Just in case, if someone is looking for a similar problem...
Most solutions given here are one line and are quite readable and simple. Just wanted to add one more that does not need the use of lambda(I am assuming that you are trying to use lambda just for the sake of making it a one line code). Instead, you can use a simple list comprehension.
[print(i) for i in x]
BTW, the return values will be a list of Nones.
Top answer 1 of 10
46
Just in case, if someone is looking for a similar problem...
Most solutions given here are one line and are quite readable and simple. Just wanted to add one more that does not need the use of lambda(I am assuming that you are trying to use lambda just for the sake of making it a one line code). Instead, you can use a simple list comprehension.
[print(i) for i in x]
BTW, the return values will be a list of Nones.
2 of 10
26
Since a for loop is a statement (as is print, in Python 2.x), you cannot include it in a lambda expression. Instead, you need to use the write method on sys.stdout along with the join method.
x = lambda x: sys.stdout.write("\n".join(x) + "\n")
Delft Stack
delftstack.com › home › howto › python › use lambda functions alongside a for loop
How to Use Lambda Functions With the for Loop in Python | Delft Stack
February 9, 2025 - For loops can be used to iterate over other sequences such as tuples, strings, dictionaries, and sets. Although lambda functions can only have one expression, there are no restrictions on the data types that can be used. The example below illustrates how we can iterate over a list of strings ...
python - Lambda in a loop - Stack Overflow
You can also fix the scoping inside the lambda expression ... However in general this is not good practice as you have changed the signature of your function. ... Is this same problem that occurs with defining closures within for-loops using def, that in Python for-loops don't get their own scopes? 2020-04-07T02:35:01.52Z+00:00 ... @robbie_c An interesting behavior to support your first example... More on stackoverflow.com
Issue with creating lambda functions using for loop
If you want the function to take n from outer scope, don't put it in as a parameter. arr = [] for n in range(1,5): arr.append(lambda: 5+n) More on reddit.com
11
10
February 7, 2022Can somebody explain to me why using a for loop here changes the behavior?
The problem is because filter return an iterator and not an actual list. x isn't evaluated until you execute the iterator and at that time (when you call list) x=3 There's a trick to evaluate x when declaring the lambda : for x in [2,3]: f = filter(lambda n, m=x: n%m, f) More on reddit.com
15
73
June 5, 2022I still don't understand the benefit of lambda functions
they're just...functions with different syntax That's exactly what they are. The main syntactical difference between the two is that a regular function definition is a statement, whereas a lambda function definition is an expression. Lambda functions can therefore be defined and then passed to another function in one step, without having to go through a local name (that's also why lambda functions are sometimes called anonymous functions, they don't necessarily have a particular name). Lambda is a convenience feature to more easily define small, one-off functions. More on reddit.com
118
320
January 23, 2022Videos
07:39
Python Crash Course: Part 13 - Using Lambdas - YouTube
02:42
python lambda for loop example - YouTube
04:13
Loops In Python I While Loop | For Loops | Lambda Function | ...
08:20
Lambda in a Loop is a Code Smell - YouTube
Python Lambda Functions?? - YouTube
01:21
PYTHON : Lambda in a loop - YouTube
GeeksforGeeks
geeksforgeeks.org › python › python-iterating-with-python-lambda
Python: Iterating With Python Lambda - GeeksforGeeks
July 23, 2025 - # Iterating With Python Lambdas # list of numbers l1 = [4, 2, 13, 21, 5] l2 = [] # run for loop to iterate over list for i in l1: # lambda function to make square # of number temp=lambda i:i**2 # save in list2 l2.append(temp(i)) # print list ...
Caisbalderas
caisbalderas.com › blog › iterating-with-python-lambdas
Iterating With Python Lambdas - Carlos Isaac Balderas
[v * 5 for v in x if v % 2] #list comprehension map(lambda for v: v * 5, for filter(lambda for v: if v % 2, in x)) #"pseudo" lambda and list comprehension map(lambda v : v * 5, filter(lambda u : u % 2, x)) #lambda, just a 'rearrangement' of what we had before · Going all the way. Going deeper, our loops iterate through x, iterate through y, and adds the sum of the values to z.
EyeHunts
tutorial.eyehunts.com › home › python lambda for loop | example code
Python lambda for loop | Example code - Tutorial - By EyeHunts
May 30, 2022 - Answer: Simply create a list of lambdas in a python loop using the following code. def square(x): return lambda: x * x lst = [square(i) for i in [1, 2, 3, 4, 5]] for f in lst: print(f()) ... Another way: Using a functional programming construct ...
OpenGenus
iq.opengenus.org › python-lambda-for-loop
Python lambda for loop
November 27, 2022 - The trick is to write for loop in one line expression which can be done as follows: ... As this is a one line expression, we can directly include this in a lambda. Following Python code traverses through a list of integers using lambda which in turn uses for loop:
W3Schools
w3schools.com › python › python_for_loops.asp
Python For Loops
Python Dictionaries Access Items ... Items Loop Dictionaries Copy Dictionaries Nested Dictionaries Dictionary Methods Dictionary Exercises Code Challenge Python If...Else · Python If Python Elif Python Else Shorthand If Logical Operators Nested If Pass Statement Code Challenge Python Match ... Python Functions Python Arguments Python *args / **kwargs Python Scope Python Decorators Python Lambda Python Recursion ...
W3Schools
w3schools.com › python › python_lambda.asp
Python Lambda
Python Dictionaries Access Items Change Items Add Items Remove Items Loop Dictionaries Copy Dictionaries Nested Dictionaries Dictionary Methods Dictionary Exercises Code Challenge Python If...Else · Python If Python Elif Python Else Shorthand If Logical Operators Nested If Pass Statement Code Challenge Python Match ... Python Functions Python Arguments Python *args / **kwargs Python Scope Python Decorators Python Lambda Python Recursion Python Generators Code Challenge Python Range
TutorialsPoint
tutorialspoint.com › How-to-create-a-lambda-inside-a-Python-loop
How to create a lambda inside a Python loop?
You can create a list of lambdas in a python loop using the following syntax − · def square(x): return lambda : x*x listOfLambdas = [square(i) for i in [1,2,3,4,5]] for f in listOfLambdas: print f() This will give the output − · 1 4 9 16 25 · You can also achieve this using a functional ...
GeeksforGeeks
geeksforgeeks.org › python › why-do-python-lambda-defined-in-a-loop-with-different-values-all-return-the-same-result
Why do Python lambda defined in a loop with different values all return the same result? - GeeksforGeeks
July 23, 2025 - Here is an example of a simple lambda function that takes a single argument and returns its square: ... # Lambda function to return # square of a number square = lambda x: x ** 2 # Printing the square of a number # using square lambda function ...
Codecademy
codecademy.com › forum_questions › 51617d5b0f2389811b00460e
Can we Use Loops such as for and while inside a lambda function???? | Codecademy
It loop through garbled and put every element unequal to “X” into message. There is a loop and a conditional in there already ... No you can’t. Lambda is an expression not a statement.
Finxter
blog.finxter.com › home › learn python blog › python for loop inside lambda
Python For Loop Inside Lambda - Be on the Right Side of Change
June 13, 2021 - The following question is a classic ... execute this code in our console to find out what happens! y = "hello and welcome" x = y[0:] x = lambda x: (for i in x : print i)...
IncludeHelp
includehelp.com › python › iterating-with-python-lambda.aspx
Iterating with Python Lambda
# Python program to demonstrate the example to # iterate with lambda # list of integers numbers = [10, 15, 20, 25, 30] # list to store cubes cubes = [] # for loop to iterate over list for x in numbers: # lambda expression to find cubes res = lambda x: x**3 # appending to the list (cubes) ...
DigitalOcean
digitalocean.com › community › tutorials › lambda-expression-python
Python Lambda Expressions Explained with Examples | DigitalOcean
July 8, 2025 - Master Python lambda expressions with this step-by-step guide. Learn syntax, use cases, and common mistakes for writing cleaner functional code.
freeCodeCamp
freecodecamp.org › news › python-lambda-function-explained
How the Python Lambda Function Works – Explained with Examples
December 17, 2024 - You can manipulate all of the values in a series by using the lambda function. For example, if I have a data frame with the following columns and want to convert the values in the name column to lower case, I can do so using the Pandas apply function and a Python lambda function like this:
Real Python
realpython.com › python-lambda
How to Use Python Lambda Functions – Real Python
December 1, 2023 - In this step-by-step tutorial, you'll learn about Python lambda functions. You'll see how they compare with regular functions and how you can use them in accordance with best practices.
GitHub
gist.github.com › gisbi-kim › 2e5648225cc118fc72ac933ef63c2d64
Why Lambda in a Loop is a Code Smell in python? Also it happens in c++? · GitHub
So, if the lambda uses loop variables, ... when the function was defined. funcs = [lambda x: x + i for i in range(3)] for func in funcs: print(func(0)) # Output: 2 2 2, not 0 1 2 as might be expected...
Finxter
blog.finxter.com › home › learn python blog › python one line for loop lambda
Python One Line For Loop Lambda - Be on the Right Side of Change
July 23, 2020 - The simple formula is [expression + context]. ... Context: What elements to select? The context consists of an arbitrary number of for and if statements. The example [x for x in range(3)] creates the list [0, 1, 2].
Top answer 1 of 4
125
You need to bind d for each function created. One way to do that is to pass it as a parameter with a default value:
lambda d=d: self.root.change_directory(d)
Now the d inside the function uses the parameter, even though it has the same name, and the default value for that is evaluated when the function is created. To help you see this:
lambda bound_d=d: self.root.change_directory(bound_d)
Remember how default values work, such as for mutable objects like lists and dicts, because you are binding an object.
This idiom of parameters with default values is common enough, but may fail if you introspect function parameters and determine what to do based on their presence. You can avoid the parameter with another closure:
(lambda d=d: lambda: self.root.change_directory(d))()
# or
(lambda d: lambda: self.root.change_directory(d))(d)
2 of 4
34
This is due to the point at which d is being bound. The lambda functions all point at the variable d rather than the current value of it, so when you update d in the next iteration, this update is seen across all your functions.
For a simpler example:
funcs = []
for x in [1,2,3]:
funcs.append(lambda: x)
for f in funcs:
print f()
# output:
3
3
3
You can get around this by adding an additional function, like so:
def makeFunc(x):
return lambda: x
funcs = []
for x in [1,2,3]:
funcs.append(makeFunc(x))
for f in funcs:
print f()
# output:
1
2
3
You can also fix the scoping inside the lambda expression
lambda bound_x=x: bound_x
However in general this is not good practice as you have changed the signature of your function.
Kaggle
kaggle.com › code › mehmetblnnn › lambda-for-and-while-loops
lambda - for and while loops
Checking your browser before accessing www.kaggle.com · Click here if you are not automatically redirected after 5 seconds