You can do it like this -
let arr1 = [
{ id: "abdc4051", date: "2017-01-24" },
{ id: "abdc4052", date: "2017-01-22" }
];
let arr2 = [
{ id: "abdc4051", name: "ab" },
{ id: "abdc4052", name: "abc" }
];
let arr3 = arr1.map((item, i) => Object.assign({}, item, arr2[i]));
console.log(arr3);
Use below code if arr1 and arr2 are in a different order:
let arr1 = [
{ id: "abdc4051", date: "2017-01-24" },
{ id: "abdc4052", date: "2017-01-22" }
];
let arr2 = [
{ id: "abdc4051", name: "ab" },
{ id: "abdc4052", name: "abc" }
];
let merged = [];
for(let i=0; i<arr1.length; i++) {
merged.push({
...arr1[i],
...(arr2.find((itmInner) => itmInner.id === arr1[i].id))}
);
}
console.log(merged);
Use this if arr1 and arr2 are in a same order
let arr1 = [
{ id: "abdc4051", date: "2017-01-24" },
{ id: "abdc4052", date: "2017-01-22" }
];
let arr2 = [
{ id: "abdc4051", name: "ab" },
{ id: "abdc4052", name: "abc" }
];
let merged = [];
for(let i=0; i<arr1.length; i++) {
merged.push({
...arr1[i],
...arr2[i]
});
}
console.log(merged);
Answer from Rajaprabhu Aravindasamy on Stack OverflowYou can do it like this -
let arr1 = [
{ id: "abdc4051", date: "2017-01-24" },
{ id: "abdc4052", date: "2017-01-22" }
];
let arr2 = [
{ id: "abdc4051", name: "ab" },
{ id: "abdc4052", name: "abc" }
];
let arr3 = arr1.map((item, i) => Object.assign({}, item, arr2[i]));
console.log(arr3);
Use below code if arr1 and arr2 are in a different order:
let arr1 = [
{ id: "abdc4051", date: "2017-01-24" },
{ id: "abdc4052", date: "2017-01-22" }
];
let arr2 = [
{ id: "abdc4051", name: "ab" },
{ id: "abdc4052", name: "abc" }
];
let merged = [];
for(let i=0; i<arr1.length; i++) {
merged.push({
...arr1[i],
...(arr2.find((itmInner) => itmInner.id === arr1[i].id))}
);
}
console.log(merged);
Use this if arr1 and arr2 are in a same order
let arr1 = [
{ id: "abdc4051", date: "2017-01-24" },
{ id: "abdc4052", date: "2017-01-22" }
];
let arr2 = [
{ id: "abdc4051", name: "ab" },
{ id: "abdc4052", name: "abc" }
];
let merged = [];
for(let i=0; i<arr1.length; i++) {
merged.push({
...arr1[i],
...arr2[i]
});
}
console.log(merged);
This solution is applicable even when the merged arrays have different sizes. Also, even if the matching keys have different names.
Merge the two arrays by using a Map as follows:
const arr1 = [
{ id: "abdc4051", date: "2017-01-24" },
{ id: "abdc4052", date: "2017-01-22" },
{ id: "abdc4053", date: "2017-01-22" }
];
const arr2 = [
{ nameId: "abdc4051", name: "ab" },
{ nameId: "abdc4052", name: "abc" }
];
const map = new Map();
arr1.forEach(item => map.set(item.id, item));
arr2.forEach(item => map.set(item.nameId, {...map.get(item.nameId), ...item}));
const mergedArr = Array.from(map.values());
console.log(JSON.stringify(mergedArr));
.as-console-wrapper { max-height: 100% !important; top: 0; }
Run the stack snippet to see the result:
[
{
"id": "abdc4051",
"date": "2017-01-24",
"nameId": "abdc4051",
"name": "ab"
},
{
"id": "abdc4052",
"date": "2017-01-22",
"nameId": "abdc4052",
"name": "abc"
},
{
"id": "abdc4053",
"date": "2017-01-22"
}
]
Here is one option:-
var array = [{
name: "foo1",
value: "val1"
}, {
name: "foo1",
value: ["val2", "val3"]
}, {
name: "foo2",
value: "val4"
}];
var output = [];
array.forEach(function(item) {
var existing = output.filter(function(v, i) {
return v.name == item.name;
});
if (existing.length) {
var existingIndex = output.indexOf(existing[0]);
output[existingIndex].value = output[existingIndex].value.concat(item.value);
} else {
if (typeof item.value == 'string')
item.value = [item.value];
output.push(item);
}
});
console.dir(output);
Here is another way of achieving that goal:
var array = [{
name: "foo1",
value: "val1"
}, {
name: "foo1",
value: [
"val2",
"val3"
]
}, {
name: "foo2",
value: "val4"
}];
var output = array.reduce(function(o, cur) {
// Get the index of the key-value pair.
var occurs = o.reduce(function(n, item, i) {
return (item.name === cur.name) ? i : n;
}, -1);
// If the name is found,
if (occurs >= 0) {
// append the current value to its list of values.
o[occurs].value = o[occurs].value.concat(cur.value);
// Otherwise,
} else {
// add the current item to o (but make sure the value is an array).
var obj = {
name: cur.name,
value: [cur.value]
};
o = o.concat([obj]);
}
return o;
}, []);
console.log(output);
If you want to merge 2 arrays of objects in JavaScript. You can use this one line trick
Array.prototype.push.apply(arr1,arr2);
For Example
var arr1 = [{name: "lang", value: "English"},{name: "age", value: "18"}];
var arr2 = [{name : "childs", value: '5'}, {name: "lang", value: "German"}];
Array.prototype.push.apply(arr1,arr2);
console.log(arr1); // final merged result will be in arr1
Output:
[{"name":"lang","value":"English"},
{"name":"age","value":"18"},
{"name":"childs","value":"5"},
{"name":"lang","value":"German"}]
With ES6 you can do it very easy as below:
var arr1 = new Array({name: "lang", value: "German"}, {name: "age", value: "18"});
var arr2 = new Array({name : "childs", value: '5'}, {name: "lang", value: "German"});
var arr3 = [...arr1, ...arr2];
Output:
arr3 = [
{"name":"lang","value":"German"},
{"name":"age","value":"18"},
{"name":"childs","value":"5"},
{"name":"lang","value":"German"}
]
You could use reduce with Object.keys to do that.
var arr = [
{id: 1, tech_id:11, action: 'swim'},
{id: 2, tech_id:11, action: 'run'},
{id: 3, tech_id:22, action: 'climb'},
{id: 4, tech_id:22, action: 'swim'},
{id: 5, tech_id:11, action: 'jump'},
]
let mergeObj = arr.reduce((p, c) => {
const {tech_id, ...otherData} = c;
if (!(tech_id in p)) {
p[tech_id] = {
data: []
}
}
p[tech_id].data.push(otherData)
return p
}, {})
mergeObj = Object.keys(mergeObj).map(key => {
return {
tech_id: key,
data: mergeObj[key].data
}
})
console.log(mergeObj);
You can use the Array reduce and Object Value function to get it done.
var arr = [
{id: 1, tech_id:11, action: 'swim'},
{id: 2, tech_id:11, action: 'run'},
{id: 3, tech_id:22, action: 'climb'},
{id: 4, tech_id:22, action: 'swim'},
{id: 5, tech_id:11, action: 'jump'},
]
const result = Object.values(arr.reduce((item, next) => {
if (!item[next.tech_id]) {
item[next.tech_id] = {
tech_id: next.tech_id,
data: []
};
}
item[next.tech_id].data.push(next);
return item;
}, {}));
console.log(result);
Hey,
I'm having trouble making two objects into one on a matching key.
I have two objects coming from 2 apis and there is one matching key in the objects.
I want to iterate over them and if the storeId matches in both objects, I want to merge the two together as seen in the perfectObject.
I have tried the spread operator, Object.assign, for...in loop instead of the for loop seen here, but found close to none success.
Thanks for the help!
const logistics = [
{"logisticsId": "L5E69E26D8FCAE","storeId": 409388,"logisticsDate": "2020-03-12T07:19:09.000Z"
},]
const stores = [
{"storeId": 409388,"ka": 0,"country": "ru","name": "test","city": "Moscow","cxw": 1,"cx": 1,"plz": 22448
}]
const perfetObject = {
"storeId": 409388,"ka": 0,"country": "ru","name": "test","city": "Moscow","cxw": 1,"cx": 1,"plz": 22448,
"logisticsId": "L5E69E26D8FCAE","storeId": 409388,"logisticsDate": "2020-03-12T07:19:09.000Z"
}
let d = {}
for(let i = 0; i < logistics.length; ++i) {for (let k = 0; k < stores.length; ++k) {if(logistics.storeId === stores.storeId) {d = {
...stores .name,
...stores .city,
...logistics.logisticsId
}
}
}
}
console.log(d)