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Parsing JSON object in PHP using json_decode

stackoverflow.com › questions › 4035742 › parsing-json-object-in-php-using-json-decode

This appears to work:

$url = 'http://www.worldweatheronline.com/feed/weather.ashx?q=schruns,austria&format=json&num_of_days=5&key=8f2d1ea151085304102710%22';
$content = file_get_contents(json = json_decode($content, true);

foreach($json['data']['weather'] as $item) {
    print $item['date'];
    print ' - ';
    print $item['weatherDesc'][0]['value'];
    print ' - ';
    print '<img src="' . $item['weatherIconUrl'][0]['value'] . '" border="0" alt="" />';
    print '<br>';
}

If you set the second parameter of json_decode to true, you get an array, so you cant use the -> syntax. I would also suggest you install the JSONview Firefox extension, so you can view generated json documents in a nice formatted tree view similiar to how Firefox displays XML structures. This makes things a lot easier.

Answer from BMBM on Stack Overflow

PHP

php.net › manual › en › function.json-decode.php

PHP: json_decode - Manual

JSON can be decoded to PHP arrays by using the $associative = true option. Be wary that associative arrays in PHP can be a "list" or "object" when converted to/from JSON, depending on the keys (of absence of them).

W3Schools

w3schools.com › php › func_json_decode.asp

PHP json_decode() Function

Store JSON data in a PHP variable, and then decode it into a PHP object.

Top answer

1 of 7

This appears to work:

$url = 'http://www.worldweatheronline.com/feed/weather.ashx?q=schruns,austria&format=json&num_of_days=5&key=8f2d1ea151085304102710%22';
$content = file_get_contents(json = json_decode($content, true);

foreach($json['data']['weather'] as $item) {
    print $item['date'];
    print ' - ';
    print $item['weatherDesc'][0]['value'];
    print ' - ';
    print '<img src="' . $item['weatherIconUrl'][0]['value'] . '" border="0" alt="" />';
    print '<br>';
}

2 of 7

If you use the following instead:

$json = file_get_contents(data = json_decode($json, TRUE);

The TRUE returns an array instead of an object.

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Top answer

1 of 12

983

As per the documentation, you need to specify true as the second argument if you want an associative array instead of an object from json_decode. This would be the code:

$result = json_decode($jsondata, true);

If you want integer keys instead of whatever the property names are:

$result = array_values(json_decode($jsondata, true));

However, with your current decode you just access it as an object:

print_r($obj->Result);

2 of 12

try this

$json_string = 'http://www.domain.com/jsondata.json';
$jsondata = file_get_contents($json_string);
$obj = json_decode($jsondata,true);
echo "<pre>";
print_r($obj);

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reddit.com › r/phphelp › json_decode returns null and i don't understand why

r/PHPhelp on Reddit: json_decode returns NULL and I don't understand why

April 26, 2024 -

I have a json_files.php file where I'm placing several JSON objects. One of them is the following:

$jsonGreetingsListEnglish = '{
    "1": "Hello",
    "2": "Hi there",
    "3": "Morning",
    "4": "Evening",
    "5": "Hey",
    "6": "Howdy",
    "7": "Hiya",
    "8": "Welcome",
    "9": "Hi",
    "10": "Yo!",
    "11": "Sup?"
    "12": "Nice"
    "13": "What up?"
    "14": "Aloha"
    "15": "Oi!",
    "16": "Ahoy!",
    "17": "Cheers"
    "18": "Alright?",
    "19": "Hey yo!",
    "20": "Good day"
}';

On a second file I'm decoding it:

include_once "json_files.php";
$greetingsListEnglish = json_decode($jsonGreetingsListEnglish, true);

Later in the same (second) file, I declared this function:

/* Chooses random greeting and encodes it
Retains unencoded greeting for output */
function generateEnglishGreeting() {
    global $greetingsListEnglish;
    $index = array_rand($greetingsListEnglish);
    $unencodedGreeting = $greetingsListEnglish[$index];
    $encodedGreeting = mb_convert_encoding($unencodedGreeting, "UTF-16LE");
    return [$unencodedGreeting, $encodedGreeting];
}

However, when I called this function I get an error that says the decoded array is empty:

Fatal error: Uncaught TypeError: array_rand(): Argument #1 ($array) must be of type array, null given in
C:\xampp\htdocs\join_avenue_visitor_generator\visitor_data_functions.php:88 Stack trace: #0

I ran this to check and when the script runs it always prints "Empty":

if (!empty($greetingsListEnglish)) {
    echo "Not empty";
} else {
    echo "Empty";
}

Am I messing up some syntax or something?

Update: As mentioned in several replies, there were several commas missing. Thanks for all the extra advice.