Lambdas are typically used when you're passing a callback function as a parameter to another object or method. Technically, functions in Java are not objects, so a "lambda function" actually gives you an object that implements an interface. There are other ways to do this, but lambdas are very concise and keep the code of the callback "inline" at the point where you're using it. Consider, for instance, the Swing JButton class. To make the button actually do something when clicked, you call addActionListener which expects as its parameter an implementation of the ActionListener interface. Say you want to print the string "Hello world!" when the button is clicked. You could write a whole separate HelloWorldActionListener class that implements ActionListener. Or you could write it as an inline anonymous class: button.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { System.out.println("Hello world!"); } }); A lambda function lets you do the same thing much more concisely: button.addActionListener(e -> System.out.println("Hello world!")); Answer from teraflop on reddit.com
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W3Schools
w3schools.com › java › java_lambda.asp
Java Lambda Expressions
A lambda expression can be stored in a variable. The variable's type must be an interface with exactly one method (a functional interface). The lambda must match that method's parameters and return type. Java includes many built-in functional interfaces, such as Consumer (from the java.util package) used with lists.
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GeeksforGeeks
geeksforgeeks.org › java › lambda-expressions-java-8
Java Lambda Expressions - GeeksforGeeks
Java lambda expressions, introduced in Java 8, allow developers to write concise, functional-style code by representing anonymous functions.
Published   2 weeks ago
Discussions

Can someone explain lambdas?
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November 14, 2023
Is using Lambda expressions whenever possible in java good practice? - Software Engineering Stack Exchange
I have recently mastered the Lambda expression that was introduced in java 8. I find that whenever I am using a functional interface, I tend to always use a Lambda expression instead of creating a ... More on softwareengineering.stackexchange.com
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What’s the use of lambda expressions?
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Are lambda expressions used much by professional coders ?
Please ensure that: Your code is properly formatted as code block - see the sidebar (About on mobile) for instructions You include any and all error messages in full You ask clear questions You demonstrate effort in solving your question/problem - plain posting your assignments is forbidden (and such posts will be removed) as is asking for or giving solutions. Trying to solve problems on your own is a very important skill. Also, see Learn to help yourself in the sidebar If any of the above points is not met, your post can and will be removed without further warning. Code is to be formatted as code block (old reddit: empty line before the code, each code line indented by 4 spaces, new reddit: https://i.imgur.com/EJ7tqek.png ) or linked via an external code hoster, like pastebin.com, github gist, github, bitbucket, gitlab, etc. Please, do not use triple backticks (```) as they will only render properly on new reddit, not on old reddit. Code blocks look like this: public class HelloWorld { public static void main(String[] args) { System.out.println("Hello World!"); } } You do not need to repost unless your post has been removed by a moderator. Just use the edit function of reddit to make sure your post complies with the above. If your post has remained in violation of these rules for a prolonged period of time (at least an hour), a moderator may remove it at their discretion. In this case, they will comment with an explanation on why it has been removed, and you will be required to resubmit the entire post following the proper procedures. To potential helpers Please, do not help if any of the above points are not met, rather report the post. We are trying to improve the quality of posts here. In helping people who can't be bothered to comply with the above points, you are doing the community a disservice. I am a bot, and this action was performed automatically. Please contact the moderators of this subreddit if you have any questions or concerns. More on reddit.com
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Oracle
docs.oracle.com › javase › tutorial › java › javaOO › lambdaexpressions.html
Lambda Expressions (The Java™ Tutorials > Learning the Java Language > Classes and Objects)
However, when the Java runtime invokes the method printPersonsWithPredicate, it's expecting a data type of Predicate<Person>, so the lambda expression is of this type. The data type that these methods expect is called the target type. To determine the type of a lambda expression, the Java compiler ...
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Reddit
reddit.com › r/learnprogramming › can someone explain lambdas?
r/learnprogramming on Reddit: Can someone explain lambdas?
November 14, 2023 -

So I’m reading a book on Java, and it’s talking about lambdas. The syntax seems simple enough, but the author hasn’t described why you would use them over a regular function. They’re being used in the context of functions that don’t have bodies (abstracts, I think?), but I don’t understand why I would use those either.

Top answer
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Lambdas are typically used when you're passing a callback function as a parameter to another object or method. Technically, functions in Java are not objects, so a "lambda function" actually gives you an object that implements an interface. There are other ways to do this, but lambdas are very concise and keep the code of the callback "inline" at the point where you're using it. Consider, for instance, the Swing JButton class. To make the button actually do something when clicked, you call addActionListener which expects as its parameter an implementation of the ActionListener interface. Say you want to print the string "Hello world!" when the button is clicked. You could write a whole separate HelloWorldActionListener class that implements ActionListener. Or you could write it as an inline anonymous class: button.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { System.out.println("Hello world!"); } }); A lambda function lets you do the same thing much more concisely: button.addActionListener(e -> System.out.println("Hello world!"));
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Lambdas are basically anonymous, ad-hoc functions which are treated as first-class variables and can be passed around like any other object. They allow you to inject behavior as a dependency/parameter. They are very useful for cutting down on boilerplate. For example, let's say you have the following boilerplate in C#: StartTimer(); result = DoSomething(); StopTimer(); LogResultAndTime(result); StartTimer(); result = DoSomethingElse(); StopTimer(); LogResultAndTime(result); //ad nauseum Creating a regular method like so: void BoilerplateCode(int result) { StartTimer(); //What do you put here? StopTimer(); LogResultAndTime(result); //result was already calculated before it was passed in, so the result was not properly timed! } Will not work. However, if you use a lambda, you can make it work: void Boilerplate(Func lambda) { StartTimer(); var result = lambda(); //Invoke the lambda on behalf of the caller so that we can time the function that was passed in. StopTimer(); LogResultAndTime(result); } //Usage example: Boilerplate(() => DoSomething()/*This does not get executed until the lambda is invoked*/); Boilerplate(() => DoSomethingElse()); Boilerplate(() => DoSomethingOther()); // ad nauseum As you can see, using a lambda allows me to only define my boilerplate code once, instead of needing to repeat it each time I want to use it. This allows me to easily make an enhancement, such as adding exception handling: void Boilerplate(Func lambda) { try { StartTimer(); var result = lambda(); //Invoke the lambda on behalf of the caller so that we can time the function that was passed in. StopTimer(); LogResultAndTime(result); } catch (Exception ex) { LogExceptionAndTime(ex); } } And all usages of the boilerplate get the updated/enhanced behavior immediately without the need for me to hunt down every instance of the boilerplate and update them by hand. Lambdas can also capture contextual data from the local scope, which allows your boilerplate to ignore implementation details about your lambda, like parameters and dependencies. var myParam = CalculateExpensiveDependency(); Boilerplate(() => DoSomething(myParam)); Boilerplate(() => DoSomethingElse(myParam)); Because we are using lambdas, Boilerplate() doesn't need to know anything about the parameters which DoSomething() or DoSomethingElse() requires. This reduces coupling, and makes your code more resusable, more resilient and more maintainable
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Medium
devcookies.medium.com › a-complete-guide-to-lambda-expressions-in-java-0aea2e1cea42
A Complete Guide to Lambda Expressions in Java
December 3, 2024 - Lambda expressions were introduced in Java 8 to enable functional programming and simplify the verbosity of anonymous classes. They allow you to write concise, functional-style code that is both readable and expressive.
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Dev.java
dev.java › learn › lambdas
Lambda Expressions - Dev.java
Discovering the most useful functional interfaces of the JDK. ... Understanding Method References. ... Using Default and Static Methods to Combine and Create Lambdas. ... Creating and Combining Comparators Using Lambda Expressions.
Find elsewhere
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Baeldung
baeldung.com › home › java › lambda expressions and functional interfaces: tips and best practices
Lambda Expressions and Functional Interfaces: Tips and Best Practices | Baeldung
December 16, 2023 - But in the case of mutable object variables, a state could be changed inside lambda expressions. ... This code is legal, as total variable remains “effectively final,” but will the object it references have the same state after execution of the lambda? No! Keep this example as a reminder to avoid code that can cause unexpected mutations. In this article, we explored some of the best practices and pitfalls in Java 8’s lambda expressions and functional interfaces.
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CodingNomads
codingnomads.com › java-lambda-expressions
Java Lambda Expressions
Lambda expressions provide a clear and concise way to represent a one-method interface (aka Functional Interface) using an expression. Lambda expressions also improve the Collection libraries, making it easier to iterate through, filter, and ...
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TheServerSide
theserverside.com › blog › Coffee-Talk-Java-News-Stories-and-Opinions › Benefits-of-lambda-expressions-in-Java-makes-the-move-to-a-newer-JDK-worthwhile
Benefits of lambda expressions in Java make the move to a newer JDK worthwhile
Variables defined outside of an inner class do not employ the traditional rules pertaining to block scope within a Java class. As a result, it is easy to fall prey to a bug-inducing anti-pattern known as variable shadowing. This can create bugs that are very difficult to troubleshoot. With lambda expressions, the goal is to minimize as many of the drawbacks to using a single class or anonymous inner class when we implement a functional interface.
Top answer
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Syntax is:

arguments -> body

where arguments can be either

  • ()

  • a single variable if the type of that variable can be inferred from the context

  • a sequence of variables, with or without types (or since Java 11, with var), in parentheses.
    Examples: (x), (x, y), (int x, int y), (var x, var y) (Java 11+).
    The following are invalid: (int x, y), (x, var y), (var x, int y)

and body can be either an expression or a {...} block with statements. The expression (other than a method or constructor call) is simply returned, i.e. () -> 2 is equivalent to () -> {return 2;}


In case of lambda expressions like () -> f() (the body is a method or constructor call expression):

  • if f() returns void, they are equivalent to () -> { f(); }

  • otherwise, they are equivalent to either () -> { f(); } or () -> { return f(); }). The compiler infers it from the calling context, but usually it will prefer the latter.

Therefore, if you have two methods: void handle(Supplier<T>) and void handle(Runnable), then:

  • handle(() -> { return f(); }) and handle(() -> x) will call the first one,

  • handle(() -> { f(); } will call the second one, and

  • handle(() -> f()):

    • if f() returns void or a type that is not convertible to T, then it will call the second one

    • if f() returns a type that is convertible to T, then it will call the first one


The compiler tries to match the type of the lambda to the context. I don't know the exact rules, but the answer to:

What would happen if there were two SwingUtilities.invokeLater methods which differ only in parameter list?

is: it depends on what would be those parameter lists. If the other invokeLater had also exactly one parameter and that parameter would be of type that is also an interface with one method of type void*(), well, then it would complain that it cannot figure out which method you mean.

Why are they written as they are? Well, I think it's because syntax in C# and Scala is almost the same (they use => rather than ->).

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13

The syntax is

(parameter_list_here) -> { stuff_to_do; }

The curly braces can be omitted if it's a single expression. The regular parentheses around the parameter list can be omitted if it's a single parameter.

The syntax only works for all functional interfaces. The @FunctionalInterface annotation tells the compiler that you intend to write such an interface and gives a compile error if you do not meet the requirement(s) - for example it must only have 1 overrideable method.

@FunctionalInterface
interface TestInterface {
    void dostuff();
}

Runnable is also declared like that. Other interfaces are not, and they cannot be used with lambda functions.

Now that we've made a new functional interface with a method that takes no parameters, how about we test the question you had about "collision" in the signatures?

public class Main {
    private void test(Runnable r) {

    }
    private void test(TestInterface ti) {

    }
    public static void main(String[] args) { 
        test(() -> { System.out.println("test");})
    }

    @FunctionalInterface
    interface TestInterface {
        void dostuff();
    }
}

Result: compile error: ambigouous call to method test.

You see, the compiler/VM(if done runtime) finds the appropriate methods and their parameter list and sees if the parameter is a functional interface and if it is it creates an anonymous implementation of that interface. Technically (in byte code) it's different from an anonymous class, but otherwise identical (you won't see Main$1.class files).

Your example code (courtesy of Netbeans) can also be replaced with

SwingUtilities.invokeLater(MainAppJFrame::new);

Btw. :)

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Programiz
programiz.com › java-programming › lambda-expression
Java Lambda Expressions (With Examples)
Here, the method does not have any parameters. Hence, the left side of the operator includes an empty parameter. The right side is the lambda body that specifies the action of the lambda expression. In this case, it returns the value 3.1415. In Java, the lambda body is of two types.
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DigitalOcean
digitalocean.com › community › tutorials › how-to-use-lambdas-in-java
How to Use Lambdas in Java | DigitalOcean
February 28, 2024 - The arrow ->. It is used to link the parameters and the body of the lambda expression. A body that contains the code to be executed. If there are arguments they are used in the body to perform operations with them. Info: To follow along with the example code in this tutorial, open the Java Shell tool on your local system by running the jshell command.
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Medium
abu-talha.medium.com › lambda-expressions-in-java-a-concise-guide-with-examples-47c7ade952fb
Lambda Expressions in Java: A Concise Guide with Examples | by Abu Talha | Medium
October 8, 2023 - A lambda expression is a concise way to represent an anonymous function (a function without a name) in Java.
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Oracle
oracle.com › java › technical details
Java 8: Lambdas, Part 1
Syntax. A lambda in Java essentially consists of three parts: a parenthesized set of parameters, an arrow, and then a body, which can either be a single expression or a block of Java code. In the case of the example shown in Listing 2, run takes no parameters and returns void, so there are ...
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Hevo
hevodata.com › home › learn › data strategy
What are Java Lambda Expressions? Syntax, Rules & Examples
December 19, 2024 - In simpler terms, a Lambda Expression is an unnamed anonymous function. This anonymous function is passed as an argument to another method or stored in a variable. In Java 8, Lambda Expressions were introduced.
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Jenkov
jenkov.com › tutorials › java › lambda-expressions.html
Java Lambda Expressions
Java lambda expressions are new in Java 8. Java lambda expressions are Java's first step into functional programming. A Java lambda expression is thus a function which can be created without belonging to any class.
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Quora
quora.com › Can-we-call-the-Lambda-expressions-in-Java-anonymous-functions
Can we call the Lambda expressions in Java, anonymous functions? - Quora
Answer (1 of 3): Oooofff…lots of misinformation here so I’m afraid I’m going to have to step in. Let’s fix with the question itself, which messes up concepts and punctuation. Q: Can we call lambdas in Java “anonymous functions”? A: Think of lambdas in Java as being inline functions (functions ...