String.compareTo might or might not be what you need.
Take a look at this link if you need localized ordering of strings.
Answer from Buhb on Stack Overflow Top answer 1 of 9
172
String.compareTo might or might not be what you need.
Take a look at this link if you need localized ordering of strings.
2 of 9
133
Take a look at the String.compareTo method.
Copys1.compareTo(s2)
From the javadocs:
The result is a negative integer if this String object lexicographically precedes the argument string. The result is a positive integer if this String object lexicographically follows the argument string. The result is zero if the strings are equal; compareTo returns 0 exactly when the equals(Object) method would return true.
Delft Stack
delftstack.com › home › howto › java › java compare strings alphabetically
How to Compare Strings Alphabetically in Java | Delft Stack
February 2, 2024 - Python ScipyPythonPython TkinterBatchPowerShellPython PandasNumpyPython FlaskDjangoMatplotlibDockerPlotlySeabornMatlabLinuxGitCCppHTMLJavaScriptjQueryPython PygameTensorFlowTypeScriptAngularReactCSSPHPJavaGoKotlinNode.jsCsharpRustRubyArduinoMySQLMongoDBPostgresSQLiteRVBAScalaRaspberry Pi ... There are several ways to compare two or more strings in Java, but if you want to compare the strings lexicographically (alphabetically), here’s the article for you.
Videos
06:11
JAVA Compare strings alphabetically and sort objects in ArrayList ...
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compareTo() method (Java) - YouTube
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Sorting Strings Alphabetically using compareTo() Method in Java ...
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Compare two strings alphabetically in Java - YouTube
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java , ch5 , use compareTo() method to sort strings in alphabetic ...
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#76 Java String compareTo() Method - YouTube
Reddit
reddit.com › r/learnprogramming › how to compare two strings alphabetically without using "compareto"
How to compare two strings alphabetically without using "compareTo" : r/learnprogramming
November 18, 2017 - When you compare objects with operators ... of the string (turns out relational operators might work on Integer types because of autoboxing and unboxing). https://stackoverflow.com/questions/29179194/compare-two-objects-with-or-operators-in-java More replies More replies ... Yes....it says bad operand. ... Java, not Python ;) You misread ...
W3Schools
w3schools.com › java › ref_string_compareto.asp
Java String compareTo() Method
Tip: Use the equals() method to compare two strings without consideration of Unicode values. ... If you want to use W3Schools services as an educational institution, team or enterprise, send us an e-mail: sales@w3schools.com · If you want to report an error, or if you want to make a suggestion, send us an e-mail: help@w3schools.com · HTML Tutorial CSS Tutorial JavaScript Tutorial How To Tutorial SQL Tutorial Python Tutorial W3.CSS Tutorial Bootstrap Tutorial PHP Tutorial Java Tutorial C++ Tutorial jQuery Tutorial
Coderanch
coderanch.com › t › 702035 › java › compare-strings-find-alphabetically-Java
How to compare two strings and find which is first alphabetically in Java? Built-in Method? (Java in General forum at Coderanch)
If you go through the Java™ Tutorials, you will find lots aout sorting. You might also find that there is a Comparator already provided in the String class for sorting a before B.
Java67
java67.com › 2013 › 08 › best-way-to-compare-two-strings-in-java.html
How to check if two String variables are same in Java? equals(), equalsIgnoreCase() and == operator Example | Java67
Though they are not completely ... Strings alphabetically. When you compare two strings using the == operator, it may or may not return true, especially if you are expecting result based on contents. It will only return true if both reference variables are pointing to the same objects, like in the case of interned string or String literals. Otherwise, it will return false, even if the content of String remain same. It's one of the coding best practice in Java to use equals() ...
Sololearn
sololearn.com › en › Discuss › 1691307 › how-to-know-if-the-first-letter-of-a-string-is-alphabetically-greater-than-the-first-letter-of-another-string
How to know if the first letter of a String is alphabetically greater than the first letter of another String? | Sololearn: Learn to code for FREE!
char character = 'a'; int ascii = (int) character; get the specific Character from the String first and then cast it. char character = name.charAt(0); // This gives the character 'a' int ascii = (int) character; // ascii is now 97. do the next then compare well that how we used to do it lol ... I'm doing java and python but evrebody is saying that nobody uses python is thst true sould I switch language
W3Docs
w3docs.com › java
Comparing strings by their alphabetical order
Here is an example of how to use the compareTo() method to compare two strings:
Jazz Community Site
jazz.net › dxl › html › 1885 - Comparing strings alphabetically.html
Comparing strings alphabetically
This seems like a very basic question to me, but I have not been able to find a clear answer in the dxl reference manual. I am wishing to compare two strings alphabetically. I was thinking about creating a function that uses the ASCII values of each character in the strings to compare them ...
Vultr Docs
docs.vultr.com › java › standard-library › java › lang › String › compareTo
Java String compareTo() - Compare Strings Alphabetically | Vultr Docs
May 15, 2025 - Understanding how to use compareTo() effectively can enhance your ability to handle string manipulation and alphabetical string comparisons in Java applications.
Quora
quora.com › How-do-you-compare-strings-alphabetically-in-Java
How to compare strings alphabetically in Java - Quora
Answer (1 of 3): “German phone book, case‑insensitive, accent‑insensitive, numeric”, using standard Java SE 1.1 java.text.* APIs. [code]import java.text.Collator; import java.text.CollationKey; import java.util.Locale; public class GermanPhonebook { private static final Collator COLLATOR; ...
Quora
quora.com › How-do-you-compare-two-strings-alphabetically-in-Python
How to compare two strings alphabetically in Python - Quora
Answer: Strings are compared according to their order when sorted alphabetically. Understand with the help of code. [code]print "alpha"
Reddit
reddit.com › r/c_programming › how to compare characters in two strings to sort them alphabetically? (without c string library functions)
How to compare characters in two strings to sort them alphabetically? (without c string library functions) : r/C_Programming
July 22, 2014 - In lexicographical comparison lengths of the strings are secondary. In any case, what were you trying to do (even in Java) with this comparison ... How can length[i] possibly be smaller than length[i]-1??? E.g. how can, say, 5 be smaller than 4? ... I made minecraft in C and opengl !!! ... Made the mistake of starting programming with Python ...
Coderanch
coderanch.com › t › 399908 › java › Comparing-character-strings-alphabetically
Comparing two-character strings alphabetically. (Beginning Java forum at Coderanch)
Well, here is one solution: put ... edited by: John Smith ] ... Can your database query just order by this field? Failing that, look at the compareTo() method....
Team Treehouse
teamtreehouse.com › community › how-do-i-compare-by-multiple-things-such-as-length-first-and-then-the-normal-lexical-string-compare
How do I compare by multiple things, such as length first and then the normal lexical string compare? (Example) | Treehouse Community
November 30, 2017 - So, if I want to sort multiple strings, and many of them all have the same length, then I want them to be sorted alphabetically; how do I do that? ... Hey Oindril! I was curious about this too. It looks like Java 8 added the thenComparing() method to the Comparator class.
Coderanch
coderanch.com › t › 640534 › java › Sort-String-list-Alphabetically-compareTo
Sort String list Alphabetically with compareTo method/if else statements, logic errors (Beginning Java forum at Coderanch)
If the comparison fails, then I will continue until I have done it for all the elements · SCJP 1.4, SCWCD 1.4 - Hints for you, Certified Scrum Master Did a rm -R / to find out that I lost my entire Linux installation! ... As you can already see that your solution involves more lines of code for sorting just three Strings and it is not scalable meaning if you input another one, then you have to modify your entire if else.
GeeksforGeeks
geeksforgeeks.org › java › compare-two-strings-lexicographically-in-java
Compare two strings lexicographically in Java - GeeksforGeeks
July 11, 2024 - In this article, we will discuss how we can compare two strings lexicographically in Java. One solution is to use Java compareTo() method. The method compareTo() is used for comparing two strings lexicographically in Java.
Brainly
brainly.com › engineering › college › use the `compareto` method to write code that reads two names from the console and prints the one that comes first in alphabetical order.
for example, the program's output might look like the following:
```
type a name: taylor smith
type a name: marie singer
marie singer goes before taylor smith
```
[FREE] Use the `compareTo` method to write code that reads two names from the console and prints the one that - brainly.com
To compare two names and print the one that comes first in alphabetical order, we can utilize the compareTo method from the String class in Java.
Reddit
reddit.com › r/javahelp › tips for printing two strings in alphabetical order?
r/javahelp on Reddit: Tips for printing two Strings in alphabetical order?
October 23, 2017 -
I'm taking a CS 1 course and we're using Zybooks for some java homework, and I'm stuck on one of the problems. The problem states:
Print the two strings in alphabetical order. Assume the strings are lowercase. End with newline. Sample output:
capes rabbits
I have this so far, and the first test is right, but the second one is wrong. I want to be able to successfully complete all of the "tests"
My code so far:
import java.util.Scanner;
public class OrderStrings {
public static void main (String [] args) {
String firstString;
String secondString;
firstString = "rabbits";
secondString = "capes";
if(secondString != firstString) {
System.out.println(secondString+" "+firstString);
}
else{
System.out.println(firstString+" "+secondString);
}
}
}The first test outputs this
capes rabbits
the output that is wrong displays this for some reason:
your input: rabbits capes
expected output: capes rabbits
why does the second output switch around the Strings?
Everything before the if statement was already made for me by Zybooks.
Top answer 1 of 4
4
the first test is right This is not right. Sometimes you might have the wrong code/logic, but still get the right answer. I think this is a good case in point, of why you need more than just one test (with different words). In your if statement you compare secondString != firstString. All this does is compare if the two String variables point to the same object. You aren't doing any sort of alphabetic comparison. In fact since the two strings are never pointing to the same object, this will always mean they are not equal to each other and you enter the if always. As almost always with such a common function like alphabetic comparison, look at the [Java docs]( https://docs.oracle.com/javase/7/docs/api/java/lang/String.html#compareTo(java.lang.String) ) for the answer
2 of 4
1
Hey you're really close. You'll need to use method compareTo() to finish it. You can find more about that here: https://www.javatpoint.com/java-string-compareto If you'd like the answer, let me know. Best of luck!