No, there is no better way.
Actually you have an error in your pattern. What you want is:
DecimalFormat df = new DecimalFormat("#.00");
Note the "00", meaning exactly two decimal places.
If you use "#.##" (# means "optional" digit), it will drop trailing zeroes - ie new DecimalFormat("#.##").format(3.0d); prints just "3", not "3.00".
No, there is no better way.
Actually you have an error in your pattern. What you want is:
DecimalFormat df = new DecimalFormat("#.00");
Note the "00", meaning exactly two decimal places.
If you use "#.##" (# means "optional" digit), it will drop trailing zeroes - ie new DecimalFormat("#.##").format(3.0d); prints just "3", not "3.00".
An alternative is to use String.format:
double[] arr = { 23.59004,
35.7,
3.0,
9
};
for ( double dub : arr ) {
System.out.println( String.format( "%.2f", dub ) );
}
output:
23.59
35.70
3.00
9.00
You could also use System.out.format (same method signature), or create a java.util.Formatter which works in the same way.
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One of the way would be using NumberFormat.
NumberFormat formatter = new DecimalFormat("#0.00");
System.out.println(formatter.format(4.0));
Output:
4.00
With Java 8, you can use format method..: -
System.out.format("%.2f", 4.0); // OR
System.out.printf("%.2f", 4.0);
fis used forfloatingpoint value..2after decimal denotes, number of decimal places after.
For most Java versions, you can use DecimalFormat: -
DecimalFormat formatter = new DecimalFormat("#0.00");
double d = 4.0;
System.out.println(formatter.format(d));
try this new DecimalFormat("#.00");
update:
double angle = 20.3034;
DecimalFormat df = new DecimalFormat("#.00");
String angleFormated = df.format(angle);
System.out.println(angleFormated); //output 20.30
Your code wasn't using the decimalformat correctly
The 0 in the pattern means an obligatory digit, the # means optional digit.
update 2: check bellow answer
If you want 0.2677 formatted as 0.27 you should use new DecimalFormat("0.00"); otherwise it will be .27
DecimalFormat df=new DecimalFormat("0.00");
Use this code to get exact two decimal points. Even if the value is 0.0 it will give u 0.00 as output.
Instead if you use:
DecimalFormat df=new DecimalFormat("#.00");
It wont convert 0.2659 into 0.27. You will get an answer like .27.
You can use the printf method, like so:
System.out.printf("%.2f", val);
In short, the %.2f syntax tells Java to return your variable (val) with 2 decimal places (.2) in decimal representation of a floating-point number (f) from the start of the format specifier (%).
There are other conversion characters you can use besides f:
d: decimal integero: octal integere: floating-point in scientific notation
You can use DecimalFormat. One way to use it:
DecimalFormat df = new DecimalFormat();
df.setMaximumFractionDigits(2);
System.out.println(df.format(decimalNumber));
Another one is to construct it using the #.## format.
I find all formatting options less readable than calling the formatting methods, but that's a matter of preference.