The issue is not whether the process is in the foreground or background. When you start a process using Java, you have to use Java to control that process' lifecyle. The Java API provides you access to various attributes of the process. What you're interested in here is the output of the process. That is represented by the process' InputStream. It seems counterintuitive, but it makes sense because from the perspective of your Java program, the process' output is the program's input. Conversely, if you need to send data to the process, you write to the process' OutputStream.
To sum up, access the process' InputStream and print that out to the command-line:
Process process = new ProcessBuilder("C:\\Path\\To\\My\\Application.exe").start();
BufferedReader reader = new BufferedReader(new InputStreamReader(process.getInputStream()));
StringBuilder output = new StringBuilder();
String line;
while ((line = reader.readLine()) != null) {
output.append(line);
}
System.out.println(line);
This code, of course, assumes that your process is not waiting for any input, i.e., it is not interactive.
Answer from Vivin Paliath on Stack OverflowThe issue is not whether the process is in the foreground or background. When you start a process using Java, you have to use Java to control that process' lifecyle. The Java API provides you access to various attributes of the process. What you're interested in here is the output of the process. That is represented by the process' InputStream. It seems counterintuitive, but it makes sense because from the perspective of your Java program, the process' output is the program's input. Conversely, if you need to send data to the process, you write to the process' OutputStream.
To sum up, access the process' InputStream and print that out to the command-line:
Process process = new ProcessBuilder("C:\\Path\\To\\My\\Application.exe").start();
BufferedReader reader = new BufferedReader(new InputStreamReader(process.getInputStream()));
StringBuilder output = new StringBuilder();
String line;
while ((line = reader.readLine()) != null) {
output.append(line);
}
System.out.println(line);
This code, of course, assumes that your process is not waiting for any input, i.e., it is not interactive.
Vivin Paliath's answer is really the way to go, then you can do whatever you want with the output, display it in your own dialogue, log it, interpret it, check for errors or whatever.
But just in case you really want that command window showing up. Execute cmd.exe and get the process' OutputStream and write the command (application.exe) to it ending with a new line.
Something along the lines of:
Process p = new ProcessBuilder("C:\\Windows\\System32\\cmd.exe").start();
out = p.getOutputStream();
out.write("path\\application.exe\r\n".getBytes());
out.flush();
Should usually drain the input stream too though anyway.
You cannot do this using pure java. There is a difference between running process and accessing the window created by other process. To achieve this goal you have to use plarform specific APIs, for example JNI/JNA either directly or indirectly.
Take a look on this project: https://github.com/twall/jna I hope it can be helpful.
You need to execute exec() method of Runtime that returns Process instance or use ProcessBuilder class methods.
Process process=Runtime.getRuntime().exec("file.exe");
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The problem is, once the Java program finishes executing, all sub-processes are closed, also the Ruby Script.
On *nix systems (POSIX really, including Debian Linux) the process is sent a HUP signal (SIGHUP or hangup) when its' parent process ends. You can use the nohup(1) command when you start a subprocess to ignore the hangup from the child process.
Alternatively, you could potentially make use of the Ruby Signal Module and use Signal.trap(HUP) to handle it some other way.
Try to use Process.getOutputStream, wait for output from the process with runs Ruby, and if it takes too much time, then you can run in the background also.