A very simple implementation with String.split():

String path = "/abc/def/ghfj.doc";
// Split path into segments
String segments[] = path.split("/");
// Grab the last segment
String document = segments[segments.length - 1];

You may try this

String example = "ABC Results for draw no 2888";
System.out.println(example.substring(example.lastIndexOf(" ") + 1));

You can just split the string..

public String[] split(String regex)

Note that java.lang.String.split uses delimiter's regular expression value. Basically like this...

String filename = "abc.def.ghi";     // full file name
String[] parts = filename.split("\\."); // String array, each element is text between dots

String beforeFirstDot = parts[0];    // Text before the first dot

Of course, this is split into multiple lines for clairity. It could be written as

String beforeFirstDot = filename.split("\\.")[0];

Quick and dirty solution using a regular expression and groups:

public class AClass {

    private static final String TEXT = "/abc/def/ghfj/ijk/lmn.doc";
    private static final String REGULAR_EXPRESSION = "(/[^/]*){2}/([^/]*)/.*";

    public static void main(final String[] args) {
        final Pattern pattern = Pattern.compile(REGULAR_EXPRESSION);
        final Matcher matcher = pattern.matcher(TEXT);
        if (matcher.matches()) {
            // the following variable holds "ghfj"
            String value = matcher.group(2);
            System.out.println(value);
        }
    }
}

Now you need to be more precise in order to allow us to fine tune the regular expression to your concrete needs.

Edit: I edited the solution according to your own edit. The regular expression has to be understood as follows:

• (/[^/]*){2} : two times the character / followed by any character except /
• / : an additional /character
• ([^/]*) : a group of characters not containing /
• /.* : a / character followed by any other character

Then matcher.group(2) returns the String held by the group represented by the ([^/]*) part of the above regular expression.