You can use File#isDirectory() to test if the given file (path) is a directory. If this is true, then you just call the same method again with its File#listFiles() outcome. This is called recursion.
Here's a basic kickoff example:
package com.stackoverflow.q3154488;
import java.io.File;
public class Demo {
public static void main(String... args) {
File dir = new File("/path/to/dir");
showFiles(dir.listFiles());
}
public static void showFiles(File[] files) {
for (File file : files) {
if (file.isDirectory()) {
System.out.println("Directory: " + file.getAbsolutePath());
showFiles(file.listFiles()); // Calls same method again.
} else {
System.out.println("File: " + file.getAbsolutePath());
}
}
}
}
Note that this is sensitive to StackOverflowError when the tree is deeper than the JVM's stack can hold. If you're already on Java 8 or newer, then you'd better use Files#walk() instead which utilizes tail recursion:
package com.stackoverflow.q3154488;
import java.io.File;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
public class DemoWithJava8 {
public static void main(String... args) throws Exception {
Path dir = Paths.get("/path/to/dir");
Files.walk(dir).forEach(path -> showFile(path.toFile()));
}
public static void showFile(File file) {
if (file.isDirectory()) {
System.out.println("Directory: " + file.getAbsolutePath());
} else {
System.out.println("File: " + file.getAbsolutePath());
}
}
}
Answer from BalusC on Stack OverflowYou can use File#isDirectory() to test if the given file (path) is a directory. If this is true, then you just call the same method again with its File#listFiles() outcome. This is called recursion.
Here's a basic kickoff example:
package com.stackoverflow.q3154488;
import java.io.File;
public class Demo {
public static void main(String... args) {
File dir = new File("/path/to/dir");
showFiles(dir.listFiles());
}
public static void showFiles(File[] files) {
for (File file : files) {
if (file.isDirectory()) {
System.out.println("Directory: " + file.getAbsolutePath());
showFiles(file.listFiles()); // Calls same method again.
} else {
System.out.println("File: " + file.getAbsolutePath());
}
}
}
}
Note that this is sensitive to StackOverflowError when the tree is deeper than the JVM's stack can hold. If you're already on Java 8 or newer, then you'd better use Files#walk() instead which utilizes tail recursion:
package com.stackoverflow.q3154488;
import java.io.File;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
public class DemoWithJava8 {
public static void main(String... args) throws Exception {
Path dir = Paths.get("/path/to/dir");
Files.walk(dir).forEach(path -> showFile(path.toFile()));
}
public static void showFile(File file) {
if (file.isDirectory()) {
System.out.println("Directory: " + file.getAbsolutePath());
} else {
System.out.println("File: " + file.getAbsolutePath());
}
}
}
If you are using Java 1.7, you can use java.nio.file.Files.walkFileTree(...).
For example:
public class WalkFileTreeExample {
public static void main(String[] args) {
Path p = Paths.get("/usr");
FileVisitor<Path> fv = new SimpleFileVisitor<Path>() {
@Override
public FileVisitResult visitFile(Path file, BasicFileAttributes attrs)
throws IOException {
System.out.println(file);
return FileVisitResult.CONTINUE;
}
};
try {
Files.walkFileTree(p, fv);
} catch (IOException e) {
e.printStackTrace();
}
}
}
If you are using Java 8, you can use the stream interface with java.nio.file.Files.walk(...):
public class WalkFileTreeExample {
public static void main(String[] args) {
try (Stream<Path> paths = Files.walk(Paths.get("/usr"))) {
paths.forEach(System.out::println);
} catch (IOException e) {
e.printStackTrace();
}
}
}
List and iterate over sub-directories
How to iterate over the files of a certain directory, in Java? - Stack Overflow
loops - Java Basics - Looping through folder - Stack Overflow
How to loop through a directory, get all file names, then get the contents of those files in Java - Stack Overflow
If you have the directory name in myDirectoryPath,
import java.io.File;
...
File dir = new File(myDirectoryPath);
File[] directoryListing = dir.listFiles();
if (directoryListing != null) {
for (File child : directoryListing) {
// Do something with child
}
} else {
// Handle the case where dir is not really a directory.
// Checking dir.isDirectory() above would not be sufficient
// to avoid race conditions with another process that deletes
// directories.
}
I guess there are so many ways to make what you want. Here's a way that I use. With the commons.io library you can iterate over the files in a directory. You must use the FileUtils.iterateFiles method and you can process each file.
You can find the information here: http://commons.apache.org/proper/commons-io/download_io.cgi
Here's an example:
Iterator it = FileUtils.iterateFiles(new File("C:/"), null, false);
while(it.hasNext()){
System.out.println(((File) it.next()).getName());
}
You can change null and put a list of extentions if you wanna filter. Example: {".xml",".java"}
The answer is in this article: http://www.baeldung.com/java-compress-and-uncompress
This code zips multiple files (Very similar to your code but slightly changed):
public class ZipMultipleFiles {
public static void main(String[] args) throws IOException {
List<String> srcFiles = Arrays.asList("test1.txt", "test2.txt");
FileOutputStream fos = new FileOutputStream("multiCompressed.zip");
ZipOutputStream zipOut = new ZipOutputStream(fos);
for (String srcFile : srcFiles) {
File fileToZip = new File(srcFile);
FileInputStream fis = new FileInputStream(fileToZip);
ZipEntry zipEntry = new ZipEntry(fileToZip.getName());
zipOut.putNextEntry(zipEntry);
byte[] bytes = new byte[1024];
int length;
while((length = fis.read(bytes)) >= 0) {
zipOut.write(bytes, 0, length);
}
fis.close();
}
zipOut.close();
fos.close();
}
}
EDIT:
This line in the code creates an array that is easy to go through in a while loop:
List<String> srcFiles = Arrays.asList("test1.txt", "test2.txt");
basically used finding children of a folder method thanks to Elliotk link. I am making the string equal to the path of the parent folder - >checking if whether if its a directory - > list its files -> get the names and while loop to write all of them to a zipped folder
here is my whole code
package zipfolder2;
import java.io.*;
import java.util.*;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class zipfolders2 {
public static void main(String[] args) {
try {
String sourceFile = "src/resources";
FileOutputStream fos = new FileOutputStream("zippedfiles.zip");
ZipOutputStream zipOut = new ZipOutputStream(fos);
File fileToZip = new File(sourceFile);
zipFile(fileToZip, fileToZip.getName(), zipOut);
zipOut.close();
fos.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
private static void zipFile(File fileToZip, String fileName, ZipOutputStream zipOut) throws IOException {
if (fileToZip.isHidden()) {
return;
}
if (fileToZip.isDirectory()) {
File[] children = fileToZip.listFiles();
for (File childFile : children) {
zipFile(childFile, fileName + "/" + childFile.getName(), zipOut);
}
return;
}
FileInputStream fis = new FileInputStream(fileToZip);
ZipEntry zipEntry = new ZipEntry(fileName);
zipOut.putNextEntry(zipEntry);
byte[] bytes = new byte[1024];
int length;
while ((length = fis.read(bytes)) >= 0) {
zipOut.write(bytes, 0, length);
}
fis.close();
}
}