Yes. Call the method println from System.out (not String.out which doesn't exist), you don't assign a value to it. And you multiply the int you parsed.
String.out.println = mataintal * mataintal;
should be
System.out.println(nr * nr);
Top answer 1 of 3
3
Yes. Call the method println from System.out (not String.out which doesn't exist), you don't assign a value to it. And you multiply the int you parsed.
String.out.println = mataintal * mataintal;
should be
System.out.println(nr * nr);
2 of 3
1
this makes no sense>
String.out.println = mataintal * mataintal;
you print using
System.out.println();
on the other hand, mataintal is a String, you need instead nr which is the result of parsing that string into an integer
your final line must be like:
System.out.println(nr * nr);
Java Square Cafe
javasquare.cafe
Local coffee shop serving espresso coffee drinks | Java Square Cafe | Java Square Cafe
Java Square is a full service coffee shop serving espresso coffee drinks, such as lattes and cappuccinos, blended iced coffees. Our staff of trained baristas strives to pull the perfect shot, steam the most velvety milk and pour the most perfect ...
[Java] How do I find the square root of a number then round it up/down
Break down your problem into steps so small that you can solve each trivially, for example: Find a function which gets the square root of a number Store the returned value of a function in a variable Find a function which rounds a number up or down Print a number You can now Google each of these subtasks and chain them together to get your result. Try it and let us know what goes wrong, if anything. More on reddit.com
9
0
May 5, 2022[Java] Square every digit of a number?[Code Explanation]
String result = ""; just initializes the result variable to the empty string "". n /= 10 is shorthand for n = n / 10 result = digit * digit + result This evaluates digit * digit (so digit2 ) and adds result to it. So, if result is initially 81 and digit is 8, it will set result to 8 * 8 (64) plus result (81). In Java, adding an integer to a string first converts the integer to a string, so the result 64 turns into the String "64", and adds it to "81", giving you "6481". More on reddit.com
6
8
August 11, 2017Videos
01:27
How to Square a Number in Java - For Beginners [2025] - YouTube
03:37
Square a Number Using a Method in Java - YouTube
r/programming on Reddit: Square a Number Using a Method in Java
20:23
Star Pattern - 14 How to Print Hollow Rectangle/ Square Star ...
All Things Good | By Java on the Square
Solve any square or hollow pattern in Java
CodeGym
codegym.cc › java blog › java numbers › how to square a number in java
How to Square a Number in Java
September 28, 2023 - Square of 3.5 is: 12.25 Square of 11.1 is: 123.21 Square of 13.0 is: 169.0 · In this example, we have used Math.pow(number, POW) method provided by Java to multiply the number with itself to the times “POW” is passed.
Alvin Alexander
alvinalexander.com › java › how-square-number-in-java-method-function
Java: How to square a number | alvinalexander.com
January 31, 2026 - This is how you square a number by multiplying it by itself:
Square
developer.squareup.com › docs › sdks › java › quick-start
Square Java SDK Quickstart
Calls the list method of the Locations API to retrieve the locations associated with the Square account. If the request is successful, the code prints the location information in the terminal. ... The Java code in this Quickstart reads your Square Sandbox access token from a separate configuration file.
Oracle
docs.oracle.com › javase › 8 › docs › api › java › lang › Math.html
Math (Java Platform SE 8 )
October 20, 2025 - Returns the correctly rounded positive square root of a double value.
Top answer 1 of 3
15
The fastest way to square a number is to multiply it by itself.
Why is
Math.powso slow?
It's really not, but it is performing exponentiation instead of simple multiplication.
and why does it cope badly with > 1 and even worse with < -1 numbers
First, because it does the math. From the Javadoc it also contains tests for many corner cases. Finally, I would not rely too much on your micro-benchmark.
2 of 3
8
Squaring by multipling with self is the fastest. Because that approch can be directly translated into simple, non-branching bytecode (and thus, indirectly, machine code).
Math.pow() is a quite complex function that comes with various guarantees for edge cases. And it need to be called instead of being inlined.
Instagram
instagram.com › javasquare
Java Square Cafe (@javasquare)
1,317 Followers, 432 Following, 1,217 Posts - Java Square Cafe (@javasquare) on Instagram: "103 W. Landry/ Opelousas/ LA"
W3Schools
w3schools.com › java › ref_math_sqrt.asp
Java Math sqrt() Method
System.out.println(Math.sqrt(0)); System.out.println(Math.sqrt(1)); System.out.println(Math.sqrt(9)); System.out.println(Math.sqrt(0.64)); System.out.println(Math.sqrt(-9)); ... The sqrt() method returns the square root of a number.
Square
developer.squareup.com › docs › sdks › java
Java SDK
Download the Square Java SDK Quickstart sample app and follow the instructions in the README.
Java Plus
java-plus.com
Java Plus
Met Square Specials · Clayton Specials · We practice hospitality with exceptional food and service to build strong connections with our community! Always Fast, Fresh, & Friendly!! We serve all St. Louis Metropolitan Area from east, west, north, & south, we’ve got you covered!
GitHub
github.com › square › square-java-sdk
GitHub - square/square-java-sdk: Java client library for the Square API
Java client library for the Square API. Contribute to square/square-java-sdk development by creating an account on GitHub.
Starred by 66 users
Forked by 36 users
Languages Java 100.0% | Java 100.0%
Reddit
reddit.com › r/learnprogramming › [java] how do i find the square root of a number then round it up/down
r/learnprogramming on Reddit: [Java] How do I find the square root of a number then round it up/down
May 5, 2022 -
This is probably a simple thing to most but I’m just struggling to print the square root of a number then rounding it up or down in Java. Any help would be greatly appreciated!
Top answer 1 of 3
7
Break down your problem into steps so small that you can solve each trivially, for example: Find a function which gets the square root of a number Store the returned value of a function in a variable Find a function which rounds a number up or down Print a number You can now Google each of these subtasks and chain them together to get your result. Try it and let us know what goes wrong, if anything.
2 of 3
2
https://docs.oracle.com/javase/8/docs/api/java/lang/Math.html#sqrt-double-
Quora
quora.com › How-do-I-square-in-Java
How to square in Java - Quora
Java (programming languag... ... To square a number in Java you multiply it by itself.
Medium
medium.com › @AlexanderObregon › checking-if-a-number-is-a-perfect-square-in-java-fce4d6fc80ec
Checking if a Number Is a Perfect Square in Java | Medium
October 21, 2025 - Larger values such as 10,000 are still perfect squares because 100 squared equals 10,000. This means any detection method in code has to scale to numbers both small and large without breaking accuracy. One way to introduce this in Java is by checking a few values directly with a loop and a square comparison:
GeeksforGeeks
geeksforgeeks.org › dsa › calculate-square-of-a-number-without-using-and-pow
Calculate square of a number without using *, / and pow() - GeeksforGeeks
March 29, 2023 - // Simple solution to calculate square // without using * and pow() import java.io.*; class GFG{ public static int square(int num) { // Handle negative input if (num < 0) num = -num; // Initialize result int result = 0, times = num; while (times > 0) { int possibleShifts = 0, currTimes = 1; while ((currTimes << 1) <= times) { currTimes = currTimes << 1; ++possibleShifts; } result = result + (num << possibleShifts); times = times - currTimes; } return result; } // Driver code public static void main(String[] args) { for(int n = 10; n <= 15; ++n) { System.out.println("n = " + n + ", n^2 = " + square(n)); } } } // This code is contributed by RohitOberoi
Reddit
reddit.com › r/learnprogramming › [java] square every digit of a number?[code explanation]
r/learnprogramming on Reddit: [Java] Square every digit of a number?[Code Explanation]
August 11, 2017 -
public int squareDigits(int n) {
String result = "";
while (n != 0) {
int digit = n % 10 ;
result = digit*digit + result ;
n /= 10 ;
}
return Integer.parseInt(result) ;
}The above code returns a square of every digit like 99= 8181
I don't understand this code particularly String result = ""; n /= 10 ; and result = digit*digit + result ;
Can Someone Explain? Thanks.
Top answer 1 of 2
7
String result = ""; just initializes the result variable to the empty string "". n /= 10 is shorthand for n = n / 10 result = digit * digit + result This evaluates digit * digit (so digit2 ) and adds result to it. So, if result is initially 81 and digit is 8, it will set result to 8 * 8 (64) plus result (81). In Java, adding an integer to a string first converts the integer to a string, so the result 64 turns into the String "64", and adds it to "81", giving you "6481".
2 of 2
6
Let's try it with an example. Assume n is 97. Line 6: digit gets the remainder of 97 divided by 10 (which is 7). Line 7: result is set to digit * digit (which is 49) plus the result, except this plus is concatenating to a string. result was "" (the empty string) and then you do 49 + "" (which adds an int to a string) to yield "49" (which is a string. Line 8, n /= 10 divides n by 10 and throws away and remainder (it is doing integer division). 97 / 10 is therefore 9. Line 5: We test if n != 0. Since n is 9, we enter the loop. Line 6: We divide 9 by 10 and get the remainder (it's 0 with a remainder of 9) so digit gets the value 9. Line 7: digit * digit is 81. result is currently "49", so 81 + "49" is "8149". Line 8: n /= 10 divides 9 by 10 which is 0 (throw away the remainder), so n is now 0. Line 5: n is now 0, exit the loop. Line 11: Convert "8149" to an integer.
Geva Theatre
gevatheatre.org › home
Home - Geva Theatre
November 30, 2022 - Experience world‑class live theatre in Rochester at Geva Theatre - season shows, subscriptions, events & community arts.
Scaler
scaler.com › home › topics › program to find square and square root in java
Program to Find Square and Square Root in Java - Scaler Topics
April 25, 2024 - If you pass an integer or any primitive ... 2) = 100.0 · So, in order to find the square of a number, we can pass the base as the number and the exponent as 2....
Study.com
study.com › business courses › business 104: information systems and computer applications
How to Square a Number in Java - Lesson | Study.com
March 14, 2018 - If you need to square a number, a very simple solution is to just multiply the number by itself. After all, 52 is really 5 * 5. In this instance, it's totally acceptable to multiply a number by itself, although there is another tool that will ...