.
Java's String class is immutable. In order to maintain this guarantee, String has to have its own reference to the char[] backing it, and nobody else may have that reference. If it were to share an array with the ByteBuffer, the String class could not guarantee that it would not be modified. In addition, char, and byte are not the same in Java.
You need to use the buffer's position and limit to determine the number of bytes to read.
// ...populate the buffer...
buffer.flip(); // flip the buffer for reading
byte[] bytes = new byte[buffer.remaining()]; // create a byte array the length of the number of bytes written to the buffer
buffer.get(bytes); // read the bytes that were written
String packet = new String(bytes);
In my opinion you shouldn't really be using the backing array() at all; it's bad practice. Direct byte buffers (created by ByteBuffer.allocateDirect() won't have a backing array and will throw an exception when you try to call ByteBuffer.array(). Because of this, for portability you should try to stick to the standard buffer get and put methods. Of course, if you really want to use the array you can use ByteBuffer.hasArray() to check if the buffer has a backing array.
The answer talking about setting range from position to limit is not correct in a general case. When the buffer has been partially consumed, or is referring to a part of an array (you can ByteBuffer.wrap an array at a given offset, not necessarily from the beginning), we have to account for that in our calculations. This is the general solution that works for buffers in all cases (does not cover encoding):
if (myByteBuffer.hasArray()) {
return new String(myByteBuffer.array(),
myByteBuffer.arrayOffset() + myByteBuffer.position(),
myByteBuffer.remaining());
} else {
final byte[] b = new byte[myByteBuffer.remaining()];
myByteBuffer.duplicate().get(b);
return new String(b);
}
For the concerns related to encoding, see Andy Thomas' answer.
Check out the CharsetEncoder and CharsetDecoder API descriptions - You should follow a specific sequence of method calls to avoid this problem. For example, for CharsetEncoder:
- Reset the encoder via the
resetmethod, unless it has not been used before; - Invoke the
encodemethod zero or more times, as long as additional input may be available, passingfalsefor the endOfInput argument and filling the input buffer and flushing the output buffer between invocations; - Invoke the
encodemethod one final time, passingtruefor the endOfInput argument; and then - Invoke the
flushmethod so that the encoder can flush any internal state to the output buffer.
By the way, this is the same approach I am using for NIO although some of my colleagues are converting each char directly to a byte in the knowledge they are only using ASCII, which I can imagine is probably faster.
Unless things have changed, you're better off with
public static ByteBuffer str_to_bb(String msg, Charset charset){
return ByteBuffer.wrap(msg.getBytes(charset));
}
public static String bb_to_str(ByteBuffer buffer, Charset charset){
byte[] bytes;
if(buffer.hasArray()) {
bytes = buffer.array();
} else {
bytes = new byte[buffer.remaining()];
buffer.get(bytes);
}
return new String(bytes, charset);
}
Usually buffer.hasArray() will be either always true or always false depending on your use case. In practice, unless you really want it to work under any circumstances, it's safe to optimize away the branch you don't need.
You can do something like this:
String val = new String(paramByteBuffer.array());
OR
String val = new String(paramByteBuffer.array(),"UTF-8");
Here is a list of supported charsets
Buffers are a little tricky to use as they have a current state, which you need to take into account when accessing them.
you want to put
paramByteBuffer.flip();
before each decode to get the buffer into the state you want for the decode to read.
e.g.
ByteBuffer paramByteBuffer = ByteBuffer.allocate(100);
paramByteBuffer.put((byte)'a'); // write 'a' at next position(0)
paramByteBuffer.put((byte)'b'); // write 'b' at next position(1)
paramByteBuffer.put((byte)'c'); // write 'c' at next position(2)
// if I try to read now I will read the next byte position(3) which is empty
// so I need to flip the buffer so the next position is at the start
paramByteBuffer.flip();
// we are at position 0 so we can do our read function
CharBuffer charBuffer = StandardCharsets.UTF_8.decode(paramByteBuffer);
String text = charBuffer.toString();
System.out.println("UTF-8" + text);
// because the decoder has read all the written bytes we are back to the
// state (position 3) we had just after we wrote the bytes in the first
// place so we need to flip again
paramByteBuffer.flip();
// we are now at position 0 so we can do our read function
charBuffer = StandardCharsets.UTF_16.decode(paramByteBuffer);
text = charBuffer.toString();
System.out.println("UTF_16"+text);
try {
ByteBuffer bbuf = encoder.encode(CharBuffer.wrap(yourstr));
bbuf.position(0);
bbuf.limit(200);
CharBuffer cbuf = decoder.decode(bbuf);
String s = cbuf.toString();
System.out.println(s);
} catch (CharacterCodingException e) {
}
Which should return chars from the byte buffer starting at 0. byte and ending in 200.
Or rather:
ByteBuffer bbuf = ByteBuffer.wrap(yourstr.getBytes());
bbuf.position(0);
bbuf.limit(200);
byte[] bytearr = new byte[bbuf.remaining()];
bbuf.get(bytearr);
String s = new String(bytearr);
Which does the same but without explicit character decoding/encoding.
Decoding of course does happen in constructor of String s and it is platform dependent, so watch out.
// convert all byteBuffer to string
String fullByteBuffer = new String(byteBuffer.array());
// convert part of byteBuffer to string
byte[] partOfByteBuffer = new byte[PART_LENGTH];
System.arraycopy(fullByteBuffer.array(), 0, partOfByteBuffer, 0, partOfByteBuffer.length);
String partOfByteBufferString = new String(partOfByteBuffer.array());