var date = new Date();
alert( date.getFullYear() + ("0" + (date.getMonth() + 1)).slice(-2) + ("0" + date.getDate()).slice(-2) + ("0" + date.getHours() ).slice(-2) + ("0" + date.getMinutes()).slice(-2) + ("0" + date.getSeconds()).slice(-2) );
edit
function pad2(n) { return n < 10 ? '0' + n : n }
var date = new Date();
alert( date.getFullYear().toString() + pad2(date.getMonth() + 1) + pad2( date.getDate()) + pad2( date.getHours() ) + pad2( date.getMinutes() ) + pad2( date.getSeconds() ) );
Answer from gurvinder372 on Stack Overflowvar date = new Date();
alert( date.getFullYear() + ("0" + (date.getMonth() + 1)).slice(-2) + ("0" + date.getDate()).slice(-2) + ("0" + date.getHours() ).slice(-2) + ("0" + date.getMinutes()).slice(-2) + ("0" + date.getSeconds()).slice(-2) );
edit
function pad2(n) { return n < 10 ? '0' + n : n }
var date = new Date();
alert( date.getFullYear().toString() + pad2(date.getMonth() + 1) + pad2( date.getDate()) + pad2( date.getHours() ) + pad2( date.getMinutes() ) + pad2( date.getSeconds() ) );
Here's my (ES5 safe) method to add the YYYYMMDDHHMMSS() function to any Date object.
On older browsers, either shim Object.defineProperty or just add the inner function directly to Date.prototype:
Object.defineProperty(Date.prototype, 'YYYYMMDDHHMMSS', {
value: function() {
function pad2(n) { // always returns a string
return (n < 10 ? '0' : '') + n;
}
return this.getFullYear() +
pad2(this.getMonth() + 1) +
pad2(this.getDate()) +
pad2(this.getHours()) +
pad2(this.getMinutes()) +
pad2(this.getSeconds());
}
});
Videos
[Addendum 12/2022]: Here's a library to format dates using Intl.DateTimeFormat.
[Addendum 01/2024]: And here is a (ES-)Date manipulation library
Try something like this
var d = new Date,
dformat = [d.getMonth()+1,
d.getDate(),
d.getFullYear()].join('/')+' '+
[d.getHours(),
d.getMinutes(),
d.getSeconds()].join(':');
If you want leading zero's for values < 10, use this number extension
Number.prototype.padLeft = function(base,chr){
var len = (String(base || 10).length - String(this).length)+1;
return len > 0? new Array(len).join(chr || '0')+this : this;
}
// usage
//=> 3..padLeft() => '03'
//=> 3..padLeft(100,'-') => '--3'
Applied to the previous code:
var d = new Date,
dformat = [(d.getMonth()+1).padLeft(),
d.getDate().padLeft(),
d.getFullYear()].join('/') +' ' +
[d.getHours().padLeft(),
d.getMinutes().padLeft(),
d.getSeconds().padLeft()].join(':');
//=> dformat => '05/17/2012 10:52:21'
See this code in [jsfiddle][1]
[edit 2019] Using ES20xx, you can use a template literal and the new padStart string extension.
const dt = new Date();
const padL = (nr, len = 2, chr = `0`) => `${nr}`.padStart(2, chr);
console.log(`${
padL(dt.getMonth()+1)}/${
padL(dt.getDate())}/${
dt.getFullYear()} ${
padL(dt.getHours())}:${
padL(dt.getMinutes())}:${
padL(dt.getSeconds())}`
);
You can always format a date by extracting the parts and combine them using string functions in desired order:
function formatDate(date) {
let datePart = [
date.getMonth() + 1,
date.getDate(),
date.getFullYear()
].map((n, i) => n.toString().padStart(i === 2 ? 4 : 2, "0")).join("/");
let timePart = [
date.getHours(),
date.getMinutes(),
date.getSeconds()
].map((n, i) => n.toString().padStart(2, "0")).join(":");
return datePart + " " + timePart;
}
let date = new Date();
console.log("%o => %s", date, formatDate(date));
Just leverage the built-in toISOString method that brings your date to the ISO 8601 format:
let yourDate = new Date()
yourDate.toISOString().split('T')[0]
Where yourDate is your date object.
Edit: @exbuddha wrote this to handle time zone in the comments:
const offset = yourDate.getTimezoneOffset()
yourDate = new Date(yourDate.getTime() - (offset*60*1000))
return yourDate.toISOString().split('T')[0]
You can do:
function formatDate(date) {
var d = new Date(date),
month = '' + (d.getMonth() + 1),
day = '' + d.getDate(),
year = d.getFullYear();
if (month.length < 2)
month = '0' + month;
if (day.length < 2)
day = '0' + day;
return [year, month, day].join('-');
}
console.log(formatDate('Sun May 11,2014'));
Usage example:
console.log(formatDate('Sun May 11,2014'));
Output:
2014-05-11
Demo on JSFiddle: http://jsfiddle.net/abdulrauf6182012/2Frm3/
We should use in-built toISOString function to covert it to ISO date format and remove not required data using string manipulation.
let datenow = new Date();
console.log(datenow); // "2021-07-28T18:11:11.282Z"
console.log(generateDatabaseDateTime(datenow)); // "2021-07-28 14:11:33"
function generateDatabaseDateTime(date) {
return date.toISOString().replace("T"," ").substring(0, 19);
}
Ideally solution should be to use momentjs or dayjs library.
Adding this answer as well that RobG suggested.
let datenow = new Date;
console.log(datenow); // "2021-07-28T18:11:11.282Z"
console.log(generateDatabaseDateTime(datenow)); // "2021-07-28 14:11:33"
function generateDatabaseDateTime(date) {
const p = new Intl.DateTimeFormat('en', {
year:'numeric',
month:'2-digit',
day:'2-digit',
hour:'2-digit',
minute:'2-digit',
second:'2-digit',
hour12: false,
timeZone:'UTC'
}).formatToParts(date).reduce((acc, part) => {
acc[part.type] = part.value;
return acc;
}, {});
return `${p.year}-${p.month}-${p.day} ${p.hour}:${p.minute}:${p.second}`;
}