This isn't a single JSON object. You have an array of JSON objects. You need to loop over array first and then access each object. Maybe the following kickoff example is helpful:
var arrayOfObjects = [{
"id": 28,
"Title": "Sweden"
}, {
"id": 56,
"Title": "USA"
}, {
"id": 89,
"Title": "England"
}];
for (var i = 0; i < arrayOfObjects.length; i++) {
var object = arrayOfObjects[i];
for (var property in object) {
alert('item ' + i + ': ' + property + '=' + object[property]);
}
// If property names are known beforehand, you can also just do e.g.
// alert(object.id + ',' + object.Title);
}
If the array of JSON objects is actually passed in as a plain vanilla string, then you would indeed need eval() here.
var string = '[{"id":28,"Title":"Sweden"}, {"id":56,"Title":"USA"}, {"id":89,"Title":"England"}]';
var arrayOfObjects = eval(string);
// ...
To learn more about JSON, check MDN web docs: Working with JSON .
Answer from BalusC on Stack OverflowThis isn't a single JSON object. You have an array of JSON objects. You need to loop over array first and then access each object. Maybe the following kickoff example is helpful:
var arrayOfObjects = [{
"id": 28,
"Title": "Sweden"
}, {
"id": 56,
"Title": "USA"
}, {
"id": 89,
"Title": "England"
}];
for (var i = 0; i < arrayOfObjects.length; i++) {
var object = arrayOfObjects[i];
for (var property in object) {
alert('item ' + i + ': ' + property + '=' + object[property]);
}
// If property names are known beforehand, you can also just do e.g.
// alert(object.id + ',' + object.Title);
}
If the array of JSON objects is actually passed in as a plain vanilla string, then you would indeed need eval() here.
var string = '[{"id":28,"Title":"Sweden"}, {"id":56,"Title":"USA"}, {"id":89,"Title":"England"}]';
var arrayOfObjects = eval(string);
// ...
To learn more about JSON, check MDN web docs: Working with JSON .
This is your dataArray:
[
{
"id":28,
"Title":"Sweden"
},
{
"id":56,
"Title":"USA"
},
{
"id":89,
"Title":"England"
}
]
Then parseJson can be used:
$(jQuery.parseJSON(JSON.stringify(dataArray))).each(function() {
var ID = this.id;
var TITLE = this.Title;
});
Videos
// You can declare restaurants as an array of restaurant objects
restaurants =
[
{
"location" : "123 Road Dr",
"city_state" : "MyCity ST",
"phone" : "555-555-5555",
"distance" : "1"
},
{
"location" : "456 Avenue Crt",
"city_state" : "MyTown AL",
"phone" : "555-867-5309",
"distance" : "0"
}
];
// Then operate on them with a for loop as such
for (var i = 0; i< restaurants.length; i++) {
restaurants[i].distance = restaurants[i].distance; // Or some other logic.
}
// Finally you can sort them using an anonymous function like this
restaurants.sort(function(a,b) { return a.distance - b.distance; });
First of all, this is not JSON at all, you are just using Javascript objects. JSON is a text format for representing objects, there is no such thing as a "JSON object".
You can create a constructor for your objects like this:
function Restaurant(location, city_state, phone, distance) {
this.location = location;
this.city_state = city_state;
this.phone = phone;
// here you can add some logic for the distance field, if you like:
this.distance = distance;
}
// create an array restaurants
var restaurants = [];
// add objects to the array
restaurants.push(new Restaurant("123 Road Dr", "MyCity ST", "555-555-5555", 0));
restaurants.push(new Restaurant("123 Road Dr", "MyCity ST", "555-555-5555", 0));
restaurants.push(new Restaurant("123 Road Dr", "MyCity ST", "555-555-5555", 0));
var json_data = {"2013-01-21":1,"2013-01-22":7};
var result = [];
for(var i in json_data)
result.push([i, json_data [i]]);
var data = new google.visualization.DataTable();
data.addColumn('string', 'Topping');
data.addColumn('number', 'Slices');
data.addRows(result);
http://jsfiddle.net/MV5rj/
If you have a well-formed JSON string, you should be able to do
var as = JSON.parse(jstring);
I do this all the time when transfering arrays through AJAX.
Real silly question but are both formats below correct? And if so when would you use one over the other?
'{"name":"John", "age":30, "car":null}'
'[{"name":"John", "age":30, "car":null}]'