There is no question that the future of parsing in Kotlin will be with kotlinx.serialization. It is part of Kotlin libraries. Version kotlinx.serialization 1.0 is finally released
https://github.com/Kotlin/kotlinx.serialization
import kotlinx.serialization.*
import kotlinx.serialization.json.Json
@Serializable
data class MyModel(val a: Int, @Optional val b: String = "42")
fun main(args: Array<String>) {
// serializing objects
val jsonData = Json.encodeToString(MyModel.serializer(), MyModel(42))
println(jsonData) // {"a": 42, "b": "42"}
// serializing lists
val jsonList = Json.encodeToString(MyModel.serializer().list, listOf(MyModel(42)))
println(jsonList) // [{"a": 42, "b": "42"}]
// parsing data back
val obj = Json.decodeFromString(MyModel.serializer(), """{"a":42}""")
println(obj) // MyModel(a=42, b="42")
}
Answer from Elisha Sterngold on Stack OverflowThere is no question that the future of parsing in Kotlin will be with kotlinx.serialization. It is part of Kotlin libraries. Version kotlinx.serialization 1.0 is finally released
https://github.com/Kotlin/kotlinx.serialization
import kotlinx.serialization.*
import kotlinx.serialization.json.Json
@Serializable
data class MyModel(val a: Int, @Optional val b: String = "42")
fun main(args: Array<String>) {
// serializing objects
val jsonData = Json.encodeToString(MyModel.serializer(), MyModel(42))
println(jsonData) // {"a": 42, "b": "42"}
// serializing lists
val jsonList = Json.encodeToString(MyModel.serializer().list, listOf(MyModel(42)))
println(jsonList) // [{"a": 42, "b": "42"}]
// parsing data back
val obj = Json.decodeFromString(MyModel.serializer(), """{"a":42}""")
println(obj) // MyModel(a=42, b="42")
}
You can use this library https://github.com/cbeust/klaxon
Klaxon is a lightweight library to parse JSON in Kotlin.
How to get value from JSON in Kotlin?
How to create a JSON object from a string in Kotlin?
How to pass JSON in Kotlin?
In 2019 no-one is really parsing JSON manually. It's much easier to use Gson library. It takes as an input your object and spits out JSON string and vice-versa.
Example:
data class MyClass(@SerializedName("s1") val s1: Int)
val myClass: MyClass = Gson().fromJson(data, MyClass::class.java)
val outputJson: String = Gson().toJson(myClass)
This way you're not working with JSON string directly but rather with Kotlin object which is type-safe and more convenient. Look at the docs. It's pretty big and easy to understand
Here is some tutorials:
- https://www.youtube.com/watch?v=f-kcvxYZrB4
- http://www.studytrails.com/java/json/java-google-json-introduction/
- https://www.tutorialspoint.com/gson/index.htm
UPDATE: If you really want to use JSONObject then use its constructor with a string parameter which parses your JSON string automatically.
val jsonObject = JSONObject(data)
Best way is using kotlinx.serialization. turn a Kotlin object into its JSON representation and back marking its class with the @Serializable annotation, and using the provided encodeToString and decodeFromString<T> extension functions on the Json object:
import kotlinx.serialization.*
import kotlinx.serialization.json.*
@Serializable
data class User(val name: String, val yearOfBirth: Int)
// Serialization (Kotlin object to JSON string)
val data = User("Louis", 1901)
val string = Json.encodeToString(data)
println(string) // {"name":"Louis","yearOfBirth":1901}
// Deserialization (JSON string to Kotlin object)
val obj = Json.decodeFromString<User>(string)
println(obj) // User(name=Louis, yearOfBirth=1901)
Further examples: https://blog.jetbrains.com/kotlin/2020/10/kotlinx-serialization-1-0-released/