With the directory on the classpath, from a class loaded by the same classloader, you should be able to use either of:
// From ClassLoader, all paths are "absolute" already - there's no context
// from which they could be relative. Therefore you don't need a leading slash.
InputStream in = this.getClass().getClassLoader()
.getResourceAsStream("SomeTextFile.txt");
// From Class, the path is relative to the package of the class unless
// you include a leading slash, so if you don't want to use the current
// package, include a slash like this:
InputStream in = this.getClass().getResourceAsStream("/SomeTextFile.txt");
If those aren't working, that suggests something else is wrong.
So for example, take this code:
package dummy;
import java.io.*;
public class Test
{
public static void main(String[] args)
{
InputStream stream = Test.class.getResourceAsStream("/SomeTextFile.txt");
System.out.println(stream != null);
stream = Test.class.getClassLoader().getResourceAsStream("SomeTextFile.txt");
System.out.println(stream != null);
}
}
And this directory structure:
code
dummy
Test.class
txt
SomeTextFile.txt
And then (using the Unix path separator as I'm on a Linux box):
java -classpath code:txt dummy.Test
Results:
true
true
Answer from Jon Skeet on Stack OverflowWith the directory on the classpath, from a class loaded by the same classloader, you should be able to use either of:
// From ClassLoader, all paths are "absolute" already - there's no context
// from which they could be relative. Therefore you don't need a leading slash.
InputStream in = this.getClass().getClassLoader()
.getResourceAsStream("SomeTextFile.txt");
// From Class, the path is relative to the package of the class unless
// you include a leading slash, so if you don't want to use the current
// package, include a slash like this:
InputStream in = this.getClass().getResourceAsStream("/SomeTextFile.txt");
If those aren't working, that suggests something else is wrong.
So for example, take this code:
package dummy;
import java.io.*;
public class Test
{
public static void main(String[] args)
{
InputStream stream = Test.class.getResourceAsStream("/SomeTextFile.txt");
System.out.println(stream != null);
stream = Test.class.getClassLoader().getResourceAsStream("SomeTextFile.txt");
System.out.println(stream != null);
}
}
And this directory structure:
code
dummy
Test.class
txt
SomeTextFile.txt
And then (using the Unix path separator as I'm on a Linux box):
java -classpath code:txt dummy.Test
Results:
true
true
When using the Spring Framework (either as a collection of utilities or container - you do not need to use the latter functionality) you can easily use the Resource abstraction.
Resource resource = new ClassPathResource("com/example/Foo.class");
Through the Resource interface you can access the resource as InputStream, URL, URI or File. Changing the resource type to e.g. a file system resource is a simple matter of changing the instance.
Try getting hold of a URL for your classpath resource:
URL url = this.getClass().getResource("/com/path/to/file.txt")
Then create a file using the constructor that accepts a URI:
File file = new File(url.toURI());
This also works, and doesn't require a /path/to/file URI conversion. If the file is on the classpath, this will find it.
File currFile = new File(getClass().getClassLoader().getResource("the_file.txt").getFile());