How I would do this:

Copy// function you can use:
function getSecondPart(str) {
    return str.split('-')[1];
}
// use the function:
alert(getSecondPart("sometext-20202"));

You can use String.slice with String.lastIndexOf:

var str = 'test/category/1';
str.slice(0, str.lastIndexOf('/') + 1);
// => "test/category/"
str.slice(str.lastIndexOf('/') + 1);
// => 1

const streetAddress = addy.substring(0, addy.indexOf(","));

While it’s not the best place for definitive information on what each method does (MDN Web Docs are better for that) W3Schools.com is good for introducing you to syntax.

At least three ways:

A regular expression:

var result = /[^/]*$/.exec("foo/bar/test.html")[0];

...which says "grab the series of characters not containing a slash" ([^/]*) at the end of the string ($). Then it grabs the matched characters from the returned match object by indexing into it ([0]); in a match object, the first entry is the whole matched string. No need for capture groups.

Live example

Using lastIndexOf and substring:

var str = "foo/bar/test.html";
var n = str.lastIndexOf('/');
var result = str.substring(n + 1);

lastIndexOf does what it sounds like it does: It finds the index of the last occurrence of a character (well, string) in a string, returning -1 if not found. Nine times out of ten you probably want to check that return value (if (n !== -1)), but in the above since we're adding 1 to it and calling substring, we'd end up doing str.substring(0) which just returns the string.

Using Array#split

Sudhir and Tom Walters have this covered here and here, but just for completeness:

var parts = "foo/bar/test.html".split("/");
var result = parts[parts.length - 1]; // Or parts.pop();

split splits up a string using the given delimiter, returning an array.

The lastIndexOf / substring solution is probably the most efficient (although one always has to be careful saying anything about JavaScript and performance, since the engines vary so radically from each other), but unless you're doing this thousands of times in a loop, it doesn't matter and I'd strive for clarity of code.