varags. If a method signature is method(Param param, String... x) it will take one Param type of object and any number of String objects.

There are couple if cool things about it:

1. It's nothing special. It's just sugared array. So, method(MyObject... o) is same as method(MyObject[] o).

2. Vararg has to be the last parameter in argument list.

3. There is this funny thing that bit me once. method(MyObject... o) can be called as method() without any compilation error. Java will internally convert the no-arg call to method(new MyObject[0]). So, be aware of this.

If you check the API for List you'll notice it says:

Interface List<E>

Being an interface means it cannot be instantiated (no new List() is possible).

If you check that link, you'll find some classes that implement List:

All Known Implementing Classes:

AbstractList, AbstractSequentialList, ArrayList, AttributeList, CopyOnWriteArrayList, LinkedList, RoleList, RoleUnresolvedList, Stack, Vector

Some of those can be instantiated (the ones that are not defined as abstract class). Use their links to know more about them, I.E: to know which fits better your needs.

The 3 most commonly used ones probably are:

 List<String> supplierNames1 = new ArrayList<String>();
 List<String> supplierNames2 = new LinkedList<String>();
 List<String> supplierNames3 = new Vector<String>();

Bonus:
You can also instantiate it with values, in an easier way, using the Arrays class, as follows:

List<String> supplierNames = Arrays.asList("sup1", "sup2", "sup3");
System.out.println(supplierNames.get(1));

But note you are not allowed to add more elements to that list, as it's fixed-size.