If value is not a plain array, such code will work fine:

var value = { "aaa": "111", "bbb": "222", "ccc": "333" };
var blkstr = [];
$.each(value, function(idx2,val2) {                    
  var str = idx2 + ":" + val2;
  blkstr.push(str);
});
console.log(blkstr.join(", "));

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>

(output will appear in the dev console)

As Felix mentioned, each() is just iterating the array, nothing more.

You can simple use the Array.prototype.join function

const A = [ '6', '6', '.', '5' ];

console.log(A.join(''));

As explain on the Documentation page of Array.prototype.join

The join() method creates and returns a new string by concatenating all of the elements in an array (or an array-like object), separated by commas or a specified separator string. If the array has only one item, then that item will be returned without using the separator.

It can take as parameter the separator which will be use to separate element from the array when they are joined.

let list = ["a", "b", "c", "d"];

list.join("-"); // will return "a-b-c-d"
list.join("/"); // will return "a/b/c/d"
list.join(""); // will return "abcd"

By default the separator is ,. This means if you don't specify which character will be use as the separator it will use the , character

list.join(); // will return a,b,c,d