Baeldung
baeldung.com › home › json › introduction to json-java (org.json)
Introduction to JSON-Java | Baeldung
June 20, 2025 - One of JSONObject’s constructors takes a POJO as its argument. In the example below, the package uses the getters from the DemoBean class and creates an appropriate JSONObject for the same. To get a JSONObject from a Java Object, we’ll have to use a class that is a valid Java Bean:
DigitalOcean
digitalocean.com › community › tutorials › java-json-example
Java JSON Example | DigitalOcean
August 4, 2022 - Streaming API - It’s similar to StaX Parser and good for large objects where you don’t want to keep whole object in memory. ... javax.json.JsonReader: We can use this to read JSON object or an array to JsonObject.
Videos
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Create Complex Json in Java | Json Object | Json Array In Java ...
A quick tutorial on using JSON-simple parsing JSON ...
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Json Parsing In Java | How to Parse Complex Json in Java | ...
04:28
Java - Mapping objects to JSON - YouTube
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Java Gets a JSON API - Inside Java Newscast #95 - YouTube
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How to convert JSON to Java objects using Gson - YouTube
TutorialsPoint
tutorialspoint.com › json › json_java_example.htm
JSON with Java
The following example makes use of JSONObject and JSONArray where JSONObject is a java.util.Map and JSONArray is a java.util.List, so you can access them with standard operations of Map or List. import org.json.simple.JSONObject; import org.json.simple.JSONArray; import org.json.simple.parser.ParseException; import org.json.simple.parser.JSONParser; class JsonDecodeDemo { public static void main(String[] args) { JSONParser parser = new JSONParser(); String s = "[0,{\"1\":{\"2\":{\"3\":{\"4\":[5,{\"6\":7}]}}}}]"; try{ Object obj = parser.parse(s); JSONArray array = (JSONArray)obj; System.out.pr
Stleary
stleary.github.io › JSON-java › org › json › JSONObject.html
JSONObject
Methods that are static, return void, have parameters, or are "bridge" methods, are ignored. For example, if an object has a method named "getName", and if the result of calling object.getName() is "Larry Fine", then the JSONObject will contain "name": "Larry Fine".
Oracle
docs.oracle.com › javaee › 7 › api › javax › json › JsonObject.html
JsonObject (Java(TM) EE 7 Specification APIs)
This is a convenience method for (JsonObject)get(name) to get the value. ... the object value to which the specified name is mapped, or null if this object contains no mapping for the name
Medium
medium.com › @benpourian › how-to-create-a-java-object-from-a-json-object-c47c08b030c5
How to create a Java Object from a JSON object | by Benjamin Pourian | Medium
October 25, 2018 - This will be a very brief guide to creating a Java object from a JSON object using the popular gson` google library. I will first demonstrate a simple JSON → POJO example then follow that with another example where I will be using annotations provided by gson to instantiate a new object by ...
Oracle
docs.oracle.com › javame › 8.0 › api › json › api › com › oracle › json › JsonObject.html
JsonObject (JSON Documentation)
This is a convenience method for (JsonArray)get(name) to get the value. ... the array value to which the specified name is mapped, or null if this object contains no mapping for the name ... java.lang.ClassCastException - if the value to which the specified name is mapped is not assignable ...
CodeSignal
codesignal.com › learn › courses › handling-json-files-with-java › lessons › creating-and-writing-json-data-with-java-using-jackson
Creating and Writing JSON Data with Java
In order to have more control over the JSON structure, you can use the @JsonProperty annotation is directly above the fields to specify how Java fields are mapped to JSON keys during serialization. The Participant class holds details about each event participant, including their name and project, with @JsonProperty ensuring these fields are translated the way we want into JSON properties. The Event class includes general event information such as the event name and date, along with a collection of Participant objects.
Baeldung
baeldung.com › home › json › getting a value in jsonobject
Getting a Value in JSONObject | Baeldung
May 5, 2025 - For the general introduction to ... to JSON-Java. JSONObject is a map-like structure. It keeps its data as a set of key-value pairs. While the keys are of the String type, the values may be of several types. Additionally, the value types may be primitive or compound. Primitives are String, Number, and Boolean types, or JSONObject.NULL object...
Javatpoint
javatpoint.com › java-json-example
Java JSON Example
Java JSON example for beginners and professionals with examples of JSON with java, install json.simple, java json encode, java json encode using map, java json array encode, java json array encode using List, java json decode. Learn Java JSON example with array, object, schema, encode, decode, file, date etc.
Top answer 1 of 6
39
Google GSON does this; I've used it on several projects and it's simple and works well. It can do the translation for simple objects with no intervention, but there's a mechanism for customizing the translation (in both directions,) as well.
Gson g = ...;
String jsonString = g.toJson(new Customer());
2 of 6
21
You can use Gson for that:
Maven dependency:
<dependency>
<groupId>com.google.code.gson</groupId>
<artifactId>gson</artifactId>
<version>2.8.0</version>
</dependency>
Java code:
Customer customer = new Customer();
Product product = new Product();
// Set your values ...
Gson gson = new Gson();
String json = gson.toJson(customer);
Customer deserialized = gson.fromJson(json, Customer.class);
Oracle
docs.oracle.com › javaee › 7 › tutorial › jsonp001.htm
19.1 Introduction to JSON - Java Platform, Enterprise Edition: The Java EE Tutorial (Release 7)
JSON is a text-based data exchange format derived from JavaScript that is used in web services and other connected applications. The following sections provide an introduction to JSON syntax, an overview of JSON uses, and a description of the most common approaches to generate and parse JSON. JSON defines only two data structures: objects ...
Android Developers
developer.android.com › api reference › jsonobject
JSONObject | API reference | Android Developers
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Coderanch
coderanch.com › t › 706235 › java › Identifying-JSONObject-JSONArray
Identifying JSONObject or JSONArray (Java in General forum at Coderanch)
February 12, 2019 - Here are partial examples: This is the normal string that works: This is the response that causes the parser exception: ... Sam Ritter wrote:... is there a way to determine which sb is before running the parser? The easiest way is probably to use the parser to determine if JSON element is what you are expecting - as you have found, it will throw an exception if it is the wrong type of element.
Processing
processing.github.io › processing-javadocs › core › processing › data › JSONObject.html
JSONObject
This is the most commonly used JSONObject constructor. ... Get the value object associated with a key. ... The object associated with the key. ... A string which is the value. ... Get an optional string associated with a key. It returns the defaultValue if there is no such key. ... A string which is the value. ... The integer value. ... java.lang.RuntimeException - if the key is not found or if the value cannot be converted to an integer.
Top answer 1 of 6
266
org.json.JSONArray may be what you want.
String message;
JSONObject json = new JSONObject();
json.put("name", "student");
JSONArray array = new JSONArray();
JSONObject item = new JSONObject();
item.put("information", "test");
item.put("id", 3);
item.put("name", "course1");
array.put(item);
json.put("course", array);
message = json.toString();
// message
// {"course":[{"id":3,"information":"test","name":"course1"}],"name":"student"}
2 of 6
13
In contrast to what the accepted answer proposes, the documentation says that for JSONArray() you must use put(value) no add(value).
https://developer.android.com/reference/org/json/JSONArray.html#put(java.lang.Object)
(Android API 19-27. Kotlin 1.2.50)