Shortest ES6+ one liner:

let exists = Object.values(obj).includes("test1");

There are a lot of half-truths here, so I thought I make some things clearer.

Actually you can't accurately tell if a variable exists (unless you want to wrap every second line into a try-catch block).

The reason is Javascript has this notorious value of undefined which strikingly doesn't mean that the variable is not defined, or that it doesn't exist undefined !== not defined

var a;
alert(typeof a); // undefined (declared without a value)
alert(typeof b); // undefined (not declared)

So both a variable that exists and another one that doesn't can report you the undefined type.

As for @Kevin's misconception, null == undefined. It is due to type coercion, and it's the main reason why Crockford keeps telling everyone who is unsure of this kind of thing to always use strict equality operator === to test for possibly falsy values. null !== undefined gives you what you might expect. Please also note, that foo != null can be an effective way to check if a variable is neither undefined nor null. Of course you can be explicit, because it may help readability.

If you restrict the question to check if an object exists, typeof o == "object" may be a good idea, except if you don't consider arrays objects, as this will also reported to be the type of object which may leave you a bit confused. Not to mention that typeof null will also give you object which is simply wrong.

The primal area where you really should be careful about typeof, undefined, null, unknown and other misteries are host objects. They can't be trusted. They are free to do almost any dirty thing they want. So be careful with them, check for functionality if you can, because it's the only secure way to use a feature that may not even exist.

Use ‘in’ to check for inherited properties, hasOwnProperty will return false for those.

No, there is no built in method to search for a value on an object.

The only way to do so is to iterate over all the keys of the object and check each value. Using techniques that would work even in old browsers, you can do this:

function findValue(o, value) {
    for (var prop in o) {
        if (o.hasOwnProperty(prop) && o[prop] === value) {
            return prop;
        }
    }
    return null;
}

findValue(car, "2011");    // will return "year"
findValue(car, "2012");    // will return null

Note: This will return the first property that contains the search value even though there could be more than one property that matched. At the cost of efficiency, you could return an array of all properties that contain the desired value.

Note: This uses the extra .hasOwnProperty() check as a safeguard against any code that adds enumerable properties to Object.prototype. If there is no such code and you're sure there never will be, then the .hasOwnProperty() check can be eliminated.

The simplest to understand solution is to loop over the array, and check each one.

var match;
for (var i = 0; i < yourArray.length; i++) {
   if (yourArray[i].MachineId == 2) 
        match = yourArray[i];
}

Note if there is more than one matching item, this will return the last one. You can also dress this up in a function.

function findByMachineId(ary, value) {
   var match;
    for (var i = 0; i < ary.length; i++) {
       if (ary[i].MachineId == value) 
            match = ary[i];
    }
    return match;
}

This small snippets works for me..

const arrayOfObject = [{ id: 1, name: 'john' }, {id: 2, name: 'max'}];

const checkUsername = obj => obj.name === 'max';

console.log(arrayOfObject.some(checkUsername))

if you have array of elements like ['john','marsh'] then we can do some thing like this

const checkUsername = element => element == 'john';
    
console.log(arrayOfObject.some(checkUsername))