ES6 :

Use Array.from (docs here):

console.log(
   Array.from({length:5},(v,k)=>k+1)
)

Just to complete the Mark Taylor's Answer here a more reusable way

let myArray = [];

for (let i = 0; i<101; i++){
  myArray.push({objectID:i})
}

const randomMaxMin = max => min => Math.floor(Math.random()*(max-min))
const lowerBand = requiredSpan => length => randomMaxMin(length)(requiredSpan);
const upperBand = requiredSpan => lowerBand => requiredSpan + lowerBand-1;

const getLowerAndUpperBand = requiredSpan => length => {
  const lower = lowerBand(requiredSpan)(length);
  return {
    lower: lower,
    upper: upperBand(requiredSpan)(lower)
  }
}

console.log(getLowerAndUpperBand(6)(myArray.length))

You can even specialize the generic function by choosing the requiredSpan

const getLowerAndUpperBandSix = getLowerAndUpperBand(6)
console.log(getLowerAndUpperBandSix(myArray.length))

a<x==x<b

JavaScript, 8 chars.

I had a moment, so, although you've already accepted an answer, I thought I'd contribute the following:

Number.prototype.between = function(a, b) {
  var min = Math.min(a, b),
    max = Math.max(a, b);

  return this > min && this < max;
};

var windowSize = 550;

console.log(windowSize.between(500, 600));

JS Fiddle demo.

Or, if you'd prefer to have the option to check a number is in the defined range including the end-points:

Number.prototype.between = function(a, b, inclusive) {
  var min = Math.min(a, b),
    max = Math.max(a, b);

  return inclusive ? this >= min && this <= max : this > min && this < max;
}

var windowSize = 500;

console.log(windowSize.between(500, 603, true));

JS Fiddle demo.

References:

• Math.max().
• Math.min().