No, C has no support for lambda expressions.

If you're willing to use C++, Boost has a library that emulates lambdas. Also, C++0x will have built-in support for lambda expressions.

There wasn't a huge demand for lambda expression support in C at the time, so the language didn't support it.

Answer from In silico on Stack Overflow
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Microsoft Learn
learn.microsoft.com › en-us › dotnet › csharp › language-reference › operators › lambda-expressions
Lambda expressions - Lambda expressions and anonymous functions - C# reference | Microsoft Learn
The compiler can infer the type of the input parameter, or you can specify it explicitly. This particular lambda expression counts those integers (n) which when divided by two have a remainder of 1. The following example produces a sequence that contains all elements in the numbers array that precede the 9, because that's the first number in the sequence that doesn't meet the condition:
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GeeksforGeeks
geeksforgeeks.org › c++ › lambda-expression-in-c
Lambda Expression in C++ - GeeksforGeeks
Return Type: Generally, the return-type in lambda expressions is evaluated by the compiler itself and we don’t need to specify it explicitly. However, in some complex cases e.g. conditional statements, the compiler can’t determine the return type and explicit specification is required.
Published: April 26, 2026
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Does C use lambda expressions? - Stack Overflow
Bring the best of human thought and AI automation together at your work. Explore Stack Internal ... Save this question. Show activity on this post. ... Save this answer. ... Show activity on this post. No, C has no support for lambda expressions. More on stackoverflow.com
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Lambda Expression
I am still trying to wrap my brain around the lambda expression in C#. I have the following code: string _result = “”; foreach (char c in inputString) { if (c == 122) _result += “a”; else _result += Convert.ToChar(c+1); } return _result; I understand this code, and can follow the logic. More on community.spiceworks.com
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June 1, 2018
[SOLVED] Conditional statement with a Lambda function variable
Hi, I am trying to create/use Lambdas inside of my rules to avoid repeating code over and over, I am having issues with a simple “If” statement when using a Lambda defined variable that is a string. I did seach around the forum and with google but could not find an answer. More on community.openhab.org
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August 11, 2019
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cppreference.com
en.cppreference.com › cpp › language › lambda
Lambda expressions (since C++11) - cppreference.com
has const non-volatile integral or enumeration type and has been initialized with a constant expression, or ... The current object (*this) can be implicitly captured if either capture default is present. If implicitly captured, it is always captured by reference, even if the capture default is =. The implicit capture of *this when the capture default is = is deprecated.(since C++20) Only lambda expressions satisfying any of the following conditions may have a capture-default or capture without initializers:
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Joshdata
joshdata.me › lambda-expressions.html
Lambda Expressions: A Guide
The add_one examples above used ... x + 1 in C#, Python, etc. No braces are used in those languages when the body is an expression: ... The max examples above used statement blocks as lambda function bodies, and when statements are used these languages require that they be surrounded in braces: ... This last example could be turned into an expression-bodied lambda by using the ternary operator condition ...
Find elsewhere
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openHAB Community
community.openhab.org › setup, configuration and use › scripts & rules
[SOLVED] Conditional statement with a Lambda function variable - Scripts & Rules - openHAB Community
August 11, 2019 - Hi, I am trying to create/use Lambdas inside of my rules to avoid repeating code over and over, I am having issues with a simple “If” statement when using a Lambda defined variable that is a string. I did seach around th…
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Medium
medium.com › @weidagang › modern-c-lambda-expressions-63fc0c2b8186
Modern C++: Lambda Expressions. This blog post is part of the series… | by Dagang Wei | Medium
June 22, 2024 - Flexibility: They can be passed around as arguments to functions or stored in variables. Conciseness: They eliminate the need to write separate, named functions for simple tasks. Think of a lambda expression as a self-contained function that you can create on the fly.
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Dotnetfunda
dotnetfunda.com › articles › show › 3191 › conditional-statements-inside-lambda-in-conjunction-with-string-interp
Conditional Statement(s) Inside Lambda in conjunction with String Interpolation of C# 6.0 - DotNetFunda.com
December 3, 2015 - Conditional Statement(s) Inside Lambda in conjunction with String Interpolation of C# 6.0 In this article, we will look at handling conditional statement(s) inside LINQ lambda expression in conjunction with string interpolation of C# 6.0. We will
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Reddit
reddit.com › r/csharp › why no lambda-expressions on if-statements?
r/csharp on Reddit: Why no lambda-expressions on if-statements?
November 4, 2020 -

Is there any real reason why we cant use lambda-expressions in if-else-statements?

I've seen issues/discussions on github but the main argument made there was that Lambda-expressions are bad because there are ways to archieve the same goals...

Like, this:

if(IsTrue) => DoSomething() else => DoSomeOtherThing();

Is "bad".

But then situations like these exist:

private bool DoSomething() => true

Or

public bool MyProperty => MyField

And those are somehow perfectly fine? Why is it forbidden in an if-statement but permitted in literally ANY OTHER situation?

How is it that switch-statements, which are basically nested if-statements, can work with lambda-expressions, but the most BASIC evaluation process CANT?

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Gcher
gcher.com › posts › lambda expressions in c
Lambda expressions in C | Guillaume Chereau Website
January 13, 2016 - Since the statement expression scope does not leak to the rest of the function, we can use any name for the callback, so we are going to use _. We can also put the code into a macro so that we do not have to repeat the name of the callback (as required by the statement expression). And the final result is: #define LAMBDA(c_) ({ c_ _;}) int main() { func(4, LAMBDA(void _(int v) { printf("%d\n", v); })); }
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Codecademy
codecademy.com › learn › learn-advanced-c-plus-plus › modules › lambda-expressions-in-cpp › cheatsheet
Learn Advanced C++: Lambda Expressions in C++ Cheatsheet | Codecademy
C++ lambda expressions provide a way to define anonymous functions. They consist of a capture clause, an optional parameter list, an optional return type, and a function body. This structure allows you to create succinct and powerful function ...
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Cprogramming.com
cprogramming.com › c++11 › c++11-lambda-closures.html
C++11 - Lambda Closures, the Definitive Guide - Cprogramming.com
How to begin Get the book · C tutorial C++ tutorial Game programming Graphics programming Algorithms More tutorials
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Embarcadero
blogs.embarcadero.com › the-advanced-guide-to-lambda-expression-in-c-software
The Advanced Guide To Lambda Expression In C++ Software – Embarcadero RAD Studio, Delphi, & C++Builder Blogs
September 25, 2022 - The syntax for a lambda expression consists of specific punctuation with = [ ] ( ) { ... } series. ... Datatype is its type like int, float, class, etc.
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Hackaday
hackaday.com › 2019 › 09 › 11 › lambdas-for-c-sort-of
Lambdas For C — Sort Of | Hackaday
November 2, 2023 - However, in C you have to define a function by name and pass a pointer — not a huge problem, but it can get messy if you have a lot of callback functions that you use only one time. It’s just hard to think up that many disposable function names. However, if you use gcc, there are some nonstandard C features you can use to get most of what you want out of lambda expressions...
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Reddit
reddit.com › r/c_programming › why does c not have lambdas/anonymous function expressions?
r/C_Programming on Reddit: Why does C not have lambdas/anonymous function expressions?
August 7, 2022 -

It would not seem to hard to implement to allow a programmer to use a construct similar to:

int (*add)(int, int) = (int(int x, int y)){return x+y;};

This would simplify code that requires callback functions such as qsort or bsearch or various UI libraries that use callbacks to define, for example, a buttons behavior when pressed. Is there any specific reason they elected not to support this, and require us to define named static functions instead?

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There are two basic ways to implement closures: A custom calling convention: Callers are aware they're calling a closure and so pass the closure context to the callee, perhaps as a hidden argument. Closures are nearly always implemented this way, including in C++. For C, as a lingua franca platforms would need to define this calling convention / ABI so that different implementers could all each others closures just as they can call each others functions. Since this doesn't exist, closures in language implementations using this approach are incompatible with C interop (ex. can't turn a C++ closure into a function pointer). Build a trampoline by allocating a little bit of executable memory, essentially like using a small JIT compiler. Callers do not need to be aware they're calling a closure, and a plain C calling convention is sufficient. GNU C closures are implemented this way, as are CPython's ctypes callbacks. However, frequently allocating executable memory requires significant trade-offs in performance or security. It may not even be possible on some platforms. This is also an implicit allocation — which is not in the spirit of C — and someone has to manage its lifetime. (GNU C manages it by using an automatic allocation.) Unless you're willing to make the trade-offs in the second approach — which is available to you if you use GCC — neither fits C well.
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Why are people obsessed with making C like python or whatever language they learned first? It's like asking why my bicycle only has two wheels, when your red wagon has four.
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Medium
medium.com › @staytechrich › cpp-033-c-lambda-expressions-2e5dadd3d459
cpp_033: C++ Lambda Expressions. Lambda expressions, introduced in… | by CodeAddict | Medium
May 27, 2025 - Lambda expressions, introduced in C++11, are a powerful feature that allows you to define anonymous functions inline. They are particularly useful for writing concise, localized function-like behavior, often used with algorithms, callbacks, ...