You can use File#isDirectory() to test if the given file (path) is a directory. If this is true, then you just call the same method again with its File#listFiles() outcome. This is called recursion.
Here's a basic kickoff example:
package com.stackoverflow.q3154488;
import java.io.File;
public class Demo {
public static void main(String... args) {
File dir = new File("/path/to/dir");
showFiles(dir.listFiles());
}
public static void showFiles(File[] files) {
for (File file : files) {
if (file.isDirectory()) {
System.out.println("Directory: " + file.getAbsolutePath());
showFiles(file.listFiles()); // Calls same method again.
} else {
System.out.println("File: " + file.getAbsolutePath());
}
}
}
}
Note that this is sensitive to StackOverflowError when the tree is deeper than the JVM's stack can hold. If you're already on Java 8 or newer, then you'd better use Files#walk() instead which utilizes tail recursion:
package com.stackoverflow.q3154488;
import java.io.File;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
public class DemoWithJava8 {
public static void main(String... args) throws Exception {
Path dir = Paths.get("/path/to/dir");
Files.walk(dir).forEach(path -> showFile(path.toFile()));
}
public static void showFile(File file) {
if (file.isDirectory()) {
System.out.println("Directory: " + file.getAbsolutePath());
} else {
System.out.println("File: " + file.getAbsolutePath());
}
}
}
Answer from BalusC on Stack OverflowYou can use File#isDirectory() to test if the given file (path) is a directory. If this is true, then you just call the same method again with its File#listFiles() outcome. This is called recursion.
Here's a basic kickoff example:
package com.stackoverflow.q3154488;
import java.io.File;
public class Demo {
public static void main(String... args) {
File dir = new File("/path/to/dir");
showFiles(dir.listFiles());
}
public static void showFiles(File[] files) {
for (File file : files) {
if (file.isDirectory()) {
System.out.println("Directory: " + file.getAbsolutePath());
showFiles(file.listFiles()); // Calls same method again.
} else {
System.out.println("File: " + file.getAbsolutePath());
}
}
}
}
Note that this is sensitive to StackOverflowError when the tree is deeper than the JVM's stack can hold. If you're already on Java 8 or newer, then you'd better use Files#walk() instead which utilizes tail recursion:
package com.stackoverflow.q3154488;
import java.io.File;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
public class DemoWithJava8 {
public static void main(String... args) throws Exception {
Path dir = Paths.get("/path/to/dir");
Files.walk(dir).forEach(path -> showFile(path.toFile()));
}
public static void showFile(File file) {
if (file.isDirectory()) {
System.out.println("Directory: " + file.getAbsolutePath());
} else {
System.out.println("File: " + file.getAbsolutePath());
}
}
}
If you are using Java 1.7, you can use java.nio.file.Files.walkFileTree(...).
For example:
public class WalkFileTreeExample {
public static void main(String[] args) {
Path p = Paths.get("/usr");
FileVisitor<Path> fv = new SimpleFileVisitor<Path>() {
@Override
public FileVisitResult visitFile(Path file, BasicFileAttributes attrs)
throws IOException {
System.out.println(file);
return FileVisitResult.CONTINUE;
}
};
try {
Files.walkFileTree(p, fv);
} catch (IOException e) {
e.printStackTrace();
}
}
}
If you are using Java 8, you can use the stream interface with java.nio.file.Files.walk(...):
public class WalkFileTreeExample {
public static void main(String[] args) {
try (Stream<Path> paths = Files.walk(Paths.get("/usr"))) {
paths.forEach(System.out::println);
} catch (IOException e) {
e.printStackTrace();
}
}
}
List and iterate over sub-directories
How to iterate over the files of a certain directory, in Java? - Stack Overflow
loops - Java Basics - Looping through folder - Stack Overflow
file - Iterating through a directory in java - Stack Overflow
If you have the directory name in myDirectoryPath,
import java.io.File;
...
File dir = new File(myDirectoryPath);
File[] directoryListing = dir.listFiles();
if (directoryListing != null) {
for (File child : directoryListing) {
// Do something with child
}
} else {
// Handle the case where dir is not really a directory.
// Checking dir.isDirectory() above would not be sufficient
// to avoid race conditions with another process that deletes
// directories.
}
I guess there are so many ways to make what you want. Here's a way that I use. With the commons.io library you can iterate over the files in a directory. You must use the FileUtils.iterateFiles method and you can process each file.
You can find the information here: http://commons.apache.org/proper/commons-io/download_io.cgi
Here's an example:
Iterator it = FileUtils.iterateFiles(new File("C:/"), null, false);
while(it.hasNext()){
System.out.println(((File) it.next()).getName());
}
You can change null and put a list of extentions if you wanna filter. Example: {".xml",".java"}
The answer is in this article: http://www.baeldung.com/java-compress-and-uncompress
This code zips multiple files (Very similar to your code but slightly changed):
public class ZipMultipleFiles {
public static void main(String[] args) throws IOException {
List<String> srcFiles = Arrays.asList("test1.txt", "test2.txt");
FileOutputStream fos = new FileOutputStream("multiCompressed.zip");
ZipOutputStream zipOut = new ZipOutputStream(fos);
for (String srcFile : srcFiles) {
File fileToZip = new File(srcFile);
FileInputStream fis = new FileInputStream(fileToZip);
ZipEntry zipEntry = new ZipEntry(fileToZip.getName());
zipOut.putNextEntry(zipEntry);
byte[] bytes = new byte[1024];
int length;
while((length = fis.read(bytes)) >= 0) {
zipOut.write(bytes, 0, length);
}
fis.close();
}
zipOut.close();
fos.close();
}
}
EDIT:
This line in the code creates an array that is easy to go through in a while loop:
List<String> srcFiles = Arrays.asList("test1.txt", "test2.txt");
basically used finding children of a folder method thanks to Elliotk link. I am making the string equal to the path of the parent folder - >checking if whether if its a directory - > list its files -> get the names and while loop to write all of them to a zipped folder
here is my whole code
package zipfolder2;
import java.io.*;
import java.util.*;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class zipfolders2 {
public static void main(String[] args) {
try {
String sourceFile = "src/resources";
FileOutputStream fos = new FileOutputStream("zippedfiles.zip");
ZipOutputStream zipOut = new ZipOutputStream(fos);
File fileToZip = new File(sourceFile);
zipFile(fileToZip, fileToZip.getName(), zipOut);
zipOut.close();
fos.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
private static void zipFile(File fileToZip, String fileName, ZipOutputStream zipOut) throws IOException {
if (fileToZip.isHidden()) {
return;
}
if (fileToZip.isDirectory()) {
File[] children = fileToZip.listFiles();
for (File childFile : children) {
zipFile(childFile, fileName + "/" + childFile.getName(), zipOut);
}
return;
}
FileInputStream fis = new FileInputStream(fileToZip);
ZipEntry zipEntry = new ZipEntry(fileName);
zipOut.putNextEntry(zipEntry);
byte[] bytes = new byte[1024];
int length;
while ((length = fis.read(bytes)) >= 0) {
zipOut.write(bytes, 0, length);
}
fis.close();
}
}
If you are using Java 7, then you need to take a look at NIO.2.
Specifically, take a look at the Listing a Directory's Contents section.
Path dir = Paths.get("/directory/path");
try (DirectoryStream<Path> stream = Files.newDirectoryStream(dir)) {
for (Path file: stream) {
getDoubleByteArrayOfFile(file.getFileName(), someRegion);
}
} catch (IOException | DirectoryIteratorException x) {
// IOException can never be thrown by the iteration.
// In this snippet, it can only be thrown by newDirectoryStream.
System.err.println(x);
}
Here is a quick example that may help:
private ArrayList<byte[][]> getDoubleByteArrayOfDirectory(String dirName,
Region region) throws IOException {
ArrayList<byte[][]> results = new ArrayList<byte[][]>();
File directory = new File(dirName);
if (!directory.isDirectory()) return null //or handle however you wish
for (File file : directory.listFiles()) {
results.add(getDoubleByteArrayOfFile(file.getName()), region);
}
return results;
}
Not exactly what you asked for since it's wrapping your old method rather than re-writing it, but I find it a bit cleaner this way, and leaves you with the option of still processing a single file. Be sure to tweak the return type and how to handle the region based on your actual requirements (hard to tell from the question).
Iโm not 100% solid on how JAD works exactly, but based on the info I found in this README file, this find command should give you a start:
find . -type f -name '*.class' |\
while IFS= read -r java_class_path
do
java_dirname=$(dirname "${java_class_path}")
jad -sjava -d"${java_dirname}" "${java_class_path}"
done
The -s option will set the output extension to .java and the -d sets a destination directory for file output based on where the original .class file was found via find. The key to solving problems like this is to understand you are not the first person who wanted to output command line output to another destination.
jad has support for this built-in, according to the documentation. It will expand globs for you, including ** recursive globs. So use quotes to protect them from the shell, like this example cmd copied from the docs:
jad -o -r -sjava -dsrc 'tree/**/*.class'
This command decompiles all .class files located in all subdirectories of
treeand creates output files in subdirectories ofsrcaccording to package names of classes. For example, if filetree/a/b/c.classcontains classcfrom packagea.b, then output file will have a namesrc/a/b/c.java.
This is almost certainly the best option if you like its choices of directory structure. I looks like without -r it won't turn package structure into directories. IDK if you could get it to put the .java files next to the the .class files with your directory structure.
Using find -execdir to run jad in the right directory:
# untested
find [more find options] -name '*.class' -execdir jad {} +
This will effectively cd to every directory that contains at least one .class, and do the equivalent of running jad *.class there. (Note the + instead of \; to group multiple args into one command).
GNU find is powerful; read the man page.
Or use bash features:
Since you're using bash, you can make for dir in ./* recursive with bash's globstar feature. It's significantly slower than find for big directory trees, because it bash doesn't know to take advantage of the file-type hint returned by readdir to avoid having to lstat every dir entry to see if it's a directory. But bash recursive globs can be useful.
# untested
shopt -s globstar # put this in your .bashrc if you want it enabled all the time
for dir in ./**/; do
pushd "$dir"
classfiles=( *.class ) # expand the glob into an array
[[ -e $classfiles ]] && # test the first element of the array. Will fail if *.class didn't match anything.
jad *.class
popd "$dir"
done
Note the use of a trailing slash to make the glob match only directories.