If you want two objects with the same elements but in a different order to compare equal, then the obvious thing to do is compare sorted copies of them - for instance, for the dictionaries represented by your JSON strings a and b:

import json

a = json.loads("""
{
    "errors": [
        {"error": "invalid", "field": "email"},
        {"error": "required", "field": "name"}
    ],
    "success": false
}
""")

b = json.loads("""
{
    "success": false,
    "errors": [
        {"error": "required", "field": "name"},
        {"error": "invalid", "field": "email"}
    ]
}
""")
>>> sorted(a.items()) == sorted(b.items())
False

... but that doesn't work, because in each case, the "errors" item of the top-level dict is a list with the same elements in a different order, and sorted() doesn't try to sort anything except the "top" level of an iterable.

To fix that, we can define an ordered function which will recursively sort any lists it finds (and convert dictionaries to lists of (key, value) pairs so that they're orderable):

def ordered(obj):
    if isinstance(obj, dict):
        return sorted((k, ordered(v)) for k, v in obj.items())
    if isinstance(obj, list):
        return sorted(ordered(x) for x in obj)
    else:
        return obj

If we apply this function to a and b, the results compare equal:

>>> ordered(a) == ordered(b)
True
Answer from Zero Piraeus on Stack Overflow
Top answer
1 of 12
225

If you want two objects with the same elements but in a different order to compare equal, then the obvious thing to do is compare sorted copies of them - for instance, for the dictionaries represented by your JSON strings a and b:

import json

a = json.loads("""
{
    "errors": [
        {"error": "invalid", "field": "email"},
        {"error": "required", "field": "name"}
    ],
    "success": false
}
""")

b = json.loads("""
{
    "success": false,
    "errors": [
        {"error": "required", "field": "name"},
        {"error": "invalid", "field": "email"}
    ]
}
""")
>>> sorted(a.items()) == sorted(b.items())
False

... but that doesn't work, because in each case, the "errors" item of the top-level dict is a list with the same elements in a different order, and sorted() doesn't try to sort anything except the "top" level of an iterable.

To fix that, we can define an ordered function which will recursively sort any lists it finds (and convert dictionaries to lists of (key, value) pairs so that they're orderable):

def ordered(obj):
    if isinstance(obj, dict):
        return sorted((k, ordered(v)) for k, v in obj.items())
    if isinstance(obj, list):
        return sorted(ordered(x) for x in obj)
    else:
        return obj

If we apply this function to a and b, the results compare equal:

>>> ordered(a) == ordered(b)
True
2 of 12
94

Another way could be to use json.dumps(X, sort_keys=True) option:

import json
a, b = json.dumps(a, sort_keys=True), json.dumps(b, sort_keys=True)
a == b # a normal string comparison

This works for nested dictionaries and lists.

🌐
PyPI
pypi.org › project › jsoncomparison
jsoncomparison · PyPI
This package is designed to compare two objects with a JSON-like structure and data types.
      » pip install jsoncomparison
    
Published   May 17, 2021
Version   1.1.0
🌐
Reddit
reddit.com › r/learnpython › comparing two json files for differences
r/learnpython on Reddit: Comparing Two JSON Files For Differences
August 29, 2022 -

I need to compare two JSON files that contain a list of dictionaries whose basic format is:

[{"protocol": "S", "type": "", "network": "0.0.0.0", "mask": "0", "distance": "254", "metric": "0", "nexthop_ip": "192.168.122.1", "nexthop_if": "", "uptime": ""}, {"protocol": "O", "type": "", "network": "10.129.30.0", "mask": "24", "distance": "110", "metric": "2", "nexthop_ip": "172.20.10.1", "nexthop_if": "GigabitEthernet0/1", "uptime": "08:58:25"}]

Though there are many, many more dictionary items in the list than that shown above. I am not quite sure how best to go about comparing the files to spot differences and return or save those difference to another file, preferably in JSON format, though a CSV would be fine too.

The one gotcha that there may be is I need to exclude, at a minimum, the uptime value as it is constantly changing so it will of course trigger anything looking for changes. Can anyone help get me started please?

🌐
Medium
medium.com › @abedmaatalla › compare-two-json-objects-python-c2f763c943b0
Compare two JSON objects (Python) | by Abed MAATALLA | Medium
August 4, 2022 - Programmatically, one can write ... writing code and all, This is where deepdiff comes in handy. Deepdiff is a powerful python library to compare 2 dictionaries....
🌐
GitHub
github.com › monsur › jsoncompare
GitHub - monsur/jsoncompare: A simple utility to compare two JSON objects.
jsoncompare is a simple Python utility for comparing two JSON objects USAGE python jsoncompare.py <item1> <item2> Where item1 and item2 are either a file or a url containing a JSON object.
Starred by 22 users
Forked by 27 users
Languages   Python 100.0% | Python 100.0%
🌐
GeeksforGeeks
geeksforgeeks.org › python › how-to-compare-json-objects-regardless-of-order-in-python
How to compare JSON objects regardless of order in Python? - GeeksforGeeks
July 23, 2025 - import json # JSON string json_1 = '{"Name":"GFG", "Class": "Website", "Domain":"CS/IT", "CEO":"Sandeep Jain"}' json_2 = '{"CEO":"Sandeep Jain", "Domain":"CS/IT","Name": "GFG","Class": "Website"}' # Converting string into Python dictionaries json_dict1 = json.loads(json_1) json_dict2 = json.loads(json_2) print(sorted(json_dict1.items()) == sorted(json_dict2.items()))
🌐
PyPI
pypi.org › project › json-diff
json-diff · PyPI
Generates diff between two JSON files
      » pip install json-diff
    
Published   Aug 25, 2019
Version   1.5.0
🌐
GitHub
github.com › rugleb › JsonCompare
GitHub - rugleb/JsonCompare: The Python JSON Comparison package · GitHub
from jsoncomparison import Compare, NO_DIFF expected = { "project": { "name": "jsoncomparison", "version": "0.1", "license": "MIT", "language": { "name": "python", "versions": [ 3.5, 3.6 ] } }, "os": "linux" } actual = { "project": { "name": "jsoncomparison", "version": 0.1, "license": "Apache 2.0", "language": { "name": "python", "versions": [ 3.6 ] } } } diff = Compare().check(expected, actual) assert diff != NO_DIFF ·
Starred by 68 users
Forked by 23 users
Languages   Python 95.8% | Makefile 4.2%
Find elsewhere
🌐
TutorialsPoint
tutorialspoint.com › how-to-compare-json-objects-regardless-of-order-in-python
How to Compare JSON Objects Regardless of Order in Python?
In this article, we will explore three different methods for comparing JSON objects in Python regardless of their order. We will discuss techniques for converting JSON objects to dictionaries, sorting JSON objects, and utilizing the jsondiff third?party library to compare JSON objects.
🌐
GitHub
gist.github.com › magnetikonline › 845400198a8e4e4648746a675e955af3
Python - comparing JSON data structures. · GitHub
A function compare_json_data(source_data_a,source_data_b), accepting structures populated with data loaded from json.load() and comparing for equality.
🌐
GitHub
github.com › cpatrickalves › json-diff
GitHub - cpatrickalves/json-diff: A Python script that compares two JSON files and shows their differences.
A Python script that compares two JSON files and shows their differences. - cpatrickalves/json-diff
Author   cpatrickalves
🌐
Quora
quora.com › How-do-I-compare-two-JSON-files-in-Python
How to compare two JSON files in Python - Quora
Answer (1 of 5): In Python, the [code ]==[/code] operator is recursive. So if you read in two JSON files, you can compare them like this: [code]doc1 == doc2 [/code]In python, key ordering is preserved, so these two will be printed differently: [code]d1 = {'a': 3, 'b': 4} d2 = {'b': 4, 'a': 3} [...
🌐
Deviloper's Blog
deviloper.in › advanced-json-diff-checker-in-python-an-in-depth-guide
Advanced JSON Diff Checker in Python: An In-Depth Guide
September 9, 2024 - Congratulations! You've successfully created an advanced JSON diff checker in Python using the deepdiff and termcolor libraries. You've learned how to compare JSON objects with precision and present the results in a user-friendly and visually appealing format.
🌐
JSON Diff
jsondiff.com
JSON Diff - The semantic JSON compare tool
Validate, format, and compare two JSON documents. See the differences between the objects instead of just the new lines and mixed up properties.
🌐
The Coding Forums
thecodingforums.com › archive › archive › python
how to compare two json file line by line using python? | Python | Coding Forums
May 28, 2013 - hi, how to compare two json file line by line using python? Actually I am doing it in this way.. import simplejson as json def compare(): newJsonFile= open('newData.json') lastJsonFile= open('version1.json') newLines = newJsonFile.readlines() print newLines sortedNew = sorted([repr(x) for x in...
🌐
PyPI
pypi.org › project › json-files-compare
json-files-compare · PyPI
Json-compare is a simple package that allows you to easily and fastly compare two .json files. Support key and multi-key comparison.
      » pip install json-files-compare
    
Published   Feb 05, 2023
Version   1.0.1
🌐
Reddit
reddit.com › r/learnpython › diff two large json array or objects
r/learnpython on Reddit: Diff two large JSON array or objects
February 26, 2022 -

I have a Python lambda function downloading a large excel file and converting it to JSON.

This file will be downloaded at least once a day (as the data can change)

I need to push the changed/updated data to an API.

Is there a way for me to compare two JSON files and output the diff?

It would be perfect if it would output multiple arrays of objects.

1 array of objects that have changed (I don’t care what has changed, just need to know that it has)

1 array of removed/deleted objects.

Top answer
1 of 1
4
Yes Firstly you have to load json data in python dictionary using json module/package After that jsondiff module/package help you check different This module/package also compare list,set,etc.👌 If will return empty dictionary {} if there is no different👍 import jsondiff oldJson = {1:"a",2:"b",3:"c"} newJson = {1:1,4:4} r = jsondiff.diff(oldJson,newJson) if r : print(r) else: print("404,No Different Found!") Output: {1: 1, 4: 4, delete: [2, 3]} 😀 json.diff take 1st arg oldJson means from which we are checking different & 2nd newJson. There are 3 syntax 🎲 : compact ( default ) Any Change in Value of key & new insrted key will display normaly symmetric Inserted & delete show differently change show normally explicit 👀 It is detailed Inserted Deleted Changed Show differently import jsondiff oldJson = {1:"a",2:"b",3:"c"} newJson = {1:1,4:4} r = jsondiff.diff(oldJson,newJson,syntax="explicit") if r: print(r) else: print("404,No Different Found!") Output : {insert: {4: 4}, update: {1: 1}, delete: [2, 3]} 😃 Finally 🔥,Now you doubt about how to access them You can access them using symbols eg. r[jsondiff.symbols.insert] OR from jsondiff import symbols r[symbols.insert] There are some other symbols which use in different compare like list,set, etc Note : if you try using insert in compact & update in compact & symmetric then you will get KeyError 😔 because those not exist there import jsondiff from jsondiff import symbols oldJson = {1:"a",2:"b",3:"c"} newJson = {1:1,4:4} r = jsondiff.diff(oldJson,newJson,syntax="explicit") if r: print("Deleted keys are ",r[symbols.delete]) else: print("404,No Different Found!") Output : Deleted keys are [2, 3] 🥳 Thanks for reading 😂
🌐
Readthedocs
recursive-diff.readthedocs.io
recursive_diff: Compare two Python data structures — recursive_diff ...
Again, it is very frequently needed to identify where differences are, and apply tolerance to the comparison. This module offers the function recursive_diff(), which crawls through two arbitrarily large nested JSON-like structures and dumps out all the differences. Python-specific data types, such as set and tuple, are also supported.
🌐
Edureka Community
edureka.co › home › community › categories › python › how to compare two json objects with the same...
How to compare two JSON objects with the same elements in a different order equal | Edureka Community
August 7, 2020 - How can I test whether two JSON objects are equal in python, disregarding the order of lists? For ... the order of the "errors" lists are different.
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Keploy
keploy.io › home › community › how to compare two json files?
How to compare two JSON files? | Keploy Blog
June 9, 2024 - Find differences between two JSON files using Python, VS Code, and free online JSON diff tools. Ideal for developers and testers.