[Addendum 12/2022]: Here's a library to format dates using Intl.DateTimeFormat.
[Addendum 01/2024]: And here is a (ES-)Date manipulation library
Try something like this
var d = new Date,
dformat = [d.getMonth()+1,
d.getDate(),
d.getFullYear()].join('/')+' '+
[d.getHours(),
d.getMinutes(),
d.getSeconds()].join(':');
If you want leading zero's for values < 10, use this number extension
Number.prototype.padLeft = function(base,chr){
var len = (String(base || 10).length - String(this).length)+1;
return len > 0? new Array(len).join(chr || '0')+this : this;
}
// usage
//=> 3..padLeft() => '03'
//=> 3..padLeft(100,'-') => '--3'
Applied to the previous code:
var d = new Date,
dformat = [(d.getMonth()+1).padLeft(),
d.getDate().padLeft(),
d.getFullYear()].join('/') +' ' +
[d.getHours().padLeft(),
d.getMinutes().padLeft(),
d.getSeconds().padLeft()].join(':');
//=> dformat => '05/17/2012 10:52:21'
See this code in [jsfiddle][1]
[edit 2019] Using ES20xx, you can use a template literal and the new padStart string extension.
const dt = new Date();
const padL = (nr, len = 2, chr = `0`) => `${nr}`.padStart(2, chr);
console.log(`${
padL(dt.getMonth()+1)}/${
padL(dt.getDate())}/${
dt.getFullYear()} ${
padL(dt.getHours())}:${
padL(dt.getMinutes())}:${
padL(dt.getSeconds())}`
);
Answer from KooiInc on Stack Overflow[Addendum 12/2022]: Here's a library to format dates using Intl.DateTimeFormat.
[Addendum 01/2024]: And here is a (ES-)Date manipulation library
Try something like this
var d = new Date,
dformat = [d.getMonth()+1,
d.getDate(),
d.getFullYear()].join('/')+' '+
[d.getHours(),
d.getMinutes(),
d.getSeconds()].join(':');
If you want leading zero's for values < 10, use this number extension
Number.prototype.padLeft = function(base,chr){
var len = (String(base || 10).length - String(this).length)+1;
return len > 0? new Array(len).join(chr || '0')+this : this;
}
// usage
//=> 3..padLeft() => '03'
//=> 3..padLeft(100,'-') => '--3'
Applied to the previous code:
var d = new Date,
dformat = [(d.getMonth()+1).padLeft(),
d.getDate().padLeft(),
d.getFullYear()].join('/') +' ' +
[d.getHours().padLeft(),
d.getMinutes().padLeft(),
d.getSeconds().padLeft()].join(':');
//=> dformat => '05/17/2012 10:52:21'
See this code in [jsfiddle][1]
[edit 2019] Using ES20xx, you can use a template literal and the new padStart string extension.
const dt = new Date();
const padL = (nr, len = 2, chr = `0`) => `${nr}`.padStart(2, chr);
console.log(`${
padL(dt.getMonth()+1)}/${
padL(dt.getDate())}/${
dt.getFullYear()} ${
padL(dt.getHours())}:${
padL(dt.getMinutes())}:${
padL(dt.getSeconds())}`
);
You can always format a date by extracting the parts and combine them using string functions in desired order:
function formatDate(date) {
let datePart = [
date.getMonth() + 1,
date.getDate(),
date.getFullYear()
].map((n, i) => n.toString().padStart(i === 2 ? 4 : 2, "0")).join("/");
let timePart = [
date.getHours(),
date.getMinutes(),
date.getSeconds()
].map((n, i) => n.toString().padStart(2, "0")).join(":");
return datePart + " " + timePart;
}
let date = new Date();
console.log("%o => %s", date, formatDate(date));
Just leverage the built-in toISOString method that brings your date to the ISO 8601 format:
let yourDate = new Date()
yourDate.toISOString().split('T')[0]
Where yourDate is your date object.
Edit: @exbuddha wrote this to handle time zone in the comments:
const offset = yourDate.getTimezoneOffset()
yourDate = new Date(yourDate.getTime() - (offset*60*1000))
return yourDate.toISOString().split('T')[0]
You can do:
function formatDate(date) {
var d = new Date(date),
month = '' + (d.getMonth() + 1),
day = '' + d.getDate(),
year = d.getFullYear();
if (month.length < 2)
month = '0' + month;
if (day.length < 2)
day = '0' + day;
return [year, month, day].join('-');
}
console.log(formatDate('Sun May 11,2014'));
Usage example:
console.log(formatDate('Sun May 11,2014'));
Output:
2014-05-11
Demo on JSFiddle: http://jsfiddle.net/abdulrauf6182012/2Frm3/
You can fully format the string as mentioned in other posts. But I think your better off using the locale functions in the date object?
var d = new Date("2017-03-16T17:46:53.677");
console.log( d.toLocaleString() );
edit :
ISO 8601 ( the format you are constructing with ) states the time zone is appended at the end with a [{+|-}hh][:mm] at the end of the string.
so you could do this :
var tzOffset = "+07:00"
var d = new Date("2017-03-16T17:46:53.677"+ tzOffset);
console.log(d.toLocaleString());
var d = new Date("2017-03-16T17:46:53.677"); // assumes local time.
console.log(d.toLocaleString());
var d = new Date("2017-03-16T17:46:53.677Z"); // UTC time
console.log(d.toLocaleString());
edit :
Just so you know the locale function displays the date and time in the manner of the users language and location. European date is dd/mm/yyyy and US is mm/dd/yyyy.
var d = new Date("2017-03-16T17:46:53.677");
console.log(d.toLocaleString("en-US"));
console.log(d.toLocaleString("en-GB"));
Here we go:
var today = new Date();
var day = today.getDate() + "";
var month = (today.getMonth() + 1) + "";
var year = today.getFullYear() + "";
var hour = today.getHours() + "";
var minutes = today.getMinutes() + "";
var seconds = today.getSeconds() + "";
day = checkZero(day);
month = checkZero(month);
year = checkZero(year);
hour = checkZero(hour);
minutes = checkZero(minutes);
seconds = checkZero(seconds);
console.log(day + "/" + month + "/" + year + " " + hour + ":" + minutes + ":" + seconds);
function checkZero(data){
if(data.length == 1){
data = "0" + data;
}
return data;
}
Call the toISOString() method:
var dt = new Date("30 July 2010 15:05 UTC");
document.write(dt.toISOString());
// Output:
// 2010-07-30T15:05:00.000Z
toISOString() will return current UTC time only not the current local time. If you want to get the current local time in yyyy-MM-ddTHH:mm:ss.SSSZ format then you should get the current time using following two methods
Method 1:
console.log(new Date(new Date().toString().split('GMT')[0]+' UTC').toISOString());
Method 2:
console.log(new Date(new Date().getTime() - new Date().getTimezoneOffset() * 60000).toISOString());