Suppose you have an array users. You may use users.sort and pass a function that takes two arguments and compare them (comparator)

It should return

• something negative if first argument is less than second (should be placed before the second in resulting array)
• something positive if first argument is greater (should be placed after second one)
• 0 if those two elements are equal.

In our case if two elements are a and b we want to compare a.firstname and b.firstname

Example:

users.sort(function(a, b){
    if(a.firstname < b.firstname) { return -1; }
    if(a.firstname > b.firstname) { return 1; }
    return 0;
})

This code is going to work with any type.

Note that in "real life"™ you often want to ignore case, correctly sort diacritics, weird symbols like ß, etc. when you compare strings, so you may want to use localeCompare. See other answers for clarity.

The variables are simply mislabelled, see the following:

const alpha = people.sort((a, b) => {
    const [aLast, aFirst] = a.split(', '); // expected and got ["Bernhard", "Sandra"]
    const [bLast, bFirst] = b.split(', '); // expected and got ["Bethea", "Erin"]
    return aLast > bLast ? 1 : -1;
})

Unless you are using "ASCII" like "Kleenex" (vs facial tissue), no, nothing in JavaScript is ASCII. In particular, strings are counted sequences of UTF-16 code units, one or two of which encode a Unicode codepoint. (This applies to Java, .NET, JavaScript, HTML, XML,….)

A lexicographic ordering is not very useful for human-valued text. Since you ask about alphabetically sorting, you must have a particular language's writing system's alphabet in mind. So, perhaps you want to pass localeCompare to sort.

To support unicode:

objArray.sort(function(a, b) {
   return a.DepartmentName.localeCompare(b.DepartmentName);
});

Example