Very close! In your select expression, you have to use a pipe (|) before contains.
This filter produces the expected output.
. - map(select(.Names[] | contains ("data"))) | .[] .Id
The jq Cookbook has an example of the syntax.
Filter objects based on the contents of a key
E.g., I only want objects whose genre key contains "house".
$ json='[{"genre":"deep house"}, {"genre": "progressive house"}, {"genre": "dubstep"}]' $ echo "$json" | jq -c '.[] | select(.genre | contains("house"))' {"genre":"deep house"} {"genre":"progressive house"}
Colin D asks how to preserve the JSON structure of the array, so that the final output is a single JSON array rather than a stream of JSON objects.
The simplest way is to wrap the whole expression in an array constructor:
$ echo "$json" | jq -c '[ .[] | select( .genre | contains("house")) ]'
[{"genre":"deep house"},{"genre":"progressive house"}]
You can also use the map function:
$ echo "$json" | jq -c 'map(select(.genre | contains("house")))'
[{"genre":"deep house"},{"genre":"progressive house"}]
map unpacks the input array, applies the filter to every element, and creates a new array. In other words, map(f) is equivalent to [.[]|f].
Very close! In your select expression, you have to use a pipe (|) before contains.
This filter produces the expected output.
. - map(select(.Names[] | contains ("data"))) | .[] .Id
The jq Cookbook has an example of the syntax.
Filter objects based on the contents of a key
E.g., I only want objects whose genre key contains "house".
$ json='[{"genre":"deep house"}, {"genre": "progressive house"}, {"genre": "dubstep"}]' $ echo "$json" | jq -c '.[] | select(.genre | contains("house"))' {"genre":"deep house"} {"genre":"progressive house"}
Colin D asks how to preserve the JSON structure of the array, so that the final output is a single JSON array rather than a stream of JSON objects.
The simplest way is to wrap the whole expression in an array constructor:
$ echo "$json" | jq -c '[ .[] | select( .genre | contains("house")) ]'
[{"genre":"deep house"},{"genre":"progressive house"}]
You can also use the map function:
$ echo "$json" | jq -c 'map(select(.genre | contains("house")))'
[{"genre":"deep house"},{"genre":"progressive house"}]
map unpacks the input array, applies the filter to every element, and creates a new array. In other words, map(f) is equivalent to [.[]|f].
Here is another solution which uses any/2
map(select(any(.Names[]; contains("data"))|not)|.Id)[]
with the sample data and the -r option it produces:
cb94e7a42732b598ad18a8f27454a886c1aa8bbba6167646d8f064cd86191e2b
a4b7e6f5752d8dcb906a5901f7ab82e403b9dff4eaaeebea767a04bac4aada19
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If "rebuilding" your structure is an option you could do something like this
jq '.Vpcs[]|select(.OwnerId!="abc")|{Vpcs: [.]}'
You could also use del() as:
jq 'del(.Vpcs[]|select(.OwnerId == "abc"))'
Or:
jq 'del(..|select(.OwnerId? == "abc"))'
To delete objects that have a OwnerId attribute set to "abc" wherever they are in the JSON data.
Note that would change {"key":{"OwnerId":"abcd"}} to {}. The "key" is also lost there.