json array java example

How to create correct JSONArray in Java using JSONObject

stackoverflow.com › questions › 18983185 › how-to-create-correct-jsonarray-in-java-using-jsonobject

Here is some code using java 6 to get you started:

JSONObject jo = new JSONObject();
jo.put("firstName", "John");
jo.put("lastName", "Doe");

JSONArray ja = new JSONArray();
ja.put(jo);

JSONObject mainObj = new JSONObject();
mainObj.put("employees", ja);

Edit: Since there has been a lot of confusion about put vs add here I will attempt to explain the difference. In java 6 org.json.JSONArray contains the put method and in java 7 javax.json contains the add method.

An example of this using the builder pattern in java 7 looks something like this:

JsonObject jo = Json.createObjectBuilder()
  .add("employees", Json.createArrayBuilder()
    .add(Json.createObjectBuilder()
      .add("firstName", "John")
      .add("lastName", "Doe")))
  .build();

Answer from Grammin on Stack Overflow

Stack Overflow

stackoverflow.com › questions › 18983185 › how-to-create-correct-jsonarray-in-java-using-jsonobject

json - How to create correct JSONArray in Java using JSONObject - Stack Overflow

Top answer

1 of 4

282

Here is some code using java 6 to get you started:

JSONObject jo = new JSONObject();
jo.put("firstName", "John");
jo.put("lastName", "Doe");

JSONArray ja = new JSONArray();
ja.put(jo);

JSONObject mainObj = new JSONObject();
mainObj.put("employees", ja);

Edit: Since there has been a lot of confusion about put vs add here I will attempt to explain the difference. In java 6 org.json.JSONArray contains the put method and in java 7 javax.json contains the add method.

An example of this using the builder pattern in java 7 looks something like this:

JsonObject jo = Json.createObjectBuilder()
  .add("employees", Json.createArrayBuilder()
    .add(Json.createObjectBuilder()
      .add("firstName", "John")
      .add("lastName", "Doe")))
  .build();

2 of 4

18

I suppose you're getting this JSON from a server or a file, and you want to create a JSONArray object out of it.

String strJSON = ""; // your string goes here
JSONArray jArray = (JSONArray) new JSONTokener(strJSON).nextValue();
// once you get the array, you may check items like
JSONOBject jObject = jArray.getJSONObject(0);

Hope this helps :)

Coderanch

coderanch.com › t › 706235 › java › Identifying-JSONObject-JSONArray

Identifying JSONObject or JSONArray (Java in General forum at Coderanch)

Here are partial examples: This is the normal string that works: This is the response that causes the parser exception: ... Sam Ritter wrote:... is there a way to determine which sb is before running the parser? The easiest way is probably to use the parser to determine if JSON element is what you are expecting - as you have found, it will throw an exception if it is the wrong type of element.

Discussions

How to turn json objects into an array of json objects using Java?

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r/javahelp

7

4

June 28, 2022

New to Java, wanted some help with reading .json object arrays.

it gives me an error What's the error? More on reddit.com

r/javahelp

11

1

January 20, 2024

How to parse Json array with 2 or more different types using Jackson?

http://www.baeldung.com/jackson-inheritance

You'll need to have those types inherit from one base class though.

Also; that is really bad JSON.

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