The pipe symbol is special in a regexp (it marks alternatives), you need to escape it. Depending on the java version you are using this could well explain your unpredictable results.
class t {
public static void main(String[]_)
{
String temp = "0|0";
String[] splitString = temp.split("\\|");
for (int i=0; i<splitString.length; i++)
System.out.println("splitString["+i+"] is " + splitString[i]);
}
}
outputs
splitString[0] is 0
splitString[1] is 0
Note that one backslash is the regexp escape character, but because a backslash is also the escape character in java source you need two of them to push the backslash into the regexp.
Answer from crazyscot on Stack OverflowThe pipe symbol is special in a regexp (it marks alternatives), you need to escape it. Depending on the java version you are using this could well explain your unpredictable results.
class t {
public static void main(String[]_)
{
String temp = "0|0";
String[] splitString = temp.split("\\|");
for (int i=0; i<splitString.length; i++)
System.out.println("splitString["+i+"] is " + splitString[i]);
}
}
outputs
splitString[0] is 0
splitString[1] is 0
Note that one backslash is the regexp escape character, but because a backslash is also the escape character in java source you need two of them to push the backslash into the regexp.
I still suggest to use split(), it skips null tokens by default. you want to get rid of non numeric characters in the string and only keep pipes and numbers, then you can easily use split() to get what you want. or you can pass multiple delimiters to split (in form of regex) and this should work:
String[] splited = yourString.split("[\\|\\s]+");
and the regex:
import java.util.regex.*;
Pattern pattern = Pattern.compile("\\d+(?=([\\|\\s\\r\\n]))");
Matcher matcher = pattern.matcher(yourString);
while (matcher.find()) {
System.out.println(matcher.group());
}
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This behavior is explicitly documented in String.split(String regex) (emphasis mine):
This method works as if by invoking the two-argument split method with the given expression and a limit argument of zero. Trailing empty strings are therefore not included in the resulting array.
If you want those trailing empty strings included, you need to use String.split(String regex, int limit) with a negative value for the second parameter (limit):
String[] array = values.split("\\|", -1);
Try this
String[] array = values.split("\\|",-1);
Yes use String.split() for each line as you read it from the file.
line.split("\\|");
An alternative is to use String.split(...)
String s="Hi farshad zeinali/ how are you?/i have a question!/can you help me?";
String[] ss=s.split("/");
for(int i=0;i<ss.length;i++)
{
System.out.println(ss[i]);
}
You need a regular expression like "\\s+", which means: split whenever at least one whitespace is encountered. The full Java code is:
try {
String[] splitArray = input.split("\\s+");
} catch (PatternSyntaxException ex) {
//
}
String[] result = "hi i'm paul".split("\\s+"); to split across one or more cases.
Or you could take a look at Apache Common StringUtils. It has StringUtils.split(String str) method that splits string using white space as delimiter. It also has other useful utility methods