You get the error because you are trying to turn a stdClass object into a string, something it doesn't support.

Instead of echo $decoded_traces try var_dump($decoded_traces) - that will give a diagnostic view of the object you've decoded (which I presume is what you wanted). You should find it looks like this

class stdClass#1 (2) {
  public $Coords =>
  array(5) {
    [0] =>
    class stdClass#2 (4) {
      public $Accuracy =>
      string(2) "65"
      public $Latitude =>
      string(18) "53.277720488429026"
      public $Longitude =>
      string(18) "-9.012038778269686"
      public $Timestamp =>
      string(39) "Fri Jul 05 2013 11:59:34 GMT+0100 (IST)"
    }
    [1] => (more of the same, edited for brevity)
    [2] =>
    [3] =>
    [4] =>
  }
  public $Scan =>
  string(8) "Whatever"
}

By default, json_encode will create stdClass objects like the above. If you would prefer an associative array, pass true as the second parameter to json_decode, e.g. $decoded_traces=json_decode($traces, true);

As a further aside, although stdClass can't be turned into a string, your own classes can - a class which implements the __toString magic method could be converted to a string!

use true as second parameter in json_decode

$arr = json_decode($your_array,true); // it will create array

working example http://codepad.viper-7.com/0Dxxm8

json_decode returns an object by default. In your case, you need an array. Add 2nd param as true as below:

json_decode($var, true);

You may need to do as

echo "JobID: '{$comm[0]->JobID}'"; 

So in the query u can use it as where some_col = '{$comm[0]->JobID}'

The function json_decode does not return a string.

Have a look at the documentation for the function.

https://www.php.net/function.json-decode.php

The problem is that you're trying to echo the object. The following code is faulty.

echo $issue_json;

You can use var_dump to see the structure of the object returned from json_decode.

var_dump($issue_json);

You see, the json_decode() method doesn’t return our JSON as a PHP array; it uses a stdClass object to represent our data. Let’s instead access our object key as an object attribute.

echo $stateList->AL;

If you provide true as the second parameter to the function we will receive our PHP array exactly as expected.

$stateList = json_decode($states,true);
echo $stateList['AL'];

Use the second parameter of json_decode to make it return an array:

$result = json_decode($data, true);

$price1 = DB::table('dishes')->select('price', 'chg_porridge')->where([
                ['name', '=', $opt1],
            ])->get();        
$values = json_decode(json_encode($price1), true);

try

var_dump($json);

This allows you to print out the details of objects and other non-primative types.

Echoing is used for strings - Your json decoded string will be an object of type stdClass

See var_dump http://php.net/manual/en/function.var-dump.php

See echo http://php.net/manual/en/function.echo.php